Complexation and Precipitation Reactions and Titrations Flashcards
(46 cards)
What is a ligand?
an ion or a molecule that forms a covalent bond with a cation or a neutral metal atom by donating a pair of electrons, which are then shared by the two
EX: water, ammonia, and halide ions
The number of covalent bonds that a cation tends to form
coordination number
Define chelate.
produced when a metal ion coordinates with two or more donor groups of a single ligand to form a five- or six-membered heterocyclic ring
Differentiate unidentate and bidentate
unidentate - ligand that has a single donor group
bidentate - ligand with two donor group
***tri-, tetra-, penta-
Explain the selectivity of ligand for one metal ion
The higher the formation constant of the metal-ligand complex, the better the selectivity of the ligand for the metal relative to similar complexes formed with other metals
Based on reactions that yield ionic compounds of limited solubility
Precipitation titrations
Precipitation titration is considered complete when
____
Ksp < 10^-8.
Factors decreasing solubility
- Common ion effect
- Organic solvent
Factors increasing solubility
- Complex formation
- Electrolyte effect
- Acid
- Temperature
most widely used and important precipitating reagent
AgNO3
Parameters for a feasible argentometric analysis (4)
- insoluble precipitate
- fast and rapid
- minimal co-precipitation
- visible equivalence point
The titration curve for Argentometric titration usually consists of a plot of _____
pAg versus the volume of silver nitrated added
Explain the effect of concentration of AgNO3 (precipitating agent) on titration curve
More concentrated solution has increased sharpness in the equivalence point
Explain the effect of reaction completeness (Ksp) on argentometric titration
The smaller Ksp (less soluble) give sharper breaks at the end point (more feasible titration)
In argentometric titration with mixture of analyte, the first to be titrated will be ___
the one with lower Ksp
(I < Br < Cl < IO3 < BrO3)
Describe Mohr Method
1. Indicator
2. Color change
3. Medium
4. Titrant
5. Used to determine
- Indicator - chromate ion
- yellow sol’n (CrO4 2-) to brick red precipitate (Ag2CrO4)
- Neutral or faintly alkaline
- AgNO3
- Cl and Br
Requirements for Mohr Method (5)
- The reverse titration of silver ion with chloride ion using chromate as indicator is not feasible
- Not successful for titration of iodide and thiocyanate
- No cations that give insoluble chromate (eg. barium)
- neutral or faintly alkaline medium only
- right concentration of indicator
What will happen to chromate in Mohr Method if done in acidic or alkaline medium?
Acid: decreased chromate concentration
Base: silver will precipitate as its oxide
What will happen if not right amount of indicator was used in Mohr method?
Too little: higher Ag concentration at equivalence point before precipitation of AG2CrO4 occurs
Too much: color change is hard to notice due to intense yellow color
Describe Volhard Method
1. Indicator
2. Color change
3. Medium
4. Titrant
5. Use to determine
- Indicator - ferric nitrate/ferric ammonium alum
- Red solution
- nitric acid solution
- standard potassium/ammonium thiocyanate
- Cl, Br, I (indirect)
In Volhard method, when the excess of silver has reacted, the thiocyanate may react with the silver chloride, since ___
silver thiocyanate is the less soluble until the ratio [Cl−] / [SCN−] in the solution is 170.
How to prevent thiocyanate from reacting with silver chloride in Volhard method? (3)
- filter the silver chloride before back titration
- After the addition of the silver nitrate, the suspension is boiled for about 3 minutes, cooled and then titrated immediately
- using nitrobenzene to coat silver chloride
Describe Fajans Method
1. Indicator
2. Color change
3. Titrant
4. Use to determine
- acid dyes
fluorescein, dichlorofluorescein, eosin - Color change
fluorescein/dichlorofluorescein = greenish yellow to pink
eosin = yellowish red to reddish-violet - AgNO3
- Cl (except eosin), Br, I, and SCN
How adsorption indicator works in Fajans method?
Before equivalence point, the excess lattice ion is negative (Cl-) and hence the colloid is negatively charged.
After the equivalence point, the excess lattice ion is positive (Ag+) and hence, the colloid is positively charged which makes the negatively charged indicator to bind and change color