Complex Numbers Flashcards

1
Q

i^2 =

A

-1

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2
Q

All complex numbers are in the form…

A

A + Bi
A is real
B is imaginary

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3
Q

Solve:
X^2 + 49 = 0

A

X^2 = -49
X = root - 49
X = -7i

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4
Q

Z1 = 3 + 2i
Z2 = 4 - 3i

What’s z1 + z2

What’s z1 - z2

A

7 - i
-1 + 5i

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5
Q

5(3i +2i) =

A

15 + 10i

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6
Q

I^3 =

A

I(i)^2
I(-1) = -i

Split the i’s up into multiple powers of 2,
Replace i squared with a -1

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7
Q

What is a complex conjugate symbol

A

Z*

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8
Q

What is the complex conjugate of Z = -2 + 3i

A

Z* = -2 - 3i

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9
Q

Why are complex conjugates useful

A

When u add them together u get a real number
When u multiply them together u get a real number

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10
Q

How to divide complex numbers

A

Multiply the denominator by its complex conjugate to get a real number
Simplify

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11
Q

What is an argand diagram

A

Y - axis = complex number
X - axis = real number

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12
Q

How to represent Z = 3 + 2i on an argand diagram

A

Much like a vector
3 across and 2 up

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13
Q

The complex conjugate is a ________ in the x-axis

A

Reflection

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14
Q

What does the modulus mean

A

The length of the line

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15
Q

How to work out the modulus Z =A + Bi

A

|z| = root( a ^2 + b^2)

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16
Q

What is the argument

A

The angle of the x axis
In radians

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17
Q

How to work out the argument

A

Draw a sketch
Look at the acute angle of alpha
Tan-1(y/x)
Use the positive values

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18
Q

Arg of Z = -3 + 4i

A

Tan-1(4/3)
= 0.927
-( pi - 0.927) = - 2.215

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19
Q

How to generally solve complex numbers equations

A

Group the real numbers and imaginary parts together
Then equate the real numbers with real numbers
Do the same for the imaginary numbers
Solve both equations simultaneously

20
Q

( a + b )(5 -i) = 10a + b +1 - (2a+1)i

A

5a - ai + 5b -bi = (10a + b + 1) - (2a +1)i
(5a + 5b) - (a + b)i = (10a +b +1) - (2a + 1)i
5a + 5b = 10a + b + 1
-A - b = -2a -1
Solve simultaneously

21
Q

How to find the square root of -21 - 20i

A

Let the answer = a + bi
(A + bi)^2 = -21 -20i
A^2 + 2abi - b^2 = -21 -20i
Equate the imaginary numbers with the ir numbers
So the same with the real ones
Solve simultaneously for a and b
Put back into a + bi

22
Q

How to find the roots of a polynomial with no real roots

A

Use the quadratic formula to find one root
The second root is the complex conjugate

23
Q

Find the quadratic equation that has 5 - 3i as one of its roots

A

A = 5 - 3i
B = 5 + 3i
Times them together to get your quadratic

24
Q

What did u get in an cubic equation

A

1 real root
Complex conjugate pair

25
Find all the roots of the equation X^3 -4x^2 + x + 26 = 0
Use factor theorem to find the real root X +2 is a factor Divide the cubic by the factor Find the complex conjugate by using the quadratic formula
26
What would the complex roots of a quadratic equation look like
2 real roots and a complex conjugate pair Or 2 complete conjugate pairs
27
If z = x +iy then the complex conjugate z* = x -iy is a _______ _____ on an argand diagram
Reflection in the x- axis
28
How to find the complex number that represents a reflection of z in the real axis
Find the complex conjugate
29
Z=x + iy What is x in Cartesian form
X = Rcos(theta) R = modulus Theta = argument
30
Z=x + iy What is y in Cartesian form
Y = Rsin(theta)
31
What is the complete Cartesian form of a complex number
Z = r( cos(theta) + isin(theta) )
32
|z1 x z2| = |z1||z2| =
R1 x r2
33
Arg(z1 x z2) = arg(z1) + arg(z2)
= theta1 + theta2
34
What are arg laws similar to
Log laws
35
|z1/z2| = |z1| / |z2| =
R1 / r2
36
Arg|z1/z2| = arg(z1) - arg(z2) =
Theta1 - theta2
37
Circle centre z1 radius r equation
| z - z1|
38
What is the centre and radius of | 4 +5i -z|
|-1( Z - 4 - 5i)| |-1||z - 4 - 5i| |z - (4 + 5i )| Centre 4,5
39
How to find the Cartesian equation
Let z be x + iy Z1 = a + bi |x + iy - (a +bi)| |(x-a) + i(y-b)|=r Square
40
The locus of a point which is equidistant from two fixed points A and B in the complex plane is …
The perpendicular bisector of A and B
41
What’s the general formula for the perpendicular bisector
|z - z1| = |z - z2|
42
What is the equation for a half line
Arg( z - z1)
43
<= means what type of line
Solid
44
Arg(z - z1/ z - z2) = theta
Arg(z - z1) - arg(z - z2) Let Arg(z - z1) = alpha Let Arg(z - z2) = beta Alpha -beta = theta Start at z1 move anti-clockwise to z2 On the major arc if theta is acute and the minor arc if theta is obtuse
45
Arg(z - z1) - arg(z - z2) Let Arg(z - z1) = alpha Let Arg(z - z2) = beta Alpha -beta = theta Start at z1 move anti-clockwise to z2 On the major arc if theta is acute and the minor arc if theta is obtuse