Completing the Square Flashcards
Problem 1) 2x^2 + 142 = -36x
Step 1?
Divide by Coefficient of x^2
2x^2 + 142 = -36x
————— = ——–
2 2
x^2 + 71 = -18x
Step 2?
Move “x” Term to the Left
x^2 + 71 = -18x
+ 18x = + 18x
x^2 + 18x + 71 = 0
Step 3?
Move Constant Term (“c”) to the Right
x^2 + 18x + 71 = 0
- 71 = - 71
x^2 + 18x = -71
Step 4?
Find the Constant to Add: (b/2)^2
(b/2)^2 ➜ (18/2)^2 ➜9^2 ➜ 81
Step 5?
Add the Constant (81 in this case) to Both Sides
x^2 + 18x + 81 = -71 +81
x^2 + 18x + 81 = 10 ➜ Combine Constants
(x + 9) (x + 9) = 10 ➜ Factor Trinomial
(x + 9)^2 = 10 ➜ Write as Square Binomial
Step 6?
Square Root Both Sides:
√(x + 9)^2 = √10
x + 9 = ± √10
Step 7?
Solve for X:
x + 9 = ± √10
- 9 = - 9
x = -9 ± √10
Final Answer?
x = -9 ± √10
Problem 2) x^2 - 12x + 21 = 0
Step 1?
Move Constant Term to the Right
x^2 - 12x + 21 = 0
-21 = -21
x^2 - 12x = -21
Step 2?
Find the Constant to add: (b/2)^2
(b/2)^2 ➜ (-12/2)^2 ➜ (-6)^2 ➜ 36
Step 3?
Add Constant (Which is 36 in this case) to BOTH Sides
x^2 - 12x + 36 = -21 + 36
x^2 - 12x + 36 = 15 ➜ Combine Constants
(x - 6) (x - 6) = 15 ➜ Factor Trinomial
(x -6)^2 = 15 ➜ Write as Square Binomial
Step 4?
Square Root Both Sides
√(x - 6)^2 = √15
x - 6 = ± √15
Step 5?
Solve for X
x - 6 = ± √15
+ 6 = + 6
x = 6 ± √15