Circuit Anlysis & Linear Systems Flashcards
So were are trying to find how much Capacitive Reactive Power (Q) is needed to correct the power factor lag.
First convert complex power from polar to rectangular
Find the pf correction pf:
cos(theta2) = 0.97
arccos0.97 = theta2
theta2 = 14.07 degrees
The new reactive power Qdesired = Ptan(theta2)
Qneeded = Qoriginal - Qdesired
The rms current is calculated from the peak current by using this equation.
The phase angle is referenced to the voltage waveform.
The current reaches its peak 90 degrees before the voltage. Leading currents have a positive phase shift.
What is most nearly the current immediately after the switch is closed?
(A) 0.2 A
(B) 0.7 A
(C) 1 A
(D) 3 A
Find the Forcing Frequency
2πf = 2π(60 Hz) = 377 rad/s
Find the imedances of each individual element
Inductor ZL = j(omega)L = j(377 rad/s)(133 x 10-3 H) = j50 ohms
Resistor ZR = R = 100 ohms
Find the equivalent resistance and equivalent voltage.
Req = 21 ohms
Veq = 70 V + ( -50 V ) = 20 V
Ohm’s law to determine the current through the circuit.
The voltage across any individual resister is found from ohms law.
V = IR = (0.952 A) (10 ohms) = 9.52 V (9.5 V)
Pg. 361 of handbook. Use formula.
Make sure units are correct when plugging in information.
The voltage across and current through the 5 ohm resistor in the center leg are most nearly….
(A) 2 V and 1 A
(B) 2 V and 3 A
(C) 5 V and 1 A
(D) 5 V and 20 A
Read the entire problem!
V = IR
IBE = ( VBE/R) = 60 mA
Since this is a DC Circuit, the capacitor blocks current flow. No current will flow through it.
The only voltage source in the loop containing the 5, 10, and 20 ohm resistors is the 100 V battery.
Use Kirchhoffs voltage law for the loop.
B
Use Joules Law
P = I2R
A Thevenin equivalent circuit and its original resistive load are shown. The 1 ohm load resistance is subsequently changed in order to maximize the power transfer.