CIRCLES - alevel maths Flashcards
How do convert from circle equation form: (x-a)^2 +(y-b)^2=r^2
to form: x^2+y^2 +2fx +2gy+c=0
how do you convert back to the original form?
- expand
2. Factorise by completing the square
Complete the square for this equation
x^2 - 4x + y^2 - 6y -3
- First deal with x’s then with y’s.
- half the x term to get G, and put it in a bracket: (x - G)^2
- square the G and minus it outside the bracket: (x-G)^2 -G^2
- Repeat for the y
- Add the two outcomes together
(x-2)^2 + (y-3) - 16
Equation for mid point of a line, when you have two co-ordinates of the line (x1 , y1) & (x2 , y2)
the co-ordinates of the lines mid point will be
x co-ordinate= (x1+x2)/2
y co-ordinate=(y1+y2)/2
gradient of a line equation?
when you have two points on the line
(y2 - y1) / (x2 - x1)
always do the same order of minusing so that you get the correct gradient sign. (you can always check it is correct by looking at the slope!)
What is a perpendicular bisector of a line segment?
A line that passes through the mid point of a line segment and is perpendicular to that segment
What is the gradient of a perpendicular bisector or a line segment?
-1 / (line segment gradient)
The tangent to the circle is _______ to the radius of the circle at the intersection point
the perpendicular bisector to the chord of the circle will pass through the _____ of the circle.
perpendicular
centre
what is a circumcircle?
a circle that passes through the vertices of a triangle
How do the sides of a circumcircle relate to the midpoint of the circle?
The perpendicular bisectors o the sides will pass through the centre of the circle
What will the angle be in a triangle that is in a semi-circle
90 degrees
What is the 3 point rule used for
with 3 points on a circle, you can make 2 chords, whose perpendicular bisectors will intersect at the centre of the circle.
you find the mid-point & gradient of the two chords, meaning you can find the gradient and a point on the bisectors. Use these values to get an equation for each bisector and then find where they intersect.