CIRCLES - alevel maths Flashcards

1
Q

How do convert from circle equation form: (x-a)^2 +(y-b)^2=r^2
to form: x^2+y^2 +2fx +2gy+c=0

how do you convert back to the original form?

A
  1. expand

2. Factorise by completing the square

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2
Q

Complete the square for this equation

x^2 - 4x + y^2 - 6y -3

A
  1. First deal with x’s then with y’s.
  2. half the x term to get G, and put it in a bracket: (x - G)^2
  3. square the G and minus it outside the bracket: (x-G)^2 -G^2
  4. Repeat for the y
  5. Add the two outcomes together

(x-2)^2 + (y-3) - 16

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3
Q

Equation for mid point of a line, when you have two co-ordinates of the line (x1 , y1) & (x2 , y2)

A

the co-ordinates of the lines mid point will be
x co-ordinate= (x1+x2)/2
y co-ordinate=(y1+y2)/2

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4
Q

gradient of a line equation?

when you have two points on the line

A

(y2 - y1) / (x2 - x1)

always do the same order of minusing so that you get the correct gradient sign. (you can always check it is correct by looking at the slope!)

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5
Q

What is a perpendicular bisector of a line segment?

A

A line that passes through the mid point of a line segment and is perpendicular to that segment

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6
Q

What is the gradient of a perpendicular bisector or a line segment?

A

-1 / (line segment gradient)

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7
Q

The tangent to the circle is _______ to the radius of the circle at the intersection point

the perpendicular bisector to the chord of the circle will pass through the _____ of the circle.

A

perpendicular

centre

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8
Q

what is a circumcircle?

A

a circle that passes through the vertices of a triangle

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9
Q

How do the sides of a circumcircle relate to the midpoint of the circle?

A

The perpendicular bisectors o the sides will pass through the centre of the circle

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10
Q

What will the angle be in a triangle that is in a semi-circle

A

90 degrees

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11
Q

What is the 3 point rule used for

A

with 3 points on a circle, you can make 2 chords, whose perpendicular bisectors will intersect at the centre of the circle.

you find the mid-point & gradient of the two chords, meaning you can find the gradient and a point on the bisectors. Use these values to get an equation for each bisector and then find where they intersect.

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