Chromosomes and Replication Flashcards
Why is it important for DNA to be packaged into chromatin?
Chromatin compaction = correlates with expression, and is related to accessibility of transcriptional machinery to the DNA.
DNA compaction level = relevant to DNA recombination and repair.
What is the difference between Heterochromatin and euchromatin?
Heterochromatin = closed, inactive marks on the chromatin.
Euchromatin = open, active marks on the chromatin.
What is the nucleosome?
- 146 bp of DNA wrapped around a histone octamer (2 x H2A, 2 x H2B, 2 x HB, 2 x H4) - linked by an exterior H1.
- Histones = +vely charged (lys and arg rich).
- +vely charged histones bind to -vely charged DNA.
- N-ter histone tails protrude from the octamer.
Explain post-translational histone modifications.
- Modifications occur on the N-ter tails that protrude from the nucleosome, accessible to other chromatin proteins.
- Different histone tail modification = associated with different functions (transcriptional activation, silencing, replication, repair, etc).
- Providing opportunity to alter chromatin structure by chemically altering the histone/providing docking sites for binding partners.
More than 50 sites can be modified, some with more than 1 type of tag.
Acetyl or methyl groups = added to histone tails due to accessibility.
Explain what histone acetylation is and what occurs.
- Acetylation = correlated with gene activity, partly due to reduced positive charge of histones.
- Acetylation (especially for H3 and H4) = neutralises the charge and loosens the chromatin structure.
Explain what histone methylation is.
- does not alter the charge of the histone.
- mono, di, and tri-methylation exist (mostly referring to tri-methylation).
- correlate with either transcriptional activity or inactivity - depending on which histone tail residue is methylated.
Explain the difference between H3K4me, H3K9me, and H3K27me.
- H3K4me – active locus around the promoter.
- H3K9me – inactive locus spread over the gene, constitutive heterochromatin.
- H3K27me – inactive locus spread over the gene, facultative heterochromatin.
What are the three parts of a mitotic chromosome.
- Origins of replication - regions where DNA replication is initiated.
- Centromere - point of attachment of microtubules during mitosis.
- Telomeres - a protective cap on the ends of linear chromosomes (must be maintained/extended after replication).
What are the four phases of the cell cycle?
- Interphase.
- S-phase.
- M phase.
- Interphase.
Explain what occurs in interphase (pt 1).
Single copy of the chromosomes are unfolded and loose, allowing for transcription to take place.
Explain what occurs in S phase.
Copy of the chromatids, packaged up in preparation for mitosis.
Explain what occurs in M phase.
Separation of the two copies of DNA.
Explain what occurs in interphase (pt 2).
chromosomes unpack again.
What is the Origin of Replication (DNA replication)?
Location of a chromosome where DNA replication is initiated.
Eukaryotes have multiple origins of replication on each linear chromosome.
What is the function/feature of the origin of replication?
- AT-rich (easier to separate the two DNA strands).
- Enriched for H4K20me2 (binding site for ORC) = flag for the origin of replication.
Explain what occurs in the initiation of DNA rep in Eukaryotes.
- ORC (Origin binding complex) binds to the origin.
- DNA helicase binds to complete the pre-replicative complex.
- Wait for S-phase to begin (signaled by an activation of s-cdk).
- S-cdk phosphorylates many targets associated with DNA synthesis (deactivates the ORC and activates helicase).
- Helicase separates the AT-rich area.
DNA polymerase is loaded and the replication forks head off in opposite directions.
Explain how replication occurs at the end of the chromosome (for the leading strand).
Leading strand = can be replicated right to the end (from 3’ to 5’).
Explain how replication occurs at the end of the chromosome (lagging strand).
- Lagging strand = last part of the chromosome (where the final RNA primer was placed) cannot be replicated with DNA (exonucleases will remove this single stranded overhang).
- Therefore, after each cell cycle, chromosomes lose 50-100 bp. Normal process in somatic cells of the body, which will typically only divide 50-70 before senescing (ceasing division).
What opposes the loss of bp from the lagging stran?
Telomeres and telomerase.