Chemistry UNIT 1- Amount of Substance Flashcards

1
Q

Define relative atomic mass

A

The weighted average mass of an atom of an element taking into account its naturally occurring isotopes relative to 1/12th the relative atomic mass of an atom of carbon 12

Ar = Average mass of one molecule / 1/12th the mass of one atom of Carbon 12

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2
Q

Define Relative molecular mass

A

The mass of that molecule compared to 1/12th the relative atomic mass of an atom of carbon 12.

Mr = Average mass of one atom of an element / 1/12th the mass of one atom of Carbon 12

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3
Q

Define relative formula mass

A

The mass used for ionic compounds which don’t exist as molecules, still has symbol Mr

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4
Q

What is an entity?

A

General term for a particle (eg. atom) simplest formula unit of an ionic substance.

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5
Q

Define Avogadro’s number.

A

The number of atoms in 12g of carbon 12.

This is 1 mole of carbon 12.

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6
Q

Define the term molar mass.

A

The mass per mole of a substance.

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7
Q

How can we form a solution?

A

When a solute dissolves in a solvent forming a solution.

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8
Q

What does molecular formula show?

A

Shows the actual number of atoms of each element in a molecule.
(eg. C3H6O3)

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9
Q

What does empirical formula show?

A

The smallest whole number ratio of each element in the substance.
(eg. C3H6O3 = CH2O)

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10
Q

what units do we use for solutions?

A

gdm^-3 or moldm^-3

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11
Q

What is the equation for atom economy?

A

Atom economy = mass of desired product / total mass of reactants (or products) x100

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12
Q

What is the ideal gas equation?

A

PV=nRT

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13
Q

What is the equation to work out moles from elements or compounds?

A

Mol = mass / Mr

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14
Q

What is the equation to work out moles from solutions?

A

Mol = VC / 1000

V = cm^3
C = moldm^-3
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15
Q

How do you calculate percentage yield?

A

% yield = Actual mass / Theoretical mass x100

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16
Q

How do you calculate percentage error?

A

% error = Stated error for apparatus / amount being measured x100

17
Q

What is the equation for density?

A

Density = mass / volume.