Chemistry Chapter 7-8 Flashcards
Combination
A+B = AB
Decomposition
AB = A+B
Single Replacement
A+BC = AC+B
Double Replacement
AB+CD = AD+CB
Combustion
Cx + Hy + O2 = CO2 + H2O
Steps of Combustion
Step 1: Put 2 in front of CxHy and distribute
Step 2: Go to H and H2O, balance and distribute
Step 3: Balance C in CO2 and distribute
Step 4: Add up Os on the right and the balance on the left
Step 5: Reduce if everything is reducable
Add Ratio and Balanced
OIL RIG
Oxidation is loss of electrons
Reduction is gain of electrons
Rules of Oxidation Reduction
1: Assign free elements a charge of 0
Ex: Cu or Fe2
Diatomic elements are free elements
2: Assign other charges based on oxidation numbers charges
ex: 2Cu^0 + O2^0 = 2Cu^+2O-2
3: Compare the charges and identify as oxidation or reduction
Oxidation reaction is when
0 goes to positive charge
Loses electrons
ex: 0 to 2+
Reduction reaction is when
0 goes to negative charge
Gains electrons
ex: 0 to 2-
If there is an e- on the left it is
reduction
If there is an e- on the right it is
oxidation
Oxidation always
loses electrons, may also be seen as an addition of oxygen or loss of hydrogen
Reduction always
gains electrons, may also be seen as loss of oxygen or gain of hydrogen
Half Redox reaction
Cu^0 + 2AgNO3 = Cu(NO3)2 + 2Ag
Cu goes from 0 to 2+
Ag goes from 1+ to 0
Half Redox:
Cu^0 = Cu^+2 + 2e-
Oxidation
Ag^+1 + e- = Ag^0
Reduction
What is a mole?
Unit of measurement, amount of a pure substance containing the same number of chemical units (atoms or molecules)
Avagadro’s Number
6.02 x 10^23 particles
1 mole / 6.02 x 10^23 or 6.02 x 10^23 / 1 mole
Moles of an element in a compound
Subscripts are used to write conversion factors for moles of an element
How many atoms of O are in 0.150 mole of C9H8O4?
3.61 x 10^23 atoms of O
How many CO2 molecules are in 0.500 mole of CO2?
3.01 x 10^23 molecules of CO2