Chemistry 101 Flashcards
Identify the compound usually added to water to provide the Mn2+ ions.
MnSO4.2H2O (manganese(II) sulfate) / MnCl2.4H2O (manganese(II) chloride)
What change is observed when concentrated sulphuric acid is added to a stoppered bottle, completely filled with a sample of the water, was shaken with a concentrated solution containing Mn2+ ions and then with a concentrated solution of alkaline potassium iodide (KOH/KI).
A brown solution is formed
Describe how the conical flask was prepared for a titration and then used during a titration to help ensure that an accurate end point was reached.
It was first rinsed with deionised water.
swirl to mix the content of the flask.
Wash down the sides of the flasks with deionised water.
Give one way of ensuring that the level of liquid in the burette was at eye level before taking a reading.
bend (crouch, kneel) until eye at level of liquid
When preparing a solution of Sodium Thiosulfate and Standardising it by Titration against a Solution of Iodine,
what colour changes were observed at the titration stage of the experiment
(i) up to the point when the indicator was added,
(ii) at the end point?
i) Brown fades to pale yellow
ii) Blue-black to colourless
The sodium thiosulfate solution contained 3.1 g Na2S2O3.5H2O per litre. On average, 6.0 cm3 of this solution were required for complete reaction with 200.0 cm3 portions of the iodine solution.
The balanced equation for the titration reaction is:
I2 + 2S2O32– = 2I– + S4O62–
Four moles of S2O32– were required for every one mole of dissolved O2 present originally.
Show by calculation:
(i) the average number of moles of sodium thiosulfate used in a titration,
(ii) the number of moles of O2 that released the I2 detected in each titration,
(iii) the concentration of dissolved oxygen in the water in moles per litre,
(iv) the concentration of dissolved oxygen in the water in p.p.m. (mg l–1).
i) moles= mass/ molar mass
M = 3.1/ 248 = 0.0125 (1/80) M
(6.0 x 0.0125) / 1000 = 0.000075 (7.5 × 10–5, 3/40000) moles thiosulfate.
ii) Thiosulfate : O2 = 4 : 1
0.000075 (7.5 × 10–5, 3/40000) ÷ 4
= 0.00001875 (1.875 × 10–5, 3/160000) moles O2 in 200.0 cm3.
iii) 0.00001875 (1.875 × 10–5, 3/160000) × 5 = 0.00009375 (9.375 × 10–5, 3/32000) moles /l (M) of O2
iv) 0.000009375 (9.375 × 10–5, 3/32000) × 32 = 0.003 g/l
0. 003 × 1000 = 3.0 p.p.m.
A student placed a short strip of freshly‐sanded magnesium ribbon into a test tube containing a few drops of ethanoic acid in approximately 10 cm3 of water and swirled the test tube.
(i) What was observed?
(ii) Write formulae for both products of the reaction that occurred.
i) bubbling (fizzing, effervescence, foaming, gas evolves) / solid (magnesium, Mg) dissolves (disappears) / solution forms / white powder (solid, precipitate) formed.
ii) H2 (hydrogen) and (CH3COO)2Mg (magnesium ethanoate)
Describe a chemical test to show that ethanal can be very easily oxidised.
Add Tollens’ reagent to ethanal. Then heat gently using a water bath. Silver (Ag, mirror, precipitate, solid) is positive test for aldehyde
A student was asked to prepare a small quantity of ethene from ethanol using the reaction shown by the balanced equation below. A suitable catalyst and a heat source were provided.
C2H5OH = C2H4 + H2O
(i) Identify the catalyst and describe its appearance at the beginning of the preparation.
(ii) Explain clearly why a risk of hot glassware shattering, due to rapid cooling, is associated with this preparation.
How can this risk be minimised?
(iii) A student prepared ethene, starting with 2.9 cm3 of ethanol (density 0.8 g cm–3). Calculate the volume of ethene gas produced in 26% yield when measured
at room temperature and pressure.
i) Aluminium oxide. It is a white powder.
ii) Cold water enters hot test-tube (apparatus, glassware). A suck-back can occur. To minimise this risk, loosen stopper before reducing (removing) heat.
iii) Density = mass/volume
0.8= mass/2.9
m=0.80×2.9=2.32g
2.32/ 46 =0.0504 moles ethanol used
0.0504 × 0.26 = 0.013104 actual mol ethene
0.013104 × 24.0 = 0.300 - 0.315 litres ethene
To determine the relative molecular mass (Mr) of compound X, a volatile liquid, a small volume of the pure liquid was vaporised in a suitable container. The atmospheric pressure at the location was obtained using a smart phone barometric sensor.
Explain
(i) why the pressure of the vapour at the end of the heating stage of the experiment was known to be equal to the atmospheric pressure
at your location,
(ii) how the volume of the vapour was measured.
(iii) Describe how the mass of the vapour in the container
at the end of the heating stage was found.
(iv) Calculate, correct to the nearest whole number, the relative molecular mass of X, given that 0.22 g of X occupied a volume of 76 cm3 at a pressure of 1.011 × 105 Pa and a temperature of 99C.
(v) Bromine (Br2) (Mr = 160) has a significantly greater relative molecular mass than water (Mr = 18). Account for the volatility of bromine (boiling point 58.8 C) compared to that of water (boiling point 100 C).
i) Some vapour (gas, air) escaped.
ii) Flask filled with water using (with) graduated cylinder.
iii) Subtract the initial mass of the flask, rubber band and foil from the mass of flask, rubber band, foil and its contents.
iv) n= pV/ RT
pV=nRT
n = 2.49 × 10-3moles
Mr = m/n
Mr = 0.22/ 2.49x 10-3
Mr = 88.4 = 88
v) hydrogen (H) bonds in water
van der Waals forces in bromine (Br2)
intermolecular forces in water (H2O) stronger.
Intermolecular forces in bromine (Br2) weaker.
So Bromine (Br2) non-polar (pure covalent) while water (H2O) is polar
What are cathode rays?
beams of electrons
Bananas contain small quantities of potassium‐40, a radioactive isotope. What is the daughter nucleus when K‐40 emits an electron in beta decay?
calcium-40 / Ca-40
State Avogadro’s law.
Equal volumes of gases at the same temperature and pressure have equal numbers of particles.
What is the oxidation number of sulfur in
(i) sulfur dioxide (SO2),
(ii) the sulfate ion (SO42–)?
i) SO2: 4 / +4
ii) SO42– :6/+6
Give two differences between a sigma and a pi covalent bond.
Sigma bonds are formed from head-on overlap of orbitals while pi bonds are formed from sideways overlap of orbitals.
Sigma bonds are associated with single covalent bonds while pi bonds are associated with multiple covalent bonds.
Sigma bonds determine shape of molecule while Pi bonds do not determine shape of molecule.
In the electrolysis of aqueous KI with inert electrodes one half‐equation is:
2I– (aq) = I2 (aq) + 2e–
Write a balanced half‐equation for the reaction that takes place at the negative electrode during this electrolysis.
2H2O +2e –→ H2 +2OH–
Define bond energy.
This is the average amount of energy involved in breaking/ forming bonds of a particular type in a chemical species in the gaseous state.
What is the principle of the separation of the components in a mixture using any type of chromatography?
The components have different attractions for stationary and mobile phases.