Chemical Bonding Flashcards

1
Q

Lattice Enthalpy and its factors

A
  1. Energy released when one mole of ionic compound is formed by gaseous ions (-ve value) OR energy required to break one mole of ionic compound into its gaseous ions (+ve).
  2. Lattice enthalpy depends on charge and size. (between them charge dominates.)
  3. Size - smaller the size, more the lattice enthalpy - NaCl > KCl.
  4. More the charge, more the lattice enthalpy - MgO > CaCl2 > NaCl
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Formal Charge in a Lewis Structure

A

[Valance electrons - Lone pairs of electrons] - no. of bonds

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Inadequacies of the Octet Rule + Examples

A
  1. Fails to explain the stability of molecules having incomplete octet. ex: LiCl, BeH2, BeCl3, BeCl2, BF3, AlCl3 (central atom have incomplete octet)
  2. ” “ of expanded octet. ex: PCl5, SF6, IF7, H2SO4, ClF3 and co ordination compounds.
  3. ” “ of odd electron molecules ex: NO (nitric oxide) and NO2 (nitrogen dioxide).
  4. Based on inertness of noble gases but some noble gases like Xe and Kr form compounds like XeF2, KrF2 and XeOF2.
  5. Does not explain the shape of molecules.
  6. Does not explain the energy changes during bond formation.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

True or False : Ionization is always endothermic.

A

True

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Electrovalent bond will be easily formed between

A

Elements having low ionization enthalpy with elements having a high negative value of electron gain enthalpy.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Bond Enthalpy and it’s factors

A

Def: Amount of energy required to break one mole of bonds between two atoms in the gaseous state.
More the bond enthalpy, stronger is the bond.
Bond enthalpy depends on 1) size of atoms and 2) multiplicity of bonds.
1) smaller the size, stronger the bond.
2) multiplicity inc, bond enthalpy inc.
(Triple > double > single but triple is not 3* single)
In case of polyatomic molecules average bond enthalpy is used.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Bond length and it’s factors

A

Def: Equilibrium distance between the nuclei of two bonded atoms in a molecule.
1. Covalent radii - Half the distance between two similar atoms joined by a covalent bond.
2. Van der waal’s radii - Half the distance between two similar atoms in separate molecules in a solid.
Vanderwaals > Covalent
Factors 1) size 2) multiplicity
1) size - greater the size, more the bond length
2) multiplicity - greater the multiplicity, less the bond length - single > double > triple (pi bond decreases bond length)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Bond Order and its factors

A

No. of shared pair of electrons
ex: H2 is one, O2 is two and N2 is three.
For isoelectronic species - no. of electrons + bond order is the same. ex: O2 ^2- and F2 have the B.O 1 and electrons 18. N2, CO and NO+ have B.O 3 and electrons 14.
As bond order increases, bond enthalpy increases and bond length decreases.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Preference order for recognizing resonance stability (to solve which of these resonance structures is most stable type of q)

A
  1. More covalent bonds- more stable.
  2. No charge - more stable
  3. With charge - -ve charge on more electro-ve element
  4. Less separation of opposite charges
  5. Least stable - two similar charges on adjacent atoms
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Partial Ionic Character of Covalent bond (Non Polar and Polar covalent bonds)

A
  1. Non polar covalent bond - covalent bond between two atoms of the same element - same electronegativities - electron cloud is equally distributed - pure covalent bond. eg: H2, Cl2
  2. Polar covalent bond - covalent bond between diff elements having diff electronegativities - more electronegative element pulls electron cloud towards itself - electron cloud gets distorted - more electro -ve gets partial -ve charge and less electronegative gets partial +ve charge. This leads to partial ionic character. eg: HF (F- partial -ve and H - partial +ve)
    Also leads to dipole
    More electro-ve difference - more ionic character.
    Difference of 1.7 in electronegativities produces 50% ionic character in covalent bond.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Dipole Moment

A

Due to diff in electronegativity of a polar covalent bond dipole is produced.
Dipole moment is the product of the magnitude of the charge and the distance between the positive and negative charges.
Dipole moment (μ) = charge (Q) * distance of separation (r)
Expressed in Debye units.
1 D = 3.33564×10−30 C m
Dipole moment is a vector quantity and in polyatomic molecules spatial arrangement is also considered.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Which out of NH3 and NF3 has higher dipole moment and why?

A

NH3 has the higher dipole moment. Even though the electronegativity diff is greater in NF3, the dipole of the lone pair of N are oriented in the same direction as the N-H dipole in NH3, whereas they are oriented opposite to the N-F dipole in NF3 which why NH3 has higher dipole moment.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

How decide if a molecule is polar or non polar?

A
  1. AB - homonuclear (H2) - non polar but heteronuclear (HF) - polar.
  2. AB2 - linear (CO2) - non polar but bent (H20) is polar.
  3. AB3- trigonal planar (BF3) - non polar but trigonal pyramidal (NH3) is polar.
  4. AB4 - tetrahedral is usually non polar (CCl4) but if all bonds are not the same (CHCl3) it can be polar.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Polar or Non polar ?

HX (X is halogen i.e. HF, HCl, HI, HBr)

A

Polar

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Polar or Non Polar ?

H2

A

Non polar

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Polar or Non Polar ?

H2O

A

Polar

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

Polar or Non Polar ?

H2S

A

Polar

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

Polar or Non Polar ?

BeF2

A

Non polar

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
19
Q

Polar or Non Polar ?

NH3

A

Polar

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
20
Q

Polar or Non Polar ?

NF3

A

Polar

21
Q

Polar or Non Polar ?

BF3

A

Non polar

22
Q

Polar or Non Polar ?

CCl4

A

Non polar

23
Q

Polar or Non Polar ?

CHCl3

A

Polar

24
Q

Polar or Non Polar ?

CH4

A

Non polar

25
Q

Polar or Non Polar ?

XeF2

A

Non polar

26
Q

Polar or Non Polar ?

CO2

A

Non polar

27
Q

Polar or Non Polar ?

XeF4

A

Non polar

28
Q

Polar or Non Polar ?

CS2

A

Non Polar

29
Q

Partial Covalent Character of an Ionic Bond (Polarization and Fajan’s rules)

A

Sometimes in an ionic bond, positively charged cation, attracts the outermost electrons of an anion, causing distortion of the electron cloud and resulting in sharing of some electrons between the two - Polarization.
Extent of Polarization is given by Fajan’s rules -
1. Smaller the cation and larger the anion - greater the polarization. Therefore LiCl is more covalent than NaCl. LiI is more covalent than LiCl.
2. Greater the charge on the anion and cation, greater the polarization. Therefore AlCl3 > MgCl2 > NaCl.
3. Electronic configuration of cation. Cations with electronic configuration s²p ⁶d¹⁰ show more polarization than s²p ⁶ because d electrons provide very poor screening. Therefore CuCl2 is more covalent than NaCl and AgCl is more covalent than KCl.
4. Higher the dielectric constant of the medium, lower the polarization.

Ionic compounds with high polarization behave like covalent compounds - LiCl is more soluble in organic solvents than in water

30
Q

Full form of VSEPR Theory

A

Valance Shell Electron Pair Repulsion Theory

31
Q

Who came up with VSEPR

A

Sidgwick and Powell, modified by Nyholm and Gillespie

32
Q

Repulsive interaction of electron pairs

A

Lone pair - lone pair > bond pair - lone pair > bond pair- bond pair

33
Q

Postulates of VSEPR (from NCERT)

A
  1. Shape depends on number of valance shell electron pairs of a molecule.
  2. Electron pairs in the valance shell repel each other because their clouds are negatively charged.
  3. Pairs of electrons therefore occupy positions to maximize the distance and minimize the repulsion between them.
  4. Multiple bond is treated like a single electron pair - because once a single bond is formed, to avoid repulsion electron goes as far as possible and thus geometry is decided and the pi bond is formed in the same direction. So pi bond has no role in deciding the geometry of a molecule.
34
Q

Formula for calculating lone pair for VSEPR Structure

A

1/2 × valance electrons of central atom - n(unpaired electrons of other atom) + anion - cation
unpaired electron of oxygen is 2 and of hydrogen and halogens is 1

35
Q
BP LP (Bond pair Lone Pair)
2    0
A

Linear (angle 180)

36
Q
BP LP (Bond pair Lone Pair)
3    0
A

Trigonal Planar (120)

37
Q
BP LP (Bond pair Lone Pair)
4    0
A

Tetrahedral (109.5)

38
Q
BP LP (Bond pair Lone Pair) 
5    0
A

Trigonal bipyramidal (120 and 90)

39
Q
BP LP (Bond pair Lone Pair)
6    0
A

Octahedral (90)

40
Q
BP LP (Bond pair Lone Pair)
2    1
A

Bent (119.5)

41
Q
BP LP (Bond pair Lone Pair)
2    2
A

Bent (104.5)

42
Q
BP LP (Bond pair Lone Pair)
3    1
A

Trigonal pyramidal (107)

43
Q
BP LP (Bond pair Lone Pair)
3   2
A

T - shaped

44
Q
BP LP (Bond pair Lone Pair)
4   1
A

See saw

45
Q
BP LP (Bond pair Lone Pair)
4   2
A

Square planar

46
Q
BP LP (Bond pair Lone Pair)
5   1
A

Square pyramidal

47
Q

Who put forward the valance bond theory?

A

Heitler and Londan, modified by Pauling and Slater

48
Q

What are bonding orbitals?

A

Atomic orbitals with unpaired electrons. (should have comparable energy and opposite spin to form a orbital

49
Q

Strength of the bond in VBT depends on what?

A

The extent of overlapping, greater the overlapping, more energy will be released and the bond will be stronger. (no. of bonds formed is equal to the overlapping orbitals)