CHEM 112 - MIDTERM III Flashcards
When titrating a weak acid (HA) with a strong base (OH-) what is left in the solution & equivalence point?
- left in the solution: H2O + A- (weak conjugate base)
-equivalence point: moles OH- added = moles HA in original solution
When titrating a weak base (A-) with a strong acid (H+) what is left in the solution & equivalence point?
-left in the solution: H20 + HA (strong conjugate acid)
-equivalence point: moles H+ added = moles A- in original solution
When we add a strong acid to the buffer, what happens?
Neutralization reaction occurs; acid is neutralized, consuming the conjugate base and producing conjugate acid –> [A-] decreases and [HA] increases
When we add a strong base to the buffer, what happens?
[A-] increases and [HA] decreases
- Divide moles by total volume of solutions to find new concentrations of [HA] and [A-] AFTER neutralization is complete
- Plug in equilibrium equations in Henderson-Hasselbalch equation to find pH
Calculation of pH in the buffer region
- Write out dissociation rxn (find out which reagent is being consumed, in a weak acid (first) and strong base, the base will be consumed)
- Calculate the moles of HA (initial HA)
- Calculate moles of OH- (initial OH-)
- Use modified ICE table (using moles and subtract OH- from initial weak acid moles)
- Use total volume of solutions to find new concentrations of the weak acid and conjugate base
- Use H-H equation
Calculation of pH at the equivalence point
- Determine # of moles of OH- to get to the equivalence point
- Determine the volume of OH- needed to get the moles calculated in (1)
- Determine the new total volume
- Determine the new concentration of the conjugate base (A-)
- Complete a pH calculation for a weak base with the initial concentration determined in (4)
Calculation of pH beyond equivalence point
- Beyond the equivalence point, OH- is in excess. Calculate [OH-] by subtracting the initial number of moles of H3O+ from the number of moles of added OH- and by dividing by the current total volume
- Calculate pOH and use this to find pH
Between the initial pH and equivalence point, the solution becomes a _____.
buffer
Halfway to the equivalence point the pH = ____
pKa
In the buffer region, we use the stoichiometry and the _____ equation to calculate the pH
Henderson-Hachelbach
At the equivalence point, the acid has been converted to conjugate base. We calculate pH by _____
Working an equilibrium problem for the ionization of water by the ion acting as a weak base
Beyond the equivalence point, OH- is in excess, we calculate the pH by ____
Calculating [OH-] by calculating moles of OH- and subtracting from the acid (HA) and dividing the moles by the total volume. Find pOH and subtract from 14 for pH
Salts are ____
ionic compounds dissolved in water to form aqueous solutions
The extent of a dissociation describes the _____ of the ionic compound
solubility
If an ion does NOT have a Ksp value, what does that mean?
They are fully soluble in solutions
Salts that contain _____ are almost always soluble
Na+, K+, Cl-, and NO3-
Most other salts are ____ to some degree
insoluble
Ksp
Solubility product constant; measures how soluble a compound is
If Ksp is very small then ____
the ion concentrations are very small and the compound is not very soluble
Solubility products are usually highlighted by ____ arrows
double
Molar solubility
the number of moles of solute per 1 L of a saturated solution (mol/L)
Solubility
the number of grams of solute in 1 L of a saturated solution
When Q is ____ than K, a precipitate will form
>
If there are two possible precipitates that can form, the one with the ____ Ksp will precipitate first
smallest
If the concentrations of ions in solution of a slightly soluble salt (one with a Ksp) exceed the value of the ____ of that salt, a precipitate will form
molar solubility