Chapter_7_Powerpoint 2022 Flashcards

1
Q

What is the formula mass?

A

The mass of a single molecule or formula unit

Example: The formula mass of a water molecule (H2O) is calculated as 2(1.01 u) + 1(16.00 u) = 18.02 u.

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2
Q

How do you calculate the percent composition of one element in a compound?

A

Percent composition = (mass of one element / mass of compound) x 100%

Example: For octane (C8H18), the percent composition of carbon is 84.09% and hydrogen is 15.91%.

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3
Q

What technique is used to measure the mass of molecules?

A

Mass spectrometry

This technique measures the mass of molecules by ionizing chemical species and sorting them based on their mass-to-charge ratio.

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4
Q

What is Avogadro’s Number?

A

6.02 x 10^23 units

This number is used to relate moles to particles, such as atoms or molecules.

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5
Q

How many grams are in one mole of carbon?

A

12.01 grams

The molar mass of carbon is equivalent to its atomic mass in grams.

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6
Q

What is the relationship between grams, moles, and particles?

A

Moles relate atoms to grams and particles

For example, 1 mole of CO2 (44.01 g) contains 6.02 x 10^23 molecules.

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7
Q

Differentiate between theoretical yield and actual yield.

A

Theoretical yield is the maximum amount of product that can be produced, while actual yield is the amount actually obtained from a reaction

Percent yield is calculated using the formula: (actual yield / theoretical yield) x 100%.

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8
Q

What is the formula mass of potassium carbonate (K2CO3)?

A

138.21 u

It is calculated as 2(39.10 u) + 1(12.01 u) + 3(16.00 u).

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9
Q

What is the percent yield if the theoretical yield is 50 g and the actual yield is 40 g?

A

80%

Percent yield = (40 g / 50 g) x 100%.

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10
Q

Fill in the blank: 1 atomic mass unit (u) = ______ g.

A

1.66 x 10^-24 g

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11
Q

What is the percent composition of hydrogen in water (H2O)?

A

11.19%

The calculation is based on the formula mass of water, which is 18.02 u.

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12
Q

What is the limiting reagent in a chemical reaction?

A

The reactant that is completely consumed first, limiting the amount of product formed

It determines the maximum yield of the reaction.

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13
Q

How do you convert grams of a substance to moles?

A

Use the formula: grams / molar mass

For NaCl, if you have 305 g, you divide by its molar mass (58.44 g/mol) to find moles.

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14
Q

Fill in the blank: The formula mass of carbon dioxide (CO2) is ______ g.

A

44.01 g

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15
Q

What is the mass in grams of 2.53 x 10^23 iron atoms?

A

23.5 grams Fe

Calculated using the relationship between atoms and moles, and then converting moles to grams.

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16
Q

True or False: The actual yield can never exceed the theoretical yield.

A

True

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17
Q

What is the mole ratio of H2 to O2 in the combustion of methane (CH4)?

A

2:1

The balanced equation is CH4 + 2 O2 → CO2 + 2 H2O.

18
Q

What is the molar mass of NaCl?

A

58.44 g/mol

19
Q

What is stoichiometry?

A

Using the amount of one material to predict the amount of another based on the balanced equation

It involves calculations using molar ratios from balanced chemical reactions.

20
Q

Fill in the blank: The formula mass of magnesium oxide (MgO) is ______ g.

21
Q

What does the term ‘excess reagent’ refer to?

A

The reactant that is not completely consumed in a reaction

It remains after the limiting reagent is used up.

22
Q

How many grams of MgO can be produced from 5.24 g of MgCO3?

A

2.51 g

Calculation uses the stoichiometry of the reaction and molar masses.

23
Q

What is the theoretical yield of a reaction?

A

The calculated maximum amount of product that can be formed from given reactants

24
Q

What is the limiting reagent when 1.2 moles of potassium reacts with 15 moles of chlorine gas?

A

K is the limiting reagent

K is completely consumed, limiting the amount of product formed.

25
Q

What is the excess reagent when 1.2 moles of potassium reacts with 15 moles of chlorine gas?

A

Cl2 is the excess reagent

Cl2 is not completely consumed, leaving some leftover after the reaction.

26
Q

How many moles of potassium chloride can be produced from 1.2 moles of potassium?

A

1.2 moles KCl

Based on the reaction 2 K + Cl2 → 2 KCl.

27
Q

How many moles of potassium chloride can be produced from 15 moles of chlorine gas?

A

30 moles KCl

Based on the stoichiometry of the reaction.

28
Q

What is the limiting reagent when 30 moles of uranium react with 75 moles of fluorine gas?

A

F2 is the limiting reagent

F2 limits the amount of UF6 that can be produced.

29
Q

How many moles of UF6 can be produced from 30 moles of uranium?

A

30 moles UF6

Based on the reaction U + 3 F2 → UF6.

30
Q

How many moles of UF6 can be produced from 75 moles of F2?

A

25 moles UF6

Based on the stoichiometry of the reaction.

31
Q

Using the recipe, how many turkey-and-cheese sandwiches can be made with 80 slices of bread, 18 slices of turkey, and 15 slices of cheese?

A

15 sandwiches

Limited by the number of cheese slices.

32
Q

What is the theoretical yield?

A

The amount of a product that can form, based on the balanced equation

It is a calculated value, not the actual yield observed.

33
Q

What is the actual yield?

A

The amount actually obtained

This is the measured amount after a reaction.

34
Q

How is percent yield calculated?

A

Percent yield = (Actual yield / Theoretical yield) × 100%

This formula helps assess the efficiency of a reaction.

35
Q

What can cause the actual yield to be lower than the theoretical yield?

A

Material sticks to container walls, unwanted side products, product lost during purification

These factors reduce the amount of product obtained.

36
Q

What is the percent yield for a reaction with a theoretical yield of 240 grams and an actual yield of 180 grams?

A

75%

Calculated as (180 g / 240 g) × 100%.

37
Q

What is the theoretical yield of SF6 from 120.0 kg of sulfur reacting with excess fluorine gas?

A

546.7 kg SF6

Based on the stoichiometry of the reaction S + 3F2 → SF6.

38
Q

What was the percent yield for the production of SF6 if 480.2 kg was isolated?

A

87.84%

Calculated as (480.2 kg / 546.7 kg) × 100%.

39
Q

What is the theoretical yield of magnesium oxide from 5.25 grams of MgCO3?

A

To be calculated based on stoichiometry

Requires the balanced equation MgCO3 → MgO + CO2.

40
Q

What is the percent yield if 2.37 grams of MgO are obtained from the reaction starting with 5.25 grams of MgCO3?

A

To be calculated based on theoretical yield

Requires the theoretical yield value to compute.

41
Q

What is the percent yield for a reaction starting with 14.2 g of C6H6 and isolating 13.7 g of C6H5Br?

A

To be calculated based on theoretical yield

Requires the theoretical yield value to compute.