Chapter 8 Light & Optics Flashcards
Electromagnetic waves are transverse waves because
- Because the oscillating electric and magnetic field vectors are perpendicular to the direction of propagation.
- The electric field and the magnetic field are also perpendicular to each other
Electromagnetic spectrum from lowest frequency to highest
-Radiowaves, microwaves, infrared, visible light, ultraviolet, and x ray
Speed of Light
-Electromagnetic waves vary in frequency and wavelength, but in a vacuum & in air all electromagnetic waves travel at the same speed
Speed of Light Equation
c=fλ
c= speed of light in a vacuum/air
f=frequency
λ=wavelength
Visible Region
- only part of the spectrum that is perceived as light by the human eye
- different wavelengths perceived as different colors
- violet at one end (400nm) and red at the other (700nm)
- Light that contains all the colors in equal intensity is perceived as white
- Object that appears red is one that absorbs all the colors of light except red
Blackbody
- refers to an ideal absorber of all wavelengths of light
- would appear completely black if it were at a lower temperature than its surroundings
Rectilinear Propagation
-When light travels through a homogeneous medium, it travels in a straight line
Theory of Geometrical Optics
- The behavior of light at the boundary of a medium or interface between two media
- Explains reflection and refraction
Reflection
The rebounding of incident light waves at the boundary of a medium
-light waves that are reflected are not absorbed into the second medium; they bounce off the boundary and travel back through the first medium
Real vs Virtual images created by a mirror
- Real if the light converges at the position of the image
- Virtual if the light only appears to be coming from the position of the image but doesn’t actually converge there
- Distinguishing feature of real images: ability of the image to be projected onto a screen
Plane mirrors
- flat, reflective surfaces cause neither convergence nor divergence of reflected light rays
- since the light doesn’t converge, plane mirrors will always create virtual images
- Create the appearance of light rays originating behind the mirrored surface
Spherical mirrors
- Center of curvature: a point on the optical axis located at a distance equal to the radius of curvature from the vertex of the mirror
- Concave(converging) mirror: center of curvature and radius of curvature are located in front of the mirror
- For all spherical mirrors: f=r/s (r=radius of curvature, the distance between C and the mirror)
Focal Length (f)
The distance between the focal point (F) and the mirror
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Image distance equation
1/f=1/o+1/i=2/r
f=focal length
o=distance between object and mirror
i=distance between image and mirror
r=radius of curvature
-if the image has a positive distance (i>0), it is a real image which implies that the image is in front of the mirror
-if the image has a negative distance (i<0), it is virtual and located behind the mirror
-plane mirrors: r=f=infinity and the equation becomes 1/o+1/i=o
magnification (m) and equation
-Dimensionless value that is the ratio of the image distance to the object distance
m=-i/o
-Also gives the ratio of the size of the image to the size of the object
-negative magnification=inverted image
-positive magnification=upright image
-|m|1 image is larger than object. |m|=1 image is the same size as the object