Chapter 8,9,10 Test Flashcards
Solution
a homogenous mixture of 2 or more substances
the particles are of molecular size
Solvent
part of the solution which does the dissolving
most common types is water (aqueous solution)
Solute
part of the solution which is dissolved
Calculating a Solution: STEPS
- Determine n = Cx V
2. Determine m = n x M
Preparing a Solution: STEPS
- Use an electronic balance to obtain the desired mass of solute
- Transfer all of the solute to the volumetric flask
- Add water until the flask is about half full. Then swirl the flask to dissolve the solid in the water completely
- Fill the flask by adding water slowly and carefully, using a wash bottle, until the bottom of the meniscus just touches the etched line on the flask
- Stopper the flask and mix it by inverting it several times.
Calculating a Dilution: STEPS
- Determine the dilution factor
- Determine the amount of solvent needed using the dilution formula
c1v1 = c2v2 - Plug in the known quantities da solve
Preparing a Dilution: STEPS
- Add about 10 or 20 mL of water to a volumetric flask and set it aside
- Start with a clean, dry pipette that can measure the needed volume of solution. Squeeze the pipette bulb and place it over the pipette
- Rinse the pipette with the solution to be measured
- a) Squeeze the bulb again and then place the tip into the solution to be measured
b) Fill the pipette until it is beyond the line indicating the desired volume - Remove the bulb and quickly and smoothly seal the top of the pipette with your finger or thumb. Remove pipette from solution
- Carefully release your finger allowing just enough liquid to escape so that the meniscus is at the graduation mark of the desired volume
- a) Keep your finger tightly over the pipette and transfer the tip to the volumetric flask
b) Touch the tip of the pipette against the side of the flask and allow the solution to flow into the flask - a) Fill the volumetric flask to the graduated line with water
b) Stopper the flask and mix the solution by inverting the flask several times
c) Check the volume reading after mixing and add more water if needed
Ionic Equation
equations in which soluble compounds that dissociate are written as ions
Net Ionic Equation
equations in which only substances which take part in the reaction are written
Spectator Ions
Ions that don’t participate in the reaction
Arrhenius Theory
Acid: any substance that dissociates to form Hydrogen in an aqueous solution
Base: any substance that dissociates to form OH in an aqueous solution
Bronstead-Lowry Theory
Acid: any substance from which a proton may be removed
Base: any substance that
removes a proton from an acid
Problems with A’s theory
water remains unchanged in the equation for the dissociation of hydrochloric acid in water. However, since H2O is a polar molecule, the H ion attaches itself to awater molecule forming a HYDRONIUM ION, H30+
Conjugate Acid
the particle that results when the base receives the proton from the acid
Conjugate Base
the particle that remains when a proton is removed from the acid