Chapter 8 Flashcards
generalized eigenvector
suppose T in L(V) and λ is an eigenvalue of T.
A vector v in V is called a generalized eigenvector of T corresponding to λ
if v ≠ 0
and ((T - λId)^j)*v = 0 for some positive integer j
generalized eigenspace (G(λ, T))
Suppose T in L(V) and λ in F.
The generalized eigenspace of T corresponding to λ, denoted G(λ, T), is defined to be the set of all generalized eigenvectors of T corresponding to λ,
along with the 0 vector
nilpotent
an operator where some power of it equals 0
description of operators on complex vector spaces
Suppose V is a complex vector space and T in L(V).
Let λ1,…,λm be the distinct eigenvalues of T.
Then:
(a) V = G(λ1, T) (+) … (+) G(λm, T)
(b) each G(λj, T) is invariant under T
(c) each (T - λjId) restricted to G(λj, T) is nilpotent
Jordan basis
Suppose T in L(V).
A basis of V is called a Jordan basis for T if w.r.t. this basis T has a block diagonal matrix ((A1,…,0),…,(0,…,Ap)),
where each Aj is an upper-triangular matrix of the form Aj = ((λj, 1, …, 0),…,(…,1),(0,…,λj))
Jordan Form
Suppose V is a complex vector space.
If T in L(V),
Then there is a basis of V that is a Jordan basis for T
description of generalized eigenspaces
Suppose T in L(V) and λ in F.
Then G(λ, T) = ker(T - λId)^(dim V)
matrix of a nilpotent operator (useful result)
suppose N is a nilpotent operator on V.
Then there is a basis of V w.r.t. which the matrix of N has the form ((0,…,*), …, (0,…,0)); here all entries on and below the diagonal are 0’s
a basis of generalized eigenvectors (useful result)
Suppose V is a complex vector space and T in L(V).
Then there is a basis of V consisting of generalized eigenvectors of T
sum of the multiplicities equals dim V
Suppose V is a complex vector space and T in L(V).
Then the sum of the multiplicities of all the eigenvalues of T equals dim V
Multiplicity of an eigenvalue
The dimension of the corresponding generalized eigenspace