Chapter 7 - Kinematics Flashcards

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1
Q

Displacement defintion

A

Distance in a given direction

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2
Q

Speed definition

A

Change of distance per unit time

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3
Q

Velocity definition

A

Change of displacement per unit time
- Speed in a given direction
- Rate of change of displacement

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4
Q

Speed equation

A

Speed = distance travelled/time
- v = s/t

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5
Q

Equation for constant speed in a circular motion

A

Constant speed on a circle of radius, r = 2πr/T
- T = time taken to complete one rotation

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6
Q

Shape of a distance-time graph for an object moving at constant speed

A
  • Straight line with a constant gradient
  • Speed = distance/time = gradient of the line
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7
Q

Motion of an object moving with constant velocity

A
  • Moves at the same speed without changing its direction of motion
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8
Q

Acceleration definiton

A

Change of velocity per unit time
- Rate of change of velocity

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9
Q

What is the gradient of a velocity-time graph equal to?

A

The acceleration

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10
Q

What are the conditions of motion under which the kinematic equations apply?

A
  • Uniform acceleration
  • Motion along a straight line
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11
Q

Equstion for motion without displacement (s)

A

v = u + at
- derived from y = mx + c → velocity time graph
- y-axis = v, x-axis = t
- y-intercept = c = u
- gradient = x = t

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12
Q

What is non-uniform acceleration?

A

When the direction of motion of an object changes, or its speed changes, at a varying rate

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13
Q

How is non-uniform acceleration seen on a velocity-time graph?

A
  • Curve
  • Gradient represents acceleration so increases/decreases with time
  • Second derivative is rate of change of acceleration
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14
Q

Equation for motion without acceleration (a)

A

s = ((u+v)t)/2
- derived from the area of a trapezium = 1/2(a+b)h → s = area under graph
- Can also be derived from average velocity = (u+v)/2 combined with s = vt

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15
Q

Equation for motion without time (t)

A

v^2 = u^2 + 2as
- Derived by combining a = (v-u)/t and s = ((u+v)t)/2

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16
Q

Equation for motion without final velocity (v)

A

s = ut + 1/2at^2
- Derived by combining s = ((u+v)t)/2 and v = u + at

17
Q

How is displacement represented on a velocity-time graph?

A

From the area under the graph

18
Q

Why does a heavy object not fall faster than a lighter one in a vacuum?

A

W = mg
- Acceleration due to gravity is constant
- g = W/m → When mass increases, weight also increases proportionally, so the increase cancels out in the equation for acceleration

19
Q

How does the steepness of a slope affect acceleration?

A
  • Acceleration is greater the steeper the slope
20
Q

How to investigate the free fall of a ball?

A
  • Take a multiflash photo or video of the ball’s flight as it falls after being released from rest
  • Verticle metre rule provides scale
  • Ordinary camera with slow shutter speed used to record ball’s descent in a dark room illuminated by a stroboscope flashing at a constant rate of about 20 flashes per second
  • Record the distance fallen at a given time
  • Calculate acceleration from s = ut + 1/2at^2
  • Graph of s against t^2 will be a straight line through the origin with acceleration of 2 x gradient
21
Q

When is an object in free fall?

A

When there are no external forces acting on the object apart from the force of gravity

22
Q

What is the acceleration of free fall?

A

Acceleration due to gravity
- 9.81 ms^-2 when near the Earth’s surface

23
Q

Motion of a ball thrown directly upwards on a displacement-time graph

A
  • Immediately after being thrown, the velocity is positive and large so the gradient is positive and large
  • As the ball rises, velocity decreases so gradient decreases
  • At max height, velocity is zero so gradient is zero
  • As the ball descends, its velocity becomes increasingly negative, so gradient becomes increasingly negative, as its now moving in the opposite direction
24
Q

What is a projectile?

A

Any object acted upon only by the force of gravity

25
Q

Key prinicples that apply to all projectiles

A
  1. Acceleration only affects the vertical motion of the object - acceleration always equal to g and acts downwards as force of gravity acts downwards.
  2. Horizontal velocity is constant because the acceleration does not have a horizontal component
  3. Motions in the horizontal and vertical directions are independent of each other
26
Q

When do two objects reach the ground, one dropped vertically and the other projected horizontally, relative to each other and why?

A
  • Both reach the ground at the same time
  • Both experience the same vertical acceleration and start from the same vertical velocity (zero)
  • Horizontal velocity independent from (has no effect on) vertical velocity
27
Q

Why does an object projected velocity fall with a parabolic trajectory in the absence of air resistance?

A
  • Horizontal velocity is constant - no horizontal velocity
  • Vertical velocity increases at a constant rate - uniform vertical acceleration - vertical path gets steeper as it falls
28
Q

When will an object experience projectile-like motion?

A

When the object has constant acceleration in a different direction to its velocity

29
Q

What causes the drag force on a moving object?

A
  • Air resistance - friction between the layers of air near the projectile’s surface where the air flows over the surface
30
Q

How does the drag force act?

A
  • Acts in the opposite direction to the direction of motion of the projectile
  • Drag force increases as projectile’s speed increases
31
Q

How does the drag force affect the horizontal motion of a projectile?

A

Horizontal component of drag force reduces the horizontal speed of the projectile and its range

32
Q

How does the drag force affect the vertical motion of a projectile?

A
  • Reduces its maximum height of the projectile if its initial direction is above the horizontal
  • Makes its descent steeper than its ascent
33
Q

How can the shape of the object cause a lift force?

A

When the shape casuses air to flow faster over the top of the object than underneath it
- Causes the pressure on the top of the surface to be less than on the bottom
- Pressure difference causes the lift force

34
Q

Equation for vertical displacement when air resistance is present

A

y = UtsinΘ - 1/2gt^2
- Vertical displacement = UtsinΘ without air resitance
- Displacement 1/2gt^2 lower due to drag

35
Q

Equation for vertical component of velocity when air resistance is present

A

V(y) = UsinΘ - gt
- Vertical velocity = UsinΘ without air resistance
- Velocity gt lower due to drag