Chapter 6 Flashcards
Calculating heat of reaction
Bonds broken(total molecule not part)-bonds formed
Exothermic vs endothermic
DeltaH >0 endothermic
Spontaneous given direction written
If deltaH is <40 kj/mol
It is uncertain
Otherwise
Delta S=total moles of reactant-totals moles of product
If deltaS =0 and deltah >[40] then spontaneous
Reaction energy diagram
Activation energy
From letter to highest point after letter
Overall energy change
Total displacement from one letter to another
Faster step
Shortest distance from letter to transition state
Transition states are the peaks
Delta g+- if the graph ends higher than it started it’s positive
Addition reaction mechanism
Double bond disappears and added compound turns into one side of double bond
Given deltaH and deltaS
Endo vs exo
Spontaneous vs non
Keq <1 >1 =1
deltaH less than 0 exo
deltaH greater than 0 endo
DeltaG less than 0 spon
Delta G greater than 0 non
DeltaG less than 0 spon
DeltaG less than 0 spon
DeltaG less than 0 spon
Addition reaction
Combination of two molecules
Elimination reaction
One reactant multiple products
Substitution reaction
2 reactants 2 products
Rearrangement reaction
One product one reactant
Electrophile
Reactant with positive charge
Incomplete octet
Nucleophile
Reactant with Lone pair connects to positively charged molecule
Calculate deltaG given DeltaH and DeltaS
TDeltaS-DeltaH=DeltaG