Chapter 5 - Forces Flashcards

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0
Q

The equation for moment M

A

M = Fd

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1
Q

Moment of a torque

A

It is the product of the force and the perpendicular distance of the force from the pivot

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2
Q

Torque of a couple

A

It is the product of a magnitude of one force and the perpendicular distance between two forces

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3
Q

The equation for torque T

A

T = Fd

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4
Q

Centre of gravity

A

It is the point at which the whole weight of the body is considered to act

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5
Q

Principle of moment

A

The sum of the clockwise moments about a point equals the sum of the anticlockwise moments about the same point

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6
Q

2 conditions for a body to be in equilibrium

A
  1. Resultant force is zero
  2. Resultant moment / torque is zero OR
    sum of clockwise moments = sum of anticlockwise moments
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7
Q

Describe how to draw a vector triangle to represent forces in equilibrium. Add a confirmation.

A
  1. Each force is represented by an arrow - in magnitude and direction
  2. The arrows are joined head to tail
    (Confirmation: If the triangle is ‘closed’, then the forces are in equilibrium)
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8
Q

Why a weight couldn’t be supported by strings that are horizontal

A
  1. The forces in strings would be horizontal

2. So, there’s no vertical force to support the weight

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9
Q

A card swings on a rod. List 2 forces, other than weight and air resistance, that act on the card during the time it is swinging

A
  1. Normal reaction force at the rod

2. Friction force at the rod

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10
Q

State the position in which the cards come to rest. Explain.

A

The card comes to rest with the weight acting through the rod and allows the centre of gravity to be vertically below the rod.

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