chapter 5: DNA replication, end-replication problem & telomeres Flashcards
the first replication in the 14N medium produced a band of hybrid 14N-15N DNA molecules of intermediate density:
- the parental 15N-15N molecule unwinds, ________ and ______ , and each 15N strand acts as a ______ for the synthesis of a new ________
- ______ containing 14N are added via complementary base pairing with the template strand to form the new daughter strand
- each daughter _______ consists of. one 15N parental strand which is ‘heavy’ and one 14N daughter strand which is ‘ light;
- hence, this results in hybrid 14N-15N DNA molecules which are of ________ ________
- the parental 15N-15N molecule unwinds, unzips and separate , and each 15N strand acts as a template for the synthesis of a new daughter strand
- deoxyribonucleotides containing 14N are added via complementary base pairing with the template strand to form the new daughter strand
- each daughter DNA molecule consists of one 15N parental strand which is ‘heavy’ and one 14N daughter strand which is ‘ light;
- hence, this results in hybrid 14N-15N DNA molecules which are of intermediate density
the second replication in 14N medium produced a band of hydrid 14N-15N DNA molecules and a band of 14N-14N DNA molecules
- the parental 14N-15N molecule unwinds, ________ and ______ , and each 15N strand acts as a ______ for the synthesis of a new ________
- ______ containing 14N are added via complementary base pairing with the template strand to form the new daughter strand
- half of the daughter DNA molecules would consist of one 15N parental strand and one 14N daughter strand each, resulting in 14N-15N DNA molecules of intermediate density
- The half would consist of one 14 N daughter strand and one 14N parental strand each, resulting in 14N-14N DNA molecules of light density
- the parental 14N-15N molecule unwinds, unzips and separates , and each 15N strand acts as a template for the synthesis of a new daughter strand
- deoxyribonucleotides containing 14N are added via complementary base pairing with the template strand to form the new daughter strand
- half of the daughter DNA molecules would consist of one 15N parental strand and one 14N daughter strand each, resulting in 14N-15N DNA molecules of intermediate density
- The half would consist of one 14 N daughter strand and one 14N parental strand each, resulting in 14N-14N DNA molecules of light density
INITIATION:
what are origins of replication and how is it different in prokaryotes and eukaryotes?
- DNA replication begins at specific sites called the origins of replication, where two parental DNA strands separate to form a replication bubble
- this site is usually rich in adenine and thymine
in prokaryotic cells:
- only one chromosome is present
- this chromosome is in the form of a circular DNA molecules and with a single origin of replication
in eukaryotic cells:
- the genome and DNA molecules are comparatively larger in size
- eukaryotic chromosomes are linear
- many origins of replication are present
- multiple replication bubbles form and eventually fuse to give two complete daughter DNA strands, thus increasing the rate at which DNA replication occurs
INITIATION:
describe strand separation
- after DNA is unwound from the histone proteins, the enzyme helical recognises and binds to DNA at the origin of replication, and unwinds and unzips the DNA molecule by breaking the weak hydrogen bonds between the bases
- this separates the parental strands, exposing the template for DNA replication
- helicase is ATP dependent, its activity requires energy to break strands apart
- replication of DNA then proceeds in both directions from the origin of replication until the entire molecule is copied
- unwinding produces a replication bubble which contains two replication forks
- the separated strands of parental DNA are unstable and have the tendency to reform the DNA double helix
- single-strand DNA-binding proteins thus bind to separated strands of parental DNA, which stabilised the unpaired DNA strands and keeps the strands apart,
- while they serve as templates for the synthesis of new complementary DNA strands
- unwinding also causes the helix ahead of the replication fork to rotate, causing further twisting and strain ahead of a replication fork
- topoimerase helps to relieve strain by breaking, swiveling and re-joining DNA strands
INITIATION:
describe the process of priming DNA synthesis
- before DNA synthesis can begin, there must be small pre-existing primers to start the addition of new nucleotides
- the enzyme primase catalyses the synthesis of a short RNA chain of around ten ribonucleotides called an RNA primer that is complementary to the 3’ end of the parental DNA template
- the enzyme which is directly involved in the synthesis of the new DNA strand is DNA polymerase
- a primer is required because DNA polymerase cannot initiate the synthesis of a polynucleotide strand
- DNA polymerase cannot only add deoxyribonucleotides to a free 3’ OH end of a pre-existing strand that is already base paired with the template strand
- this is due to the active site specificity of DNA polymerase which is only complementary in 3D conformation to a free 3’ OH group of a pre-existing chain base paired to the template Adna
- this is also the reason why DNA replication occurs in the 5’ to 3’ direction
- the RNA primer thus provides a 3’ OH end available for DNA polymerase
- it is base paired to the complementary DNA template strand and is anti parallel to the template strand
describe elongation: synthesis of new DNA strands
- DNA elongation of the daughter strand only occurs in the 5’ to 3’ direction
- this means that nucleotides are added to the free 3’ OH end of a growing DNA strands
- each parental strand acts as a template to determine the order of the bases to be added to the new daughter strand through complementary base pairing via hydrogen bond formation between the bases
- A pairs with T, and G pairs with C
-DNA polymerase catalyses the addition of DNA nucleotides and formation of phosphodiester bonds between adjacent DNA nucleotides, in the 5’ to 3’ direction - as DNA polymerase moves along the template, part of the enzyme ‘proofreads’ the previous region
- this is to check if proper base pairing has taken place between the bases
- if a wrongly paired deoxyribonucleotide was added, this would be swiftly removed by the enzyme and replaced with the correct DNA nucleotide
- a different DNA polymerase then removed the RNA primer and replaces it with DNA nucleotides
anti-parallel elongation of DNA strands
- since the parental strands are _______, the two daughter strands are synthesised in ________ _______ with respect to each other because
- _________ can only add deoxyribonucleotides to a free 3’ OH end of a _______ _________. hence elongation can only occur in the ___ to ___ direction
- the parental template DNA strands are antiparallel to each other
- one of the elongating strands is known as the ______ strand while the other is known as the _____ strand
since the parental strands are antiparallel, the two daughter strands are synthesised in opposite directions with respect to each other because
- DNA polymerase** can only add deoxyribonucleotides to a free 3’ OH end of a pre-existing strand hence elongation can only occur in the ** 5’ to 3’ ** direction
- the parental template DNA strands are antiparallel to each other
- one of the elongating strands is known as the leading strand while the other is known as the lagging strand
ELONGATION:
describe the process of the synthesis of the leading strand
- along one of the template strands, DNA polymerase adds DNA nucleotides continuously in the 5’ to 3’ direction as the replication fork unwinds
- the new strand is synthesised continuously as a single polymer towards the replication fork
- the DNA strand made by this mechanism is called the leading strand
ELONGATION:
describe the process of the synthesis of a lagging strand:
- as the replication fork unwinds, some template is exposed
- primase adds ribonucleotides that are complementary to the 3’ end of the template and catalyses the formation of phosphodiester bonds between adjacent RNA nucleotides to form an RNA primer - next, DNA polymerase adds DNA nucleotides to the 3’ OH of the RNA primer, forming the first okazaki fragment in the 5’ to 3’ direction
- as more of the template strand is exposed with the unwinding of DNA at the replication fork, a second RNA primer is synthesised by primase
- DNA polymerase then adds DNA nucleotides to the second primer and detaches when it reaches the first primer - another DNA polymerase then removes the RNA primer and replaces it with DNA nucleotides
- DNA ligase next forms a phosphodiester bond between free OH group at 3’ end of each new okazaki fragment to the phosphate group at the 5’ end of the growing chain
synthesis of the lagging strand:
- the lagging strand is synthesised _______ and is produced as a series of short ______ of DNA nucleotides called _______ _______
- each okazaki fragment is synthesised in the __ to __ direction by DNA polymerase, and eventually joins up with the other fragments, forming a _____ DNA strand
- the direction of synthesis of each okazaki fragment is _____ from the replication fork
- the DNA strand synthesised in this direction is called the lagging strand
- the lagging strand is synthesised discontinuously and is produced as a series of short segments of DNA nucleotides called ** okazaki fragments**
- each okazaki fragment is synthesised in the 5’ to 3’ direction by DNA polymerase, and eventually joins up with the other fragments, forming a continuous DNA strand
- the direction of synthesis of each okazaki fragment is away from the replication fork
- the DNA strand synthesised in this direction is called the lagging strand
describe the process of termination
- the termination of replication occurs when two replication forks meet each other
- the complementary parental and daughter DNA strands rewind into a double helix
- the process is semi-conservative since each new DNA molecule consists of one parental DNA strand and one newly synthesised daughter DNA strand
- mismatched nucleotides sometime evade proof reading mechanism by DNA polymerase
- after replication, DNA repair enzymes can recognise mismatched nucleotides, remove the nucleotides, and replaces it them with the correct nucleotides based on complementary base pairing rule
- this mechanism is also responsible for the repair of DNA that might have been damaged by chemicals and radiation
what does the end replication problem result in?
- the 3’ ends of the template DNA strand not being replicated
- which also means the 5’ ends of the newly synthesised daughter strands are shorter relative to that of the previous generation
how does the end replication problem occur?
- when the lagging strand is synthesised, many okazaki fragments are formed
- each fragment has a primer made by primase
- DNA polymerase removes the primers and fills the gap with complementary deoxyribonucleotides
- however at the 5’ end of the lagging strand, the last primer cannot be replaced with DNA nucleotides because of the lack of an existing 3’OH end of a pre-existing strand
- therefore, complete replication of the 5’ ends of daughter DNA strands cannot occur, and as a result, the new daughter chromosome formed lack a certain length of DNA at each 5’ end
- this causes chromosomes to become shorter with each cell division
- after repeated rounds of replication and cell division, essential genes would be eroded from the ends of the chromosomes
what is the structure of telomeres?
- telomeres are found at both ends of a linear chromosome
- telomeres consist of multiple tandem repeats of a short, non-coding DNA sequence, which varies from species to species