Chapter 5

Question 0

How is standard form found when given slope-intercept form?

Answer 0

y=2/5x-3 Write the original equation

5y=5(2/5x-3) Multiply each side by 5

5y=2x-15 Use distributive property

-2x+5y=-15 Subtract 2x from each side

Question 1

What is standard/general form?

Answer 1

Ax+By=C

Question 2

How is standard form found when given two points and the slope?

Answer 2

(-4,3) m=-2
y-y1=m(x-x1) write point-slope form
y-3=-2[x-(-4)] substitute for y1, m, x
y-3=-2(x+4) simplify 
y-3=-2x-8 use distributive property
2x+y=-5 add 2x and 3 to each side

Question 3

What is linear interpolation?

Answer 3

A method of estimating the coordinates of a point that lies between two given data points

Question 4

What is linear extrapolation?

Answer 4

A method of estimating the coordinates of a point that lies to the right or left of all of the given data points

Question 5

More liner data is what?

Answer 5

Points that form something closer to a straight line

Question 6

What is slope-intercept form?

Answer 6

y=mx+b

Question 7

What are the m and b values in slope-intercept form?

Answer 7

m is the slope

b is the y-intercept

Question 8

Find the equation of a line that is parallel to the line y=1/2x+5 and passes through the point (2,-4)

Answer 8

y=1/2+5 (2,-4)
y=1/2x+b
-4=1/2(2)+b
-4=1+b
-1   -1
-5=b
y=1/2x-5

Question 9

Find the equation of a line that passes through the point (6,-5) and has a slope of -4

Answer 9

y=-4x+b
-5=-4(6)+b
-5=-24+b
\+24  +24
19=b 
y=-4x+19