Chapter 4.2: Applications of SFG Flashcards

1
Q

Whats the point of four wave SFG

A

Generate:
tunable freq
narrow bandwidth
in VUV region (100-200nm)

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2
Q

Why cant we use crystals in VUV gen and consquence of using other

A

Crystals absorb strongly in VUV (even if u indeed found one that had a X2 or X3)
need to use metal vapours or noble gasses
-isotropic
centrosymmetric -> lowest NL order is X3

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3
Q

energy diagram fo X3

A

X3(w3,w1,w1,w2)
2 photons of w1 and 1 photon of w2 annihilated
2w1 is on resonance

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4
Q

Origin on 4 wave SF mixing name

A

4 waves - 4photons interacting (2w1+w2 = w3)
SFG between w1 w2
2 photon resonance of 2w1

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5
Q

Exp challenge in 4 wave 2 photon resonance

A

To get X3 high for the desired SFG (2w1+w2) and low for the underired ones (2w2+w1) (2w2-w1), etc

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6
Q

3 main ways of exhancing only desired X3 and suppressing other X3

A

1) 2 photon mixing
2) incidnet laser polarisation (from coupled WE, prevents 3w1 resonance)
3) phase matching

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7
Q

Why choose a 2 photon rather than a 1 phtoon resonsance

A

1 photon res (here of w1 or w3) much more strongly attenuates I3 (or I1) than a 2 photon absorption due to resonance

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8
Q

When choose 2w1 2 photon resonance we can stil have other esonacne what are theya dn how can their X3 be reduced

A

3w1 and 2w1-w2 will also be resonant with the 2w1 resonance,
the 3w1 X3 is reduced by the incidentt circular polarisation of laser beam,

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9
Q

Explain how polarisation fo incident laser beams results in prohibition of 3w1 phton abs wigner eckart

A

Angular momentum selection rules
mu terms in deno are actually expectation vals of QM WF, iwth each mu(wi) haveing a delta mi acc wigner Ect thm
dm1+dm1+dm2 +dm3 = 0

where dm is the change in teh amgnetic quantum number associated with the electric dipole operator mu(wi)

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10
Q

what is allowed with wigner eckart

A

A photon cannot carry an angular momentum great than 1 so dm = +-1 only. since we had by wigner eckart from the mu’s
dm1+dm1+dm2+dm3=0
we can set dm1 as +1 (circ polarised input w1 beam)
to statify wigner eckart we must have dm2=dm3=-1 to balance out. so input w1 and w2 beams are polarised in opposite directions

X3(w3,w1,w1,w1) would have
dm1+dm1+dm1+dm3 = 0; but that required dm3=-3 which isnt allowed so this 3w1 third harm gen is prohibited

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