Chapter 3: The Periodic Table Flashcards

1
Q

Explain how elements in the periodic table are arranged

A

1) By increasing atomic number
2) By period (horizontal rows)
3) By group (vertical columns)
4) By metal/metalloid/non-metal
- Metal: Alkali metals, metals, transition metals
- Metalloids: have properties of both metals and non-metals (demarcated by ‘staircase’ boundary at B)
- Non-metals: halogens and noble gases

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2
Q

State the properties of a metal

A

Metallic structure: lattice of cations in a sea of delocalised electrons
- Metals: able to lose electrons easily (low ionisation energies) to form cations

  • Across a period: ionisation energies increase, elements lose electrons less readily (metals usually formed by elements on left side of periodic table)
  • Down a group: ionisation energies decrease, elements lose electrons more readily (metals usually formed by elements at the end of a group (eg. group 14)

METALS:
1) Large atomic radii
2) Low ionisation energies
3) Low (exothermic) electron affinity
4) Low electronegativity

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3
Q

Use position of element on periodic table to determine its electron configuration
(Eg. Sulfur: Period 3, Group 16)

A
  • Highest filled energy level: 3
  • Number of electrons at highest filled energy level: 6

3s²3p⁴

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4
Q

Explain trend in atomic radii
(down the group and across a period)

A

ATOMIC RADIUS: size of an atom (half the internuclear distance of a molecule of that element)

Determined by:
1) Nuclear charge: number of protons (creating “attractive force”)
2) Shielding effect: repulsion of valence electrons by inner electrons (number of “core” non-valence electrons)
3) Effective nuclear charge (nuclear charge - shielding effect)

Increases down a group:
- Atoms have more electron shells down a group
- Nuclear charge and shielding effect both increase, counteracting any effect caused by a greater number of protons

Decreases across a period:
- Nuclear charge increases (no. of protons increase)
- Shielding effect remains the same (no. of non-valence electrons remain the same)
- Effective nuclear charge increases (outer electrons are more strongly attracted to the nucleus)
- Atomic radii decreases

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5
Q

Explain trend in ionic radii (cationic and anionic radii relative to their atomic radii), and across an isoelectronic series

A

IONIC RADIUS: size of an ion

Cationic radii: smaller than its atomic radii
- Cations have fewer electron shells than their atoms
- Fewer electrons
- Less repulsion between electrons, valence electrons are more strongly attracted to the nucleus
- Smaller electron cloud

Anionic radii: larger than its atomic radii
- Constant nuclear charge
- More electrons
- More repulsion between electrons
- Larger electron cloud

Across isoelectronic series (Si⁴⁻, P³⁻, S²⁻, Cl⁻):
- Increase in nuclear charge
- Constant screening effect
- Increase in effective nuclear charge
- Valence electrons are more strongly attracted to nucleus
- Ionic radii decreases

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6
Q

Explain trends in first ionisation energy
(down the group and across a period)

A

FIRST IONISATION ENERGY: energy required to remove the outermost electron from a gaseous atom
M (g) –> M⁺ (g) + e⁻

Decreases down the group:
- Increase in atomic radius
- Valence electrons are less strongly attracted to the nucleus
- Less energy required to remove the outermost electron

Increases across a period:
- Increase in nuclear charge
- Constant screening effect
- Increase in effective nuclear charge
- Smaller atomic radius
- Valence electrons are more strongly attracted to the nucleus
- More energy required to remove the outermost electron

*Exception across Period 2:
1) Group 2 (Be) and Group 13 (B)
- B has a smaller AR, and is supposed to have higher IE. However, because the electron being removed from B is at the 2s sub-shell and the electron removed from Be is at the 2p sub-shell (higher energy level), B has a lower IE than Be

2) Group 15 (N) and Group 16 (O)
- O has a smaller AR and is supposed to have higher IE. However, because O has 2 paired electrons in the 2p-orbital generating interelectronic repulsion whereas N only has 1 electron
(2p³), O has a lower IE

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7
Q

Explain trends in electron affinity
(down the group and across a period)

A

ELECTRON AFFINITY: energy change when one electron is added to a gaseous atom
X (g) + e⁻ –> X⁻ (g)
- Usually exothermic for all elements: bond forming is exothermic

Decreases down a group:
- Increase in AR
- Electron will be less strongly attracted
- Releases less energy when electron is brought in
- Less exothermic

*Exception: Group 17
Cl has the most exothermic electron affinity (supposed to be F)
- However, due to the small size of the F atom, it generates large amounts of interelectronic repulsion, requiring more energy to attract an electron and releasing less energy

Increase across a period:
- Decrease in AR
- Electron will be more strongly attracted to nucleus when brought in
- Releases more energy
- More exothermic

*Exception: Period 3
- P (group 15) is supposed to have more exothermic electron affinity than Si (group 14)
- However, P has 3 electrons in 3 separate p-orbitals (3p³), which means that bringing in an extra electron would generate interelectronic repulsion, weakening the attraction between the nucleus and the electrons, making its electron affinity less exothermic

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8
Q

Explain trends in electronegativity
(down a group and across a period)

A

ELECTRONEGATIVITY: measure of the attraction of an atom in a molecule for the electron pair in the covalent bond of which it is a part

Decreases down a group:
- Increase in AR
- Increase in bonding distance between nucleus and electron pair
- Weaker attraction between electron pair and nucleus
- Decreased electronegativity

Increases across a period
- Decrease in AR
- Decrease in bonding distance between nucleus and electron pair
- Stronger attraction between nucleus and electron pair
- Increased electronegativity

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9
Q

State the properties and reactions of Group 1 metals (alkali metals)

A

All elements down a group:
- Similar chemical properties
- Gradation in physical properties

Group 1 metals:
- Metallic bonding: electrostatic attraction between the lattice of cations and the sea of delocalised electrons

Melting point decreases down the group:
- IR increases
- Nucleus is further away from delocalised electrons
- Weaker attractive force between nucleus and delocalised electrons
- Less energy required to break apart the lattice and overcome the IMFA between particles

REACTIONS:
- Alkali metals are all highly reactive:
1) With oxygen (to form an oxide)
2) With water (to form a base and hydrogen gas)

  • Get more reactive down the group: AR increases, IE decreases
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10
Q

State the properties and reactions of Group 17 elements (halogens)

A
  • Diatomic molecules
  • Bonding in halogens: covalent bonding (weak intermolecular forces of id-id) to form simple molecular structure

Boiling point increases down the group:
- Mᵣ increases
- London forces between molecules grow stronger
- More energy required to overcome them

Reactivity decreases down the group:
1) With alkali metals (to form salts)
2) With other halogens (displacement reaction)

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11
Q

State the different types of oxides and describe the changes in types of oxides across a period

A

OXIDES:
- Basic (react with water to form alkaline solutions IF SOLUBLE + react with acids to form salts)
- Acidic (react with water to form acidic solutions IF SOLUBLE + react with bases to form salts)
- Amphoteric (react with both acids and bases to form salts + does not react with water)
- Neutral

Across a period:
Basic (metallic oxides) –> Amphoteric (some metal oxides) –> Neutral (some non-metallic oxides) -> Acidic (non-metallic oxides)

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12
Q

Write the equations for the reactions of oxides with water and predict the acidity of the resulting solutions

A

Sodium oxide (Na₂O): Basic
Na₂O + H₂O –> 2 NaOH

Magnesium oxide (MgO): Basic
MgO + H₂O –> Mg(OH)₂

Aluminium oxide (Al₂O₃): Amphoteric
Al₂O₃ + 6H⁺ –> 2Al³⁺ + 3H₂O
Al₂O₃ + 2OH⁻ + 3H₂O –> 2Al(OH)₄⁻

Phosphorous pentoxide (P₄O₁₀): Acidic
P₄O₁₀ + 6 H₂O –> 4 H₃PO₄

Sulfur dioxide (SO₂)/sulfur trioxide (SO₃):
SO₂ + H₂O –> H₂SO₃
SO₃ + H₂O –> H₂SO₄

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