Chapter 3: Inner Products and Norms Flashcards

1
Q

Prove that || • || is a continuous function

A

See chapter 3 notes

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2
Q

Prove that:

1/sqr(n) || v ||<span>2</span> <= || v ||1 <= || v ||2

over V = R^n for any norms || ||1 and || ||2

A

See notes

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3
Q

Let V be a normed vector space and T be a linear operator on V. Prove that T is continuous at all points in V.

A

See notes

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4
Q

|| A ||_\infty is a natural matrix norm

A

True

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5
Q

A unit sphere in V is enough to compute the matrix norm

|| A ||

A

True

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6
Q

Prove that a narural matrix norm is finite.

A

Hint: unit sphere is finite and T is continuous.

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7
Q

Prove that:

|| Av || <= || A || || v ||

A

See notes

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8
Q

|| A B || <= || A || || B ||

A

True

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9
Q

|| A ||_\infty = maximal absolute column sum of A

A

False

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10
Q

|| A ||1 = maximal absolute columns sum of A

A

True

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11
Q

Let A ~ B, i.e.

S-1AS = B

Then ||A|| = ||B||.

A

False

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12
Q

Let ||A||F = 5, ||B||F= 6. Then ||AB||F can have which of the following values?

  • 30
  • 31
  • 32
  • 33
A

30

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13
Q

K is Positive Definite implies K is symmetric?

A

False. This is only true for Real matrices.

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14
Q

K PD implies K = conj (K^T)

A

True for all F

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15
Q

K = ((1 0), (0 -1)) defines an inner product

A

False. Only PD matrices define an inner product. K is indefinite

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16
Q

Can two distinct PD matrices K_1 and K_2 define the same inner product?

A

Yes. If K_1 and K_2 are the matrices of the same opetrator w.r.t. different bases

17
Q

K = ((1 0), (0 -1)) admits a null direction?

A

True. x = (a, a) is a null direction for all real a

18
Q

Every non-singular (invertible) matrix is P.D.

A

False

19
Q

Every P.D. Matrix is non-singular

A

True

20
Q

Suppose K is a real, non-singular, square matrix. Then (KT)-1 = (K-1)T ?

A

True

21
Q

K be a diagonal matrix with non-zero entries. Then K must be P.D.

A

False. e.g. K = ((1 0), (0 -1)) is not P.D.

22
Q

K is a diagonal matrix with positive entries, then K is P.D.

A

True

23
Q

K is a diagonal matrix which is P.D. Then K can have a zero entry.

A

False. That would make K non-invertible.

24
Q
A