Chapter 3 Flashcards

1
Q

What is an aqueous solution?

A

Solution for which water is the solvent

Aqueous solutions are commonly used in chemistry as they involve water as the primary solvent.

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2
Q

What is Avogadro’s number (NA)?

A

Experimentally determined value of the number of entities comprising 1 mole of a substance, equal to 6.022 × 10^23 mol−1

Avogadro’s number is fundamental in converting between moles and particles.

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3
Q

What does the term concentrated refer to in a solution?

A

Qualitative term for a solution containing solute at a relatively high concentration

Concentrated solutions have a higher ratio of solute to solvent.

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4
Q

Define concentration in the context of solutions.

A

Quantitative measure of the relative amounts of solute and solvent present in a solution

Concentration can be expressed in various units, including molarity and percent by volume.

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5
Q

What does dilute mean when describing a solution?

A

Qualitative term for a solution containing solute at a relatively low concentration

Dilution results in a lower concentration of solute in the solution.

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6
Q

What is dilution?

A

The process of adding solvent to a solution in order to lower the concentration of solutes

Dilution is commonly performed in laboratory settings to achieve desired concentrations.

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7
Q

What does dissolved mean?

A

Describes the process by which solute components are dispersed in a solvent

Dissolution is essential for creating solutions where solutes are uniformly distributed.

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8
Q

What is the empirical formula mass?

A

Sum of average atomic masses for all atoms represented in an empirical formula

The empirical formula represents the simplest whole-number ratio of elements in a compound.

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9
Q

What is formula mass?

A

Sum of the average masses for all atoms represented in a chemical formula; for covalent compounds, this is also the molecular mass

Formula mass is used to calculate the mass of a specified amount of a substance.

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10
Q

Define mass percentage.

A

Ratio of solute-to-solution mass expressed as a percentage

Mass percentage is commonly used in chemistry to express the concentration of a solution.

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11
Q

What is mass-volume percent?

A

Ratio of solute mass to solution volume, expressed as a percentage

This measure is particularly useful in solutions where the volume is relevant for the solute’s concentration.

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12
Q

What is molar mass?

A

Mass in grams of 1 mole of a substance

Molar mass is essential for converting between grams and moles in stoichiometric calculations.

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13
Q

What does molarity (M) represent?

A

Unit of concentration, defined as the number of moles of solute dissolved in 1 liter of solution

Molarity is a crucial concept in preparing solutions and performing dilutions.

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14
Q

What is a mole?

A

Amount of substance containing the same number of atoms, molecules, ions, or other entities as the number of atoms in exactly 12 grams of 12C

The mole is a fundamental unit in chemistry for quantifying entities at the atomic or molecular level.

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15
Q

Define solute.

A

Solution component present in a concentration less than that of the solvent

Solutes can be solids, liquids, or gases that are dissolved in solvents.

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16
Q

Define solvent.

A

Solution component present in a concentration that is higher relative to other components

The solvent is often the major component of a solution and determines the phase of the solution.

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17
Q

What is volume percentage?

A

Ratio of solute-to-solution volume expressed as a percentage

Volume percentage is useful for expressing concentrations of liquids in solutions.

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18
Q

What is percent composition?

A

Percentage by mass of the various elements in a compound

Used to determine the contribution of each element to the total mass of the compound.

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19
Q

What does the formula for an ionic compound NOT represent?

A

The formula for an ionic compound does not represent the composition of a discrete molecule.

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20
Q

Why might the term ‘molecular mass’ be incorrectly used for ionic compounds?

A

Because the average masses of neutral atoms were used in computation, rather than the masses for cations and anions.

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21
Q

Fill in the blank: The formula for an ionic compound may not be correctly referred to as the _______.

A

[molecular mass]

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22
Q

What is the molecular mass (amu) for Acetaminophen C8H9NO2?

A

151.16 amu

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23
Q

What is the formula mass (amu) of Calcium phosphate Ca3(PO4)2?

A

310.18 amu

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24
Q

What unit is used to express formula mass?

A

amu

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25
Q

What is the atomic mass unit (amu) equivalent to?

A

Molar mass (g/mol)

The atomic mass unit is a standard unit of mass that quantifies mass on an atomic or molecular scale, equivalent to one twelfth of the mass of an unbound neutral atom of carbon-12 in its nuclear and electronic ground state.

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26
Q

What is the estimated average of 4.7g potassium in moles?

A

0.12 moles

Calculation: 4.7 g x (1 mol K / 39.1 g K) = 0.12 mol K

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27
Q

How many moles of Be are in a 3.24 g thin-foil window?

A

0.360 mol Be

3.24 g x (1 mol Be / 9.01 g Be) = 0.360 mol Be

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28
Q

How is the molar amount of a substance calculated?

A

By dividing its mass (g) by its molar mass (g/mol)

Molar amount is a key concept in chemistry for quantifying substances.

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29
Q

What is the sequence for converting units from mass to atoms?

A

mass (grams) –> moles –> atoms (molecules)

This sequence is essential for stoichiometric calculations in chemistry.

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30
Q

To convert mass (grams) to moles, what operation is performed?

A

Divide mass (grams) by molar mass (g/mol)

Molar mass is specific to each substance and is typically expressed in grams per mole.

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31
Q

How do you convert moles to atoms (molecules)?

A

Multiply moles by Avogadro’s number

Avogadro’s number is approximately (6.022 imes 10^{23}) particles per mole.

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32
Q

What is the mass of argon in a liter of air 9.2 x 10^-4 mol Ar?

A

0.04 g Ar

9.2 x 10^-4 mol Ar x (39.95 g Ar / 1 mol Ar) = 0.04 g Ar

This is calculated based on the molar mass of argon and the amount in moles.

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33
Q

What is the mass of 2.561 mol of gold?

A

504.4 g

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34
Q

Calculate the number of Au atoms in a quantity of gold that weighs 15.00 g. What is the result?

A

4.586 × 10^22 Au atoms

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35
Q

How many copper atoms are in 5.00 g of copper wire?

A

4.74 x 10^22 atoms Cu

5.00 g (1 mol / 63.55 g ) (6.022 x 10^23 atoms / 1 mol) = 4.74 x 10^22

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36
Q

How many moles of glycine molecules are contained in 28.35 g of glycine C2H5O2N?

A

0.378 mol glycine

28.35 g (1 mol / 75.07 g) = 0.378 mol

Calculation of moles is based on the molar mass of glycine.

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37
Q

How many moles of sucrose, C12H22O11, are in a 25-g sample of sucrose?

A

0.073 mol

This is calculated using the molar mass of sucrose.

38
Q

Vitamin C is a covalent compound with the molecular formula C6H8O6. The recommended daily dietary allowance of vitamin C for children aged 4–8 years is 1.42 x 10^−4 mol. What is the mass of this allowance in grams?

A

0.0250 g

1.42 x 10^-4 mol (176.124 g / 1 mol) = 0.0250 g

39
Q

What is the mass of 0.443 mol of hydrazine, N2H4?

A

14.2 g

The mass is calculated using the molar mass of hydrazine.

40
Q

A packet of an artificial sweetener contains 40.0 mg of saccharin (C7H5NO3S). Given that saccharin has a molar mass of 183.18 g/mol, how many saccharin molecules are in a 40.0 mg (0.0400 g) sample of saccharin? How many carbon atoms are in the same sample?

A

1.31 x 10^20 C7H5NO3S molecules & 9.17 x 10^20 C atoms

0.0400 g (1 mol / 183.18 g) (6.022 x 10^23 / 1 mol) = 1.31 x 10^20
1.31 x 10^20 (7 C atoms / 1 C7H5NO3S molecule) = 9.17 x 10^20

41
Q

DELETE

42
Q

How many hydrogen atoms are in 9.213 g of C4H10?

A

9.545 × 10^23 atoms H

43
Q

What is the percent composition of a compound containing 7.34 g C, 1.85 g H, and 2.85 g N in a 12.04-g sample?

A

61.0% C, 15.4% H, 23.7% N

% C = (7.34 g / 12.04 g) x 100% = 61.0%
% H = (1.85 g / 12.04 g) x 100% = 15.4%
% N = (2.85 g / 12.04 g) x 100% = 23.7%

44
Q

Calculate the percent composition of a 24.81-g gaseous compound that contains 3.01 g C, 4.00 g O, and 17.81 g Cl.

A

12.1% C, 16.1% O, 71.79% Cl

The percent composition is calculated based on the mass of each element relative to the total mass of the sample.

45
Q

To calculate the percent composition, the masses of C, H, and O in a known mass of C9H8O4 are needed. It is convenient to consider 1 mol of C9H8O4 and use its molar mass (180.159 g/mole, determined from the chemical formula) to calculate the percentages of each of its elements:

A

60.00% C, 4.476% H, 35.52% O

% C = ((9 mol C x 12.01 g/mol) / 180.159 g/mol) x 100% = 60.00%
% H = ((8 mol H x 1.008 g/mol) / 180.159 g/mol) x 100% = 4.476%
% O = ((4 mol O x 16.00 g/mol) / 180.159 g/mol) x 100% = 35.52%

46
Q

To three significant digits, what is the mass percentage of iron in the compound Fe2O3?

47
Q

Empirical formulas are derived from experimentally measured element masses by what 3 steps?

A
  1. Deriving the number of moles of each element from its mass
  2. Dividing each element’s molar amount by the smallest molar amount to yield subscripts for a tentative empirical formula
  3. Multiplying all coefficients by an integer, if necessary, to ensure that the smallest whole-number ratio of subscripts is obtained
48
Q

A sample of the black mineral hematite, an oxide of iron found in many iron ores, contains 34.97 g of iron and 15.03 g of oxygen. What is the empirical formula of hematite?

A

The empirical formula is Fe2O3

Step 1:
34.97 g Fe (1 mol / 55.85 g) = 0.6261 mol Fe
15.03 g O (1 mol / 16.00 g) = 0.9394 mol O
Step 2:
0.6261 / 0.6261 = 1.000 mol Fe
0.9394 / 0.6261 = 1.500 mol O
Step 3:
2 (Fe1O1.5) = Fe2O3

49
Q

What is the empirical formula of a compound if a sample contains 0.130 g of nitrogen and 0.370 g of oxygen?

50
Q

What is the most convenient mass of elements to calculate when determining empirical formula from percent composition?

A

100 g

This is because the scale for percentages is 100, simplifying calculations.

51
Q

The bacterial fermentation of grain to produce ethanol forms a gas with a percent composition of 27.29% C
and 72.71% O. What is the empirical formula for this gas?

Step 1:
27.29% C = 27.29 g C / 100 g compound = 27.29 g C
72.71% O = 72.71 g O / 100 g compound = 72.71 g O
Step 2:
27.29 g C (1 mol/ 12.01 g) = 2.272 mol C
72.71 g O (1 mol/ 16.00 g) = 4.544 mol O
Step 3:
2.272 mol C / 2.272 = 1 mol C
5.544 mol O / 2.272 = 2 mol O

A

The empirical formula is CO2.

52
Q

What is the empirical formula of a compound containing 40.0% C, 6.71% H, and 53.28% O?

53
Q

Nicotine, an alkaloid in the nightshade family of plants that is mainly responsible for the addictive nature of cigarettes, contains 74.02% C, 8.710% H, and 17.27% N. If 40.57 g of nicotine contains 0.2500 mol nicotine, what is the molecular formula?

A

C10H14N2

Step 1:
Assume a convenient, a 100-g sample of nicotine yields the following molar amounts of its elements: 74.02 g C, 8.710 g H, 17.27 g N
Step 2:
74.02 g C (1 mol / 12.01 g) = 6.163 mol C
8.710 g H (1 mol / 1.01 g) = 8.624 mol H
17.27 g N (1 mol / 14.01 g) = 1.233 mol N
Step 3:
6.163 mol C / 1.233 = 5 mol C
8.624 mol H / 1.233 = 7 mol H
1.233 mol N / 1.233 = 1 mol N
C5H7N = 81.13 amu (empiricial forumla mass)
Step 4:
40.57 g nicotin / 0.2500 mol nicotine = 162.3 g/mol (molar mass)
Step 5:
162.3 g/mol / 81.13 amu = 2 formula units
Step 6:
2 (C5H7N) = C10H14N2

54
Q

What is the molecular formula of a compound with a percent composition of 49.47% C, 5.201% H, 28.84% N, and 16.48% O, and a molecular mass of 194.2 amu?

55
Q

What is the formula for molarity (M)?

A

Molarity (M) = mol solute divided by L solution

Molarity is a common unit of concentration in chemistry, indicating the number of moles of solute per liter of solution.

56
Q

A 355-mL soft drink sample contains 0.133 mol of sucrose (table sugar). What is the molar concentration of sucrose in the beverage?

A

0.375 M

Step 1:
Convert mL to L
355 mL (1 L / 1000 mL) = 0.355 L
Step 2:
0.133 mol / 0.355 L = 0.375 M

57
Q

A teaspoon of table sugar contains about 0.01 mol sucrose. What is the molarity of sucrose if a teaspoon of sugar has been dissolved in a cup of tea with a volume of 200 mL?

58
Q

How much sugar (mol) is contained in a modest sip (~10 mL) of the soft drink with a molarity of 0.375

A

0.004 mol sugar

Step 1:
Convert mL to L
10 mL (1 L / 1000 mL) = 0.01 L
Step 2:
mol solute = M x L solution
0.375 x 0.01 L = 0.004 mol sugar

59
Q

Distilled white vinegar is a solution of acetic acid, CH3CO2H, in water. A 0.500-L vinegar solution contains 25.2 g of acetic acid. What is the concentration of the acetic acid solution in units of molarity?

A

0.84 M acetic acid

Step 1:
Use molar mass of solute to obtain the amount of solute in moles
CH3CO2H = 60.052 g/mol (molar mass)
25.2 g (1 mol / 60.052 g) = 0.42 mol solute
Step 2:
M = mol solute / L solution
0.42 mol / 0.500 L = 0.84 M

60
Q

Calculate the molarity of 6.52 g of CoCl2 (128.9 g/mol) dissolved in an aqueous solution with a total volume of 75.0 mL.

61
Q

How many grams of NaCl are contained in 0.250 L of a 5.30-M solution?

A

77.4 g NaCl

Step 1:
mol solute = M x L
5.30 M x 0.250 L = 1.325 mol NaCl
Step 2:
Convert moles to mass (grams)
1.325 mol (58.44 g / 1 mol) = 77.4 g NaCl

62
Q

How many grams of CaCl2 (110.98 g/mol) are contained in 250.0 mL of a 0.200-M solution of calcium chloride?

A

5.55 g CaCl2

63
Q

The concentration of acetic acid in white vinegar was determined to be 0.839 M. What volume of vinegar contains 75.6 g of acetic acid (CH3CO2H)?

A

1.50 L solution

Step 1:
Find molar mass
CH3CO2H = 60.05 g
Step 2:
mass (grams) –> moles —> solution (L)
75.6 g (1 mol / 60.05 g) (1 L / 0.839 mol) = 1.50 L solution

64
Q

What volume of a 1.50-M KBr solution contains 66.0 g KBr?

65
Q

What is the first step in determining the volume of solution containing a given mass of solute?

A

Convert mass (grams) to moles

Use the molar mass of the solute for the conversion.

66
Q

After converting mass to moles, what is the next step in determining the volume of solution?

A

Convert moles to solution (L)

This typically involves using the molarity of the solution.

67
Q

Fill in the blank: To determine the volume of solution containing a given mass of solute, you go from _______ to moles to solution (L).

A

mass (grams)

68
Q

What is the formula that defines molarity?

A

n = M x L

Where n is the number of moles of solute, M is the molarity, and L is the volume in liters.

69
Q

In the formula n = M x L, what does ‘n’ represent?

A

The number of moles of solute.

70
Q

In the formula n = M x L, what does ‘M’ represent?

A

The molarity of the solution.

71
Q

In the formula n = M x L, what does ‘L’ represent?

A

The volume of the solution in liters.

72
Q

What is the dilution equation?

A

C1V1 = C2V2

73
Q

What unit of concentration does the dilution equation use?

74
Q

What unit of volume is used in the dilution equation?

75
Q

If 0.850 L of a 5.00-M solution of copper nitrate, Cu(NO3)2, is diluted to a volume of 1.80 L by the addition of water, what is the molarity of the diluted solution?

A

2.36 M

Step 1:
C1 = 0.850 L
V1 = 5.00 mol/L
C2 = ?
V2 = 1.80 L
Step 2:
C2 = (C1 x V1) / V2
C2 = (0.850 L x 5.00 mol/L) / 1.80 L = 2.36 M

76
Q

What is the concentration of the solution that results from diluting 25.0 mL of a 2.04-M solution of CH3OH to 500.0 mL?

A

0.102 M CH3OH

77
Q

What volume of 0.12 M HBr can be prepared from 11 mL (0.011 L) of 0.45 M HBr?

A

0.041 L

Step 1:
C1 = 0.45 M
V1 = 0.011 L
C2 = 0.12 M
V2 = ?
Step 2:
V2 = (C1 x V1) / C2
V2 = (0.45 M / 0.011 L) / 0.12 M = 0.041 L

78
Q

A laboratory experiment calls for 0.125 M HNO3. What volume of 0.125 M HNO3 can be prepared from 0.250 L of 1.88 M HNO3?

79
Q

What volume of 1.59 M KOH is required to prepare 5.00 L of 0.100 M KOH?

A

0.314 L

Step 1:
C1 = 1.59 M
V1 = ?
C2 = 0.100 M
V2 = 5.00 L
Step 2:
V1 = (C2 x V2) / C1
V1 = (0.100 M x 5.00 L) / 1.59 M = 0.314 L

80
Q

What volume of a 0.575-M solution of glucose, C6H12O6, can be prepared from 50.00 mL of a 3.00-M glucose solution?

81
Q

What is the formula for mass percentage?

A

Mass percentage = (mass of component / mass of solution) x 100%

This formula is used to calculate the concentration of a component in a solution.

82
Q

A 5.0-g sample of spinal fluid contains 3.75 mg (0.00375 g) of glucose. What is the percent by mass of glucose in spinal fluid?

A

0.075%

Step 1:
Convert mg to g
3.75 mg (1g / 1000 mg) = 0.00375 g
Step 2:
Mass percentage = (mass of component / mass of solution) x 100%
% glucose = (0.00375 g glucose / 5.0 g spinal fluid) x 100% = 0.075%

83
Q

A bottle of a tile cleanser contains 135 g of HCl and 775 g of water. What is the percent by mass of HCl in this cleanser?

84
Q

“Concentrated” hydrochloric acid is an aqueous solution of 37.2% HCl that is commonly used as a laboratory reagent. The density of this solution is 1.19 g/mL. What mass of HCl is contained in 0.500 L of this solution?

A

221 g HCl

Step 1:
Convert L to mL for proper cancellation
0.500 L (1000 mL / 1 L) = 500 mL
Step 2:
Volume of solution –> mass of solution —> mass of HCl
(multiply by density g/mL) (multiply by mass percent as ratio: g HCl / g solution)
500 mL solution (1.19 g solution / 1 mL solution) (37.2 g HCl / 100 g soltuion) = 221 g HCl

85
Q

What volume of concentrated HCl solution contains 125 g of HCl?

86
Q

What is the formula for volume percentage?

A

Volume percentage = (volume solute / volume solution) x 100%

This formula is used to express the concentration of a solute in a solution as a percentage of the total solution volume.

87
Q

Rubbing alcohol (isopropanol) is usually sold as a 70%vol aqueous solution. If the density of isopropyl alcohol is 0.785 g/mL, how many grams of isopropyl alcohol are present in a 355 mL bottle of rubbing alcohol?

A

195 g isopropyl alchol

Step 1:
Isopropanol volume is 70% of the total solution volume.
Multiplying the isopropanol volume by its density yields the requested mass: (70 mL isopropy alcohol / 100 mL solution) <– add this to the volume percentage equation
Step 2:
355 mL solution (70 mL isopropy alcohol / 100 mL solution) (0.785 g isopropyl alcohol / 1 mL isopropyl alcohol) = 195 g isopropyl alchol

88
Q

Wine is approximately 12% ethanol (CH3CH2OH) by volume. Ethanol has a molar mass of 46.06 g/mol and a density 0.789 g/mL. How many moles of ethanol are present in a 750-mL bottle of wine?

A

1.5 mol ethanol

89
Q

What does ppm stand for?

A

Parts per million

Used to express very dilute concentrations of substances.

90
Q

What is the formula for calculating parts per million (ppm)?

A

ppm = (mass solute / mass solution) x 10^6

This formula is used to determine the concentration of a solute in a solution.

91
Q

What does ppb stand for?

A

Parts per billion

Used to express extremely dilute concentrations of substances.

92
Q

What is the formula for calculating parts per billion (ppb)?

A

ppb = (mass solute / mass solution) x 10^9

This formula is used to determine the concentration of a solute in a solution at a billion parts.