Chapter 24 - Transition elements Flashcards

1
Q

What is the special case in writing the electron configurations for d-block elements?

A

a. The electron configurations of chromium and copper do not follow the expected principle for placing electrons singly in orbitals before pairing.
b. It is believed that a half-filled d5 sub-shell and a fully filled d10 sub-shell give additional stability to atoms of chromium and copper.
c. So, chromium has an electron configuration that ends in 3d54s1, whilst copper ends in 3d104s1.

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2
Q

How do we write the electron configurations of ions of d-block elements?

A

a. When forming an atom, the 4s orbital fills before the 3d orbitals.
b. When forming an ion, the 4s orbital empties before the 3d orbitals.

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3
Q

What is the definition of transition elements?

A

a. Transition elements are defined as d-block elements that form at least one ion with a partially filled d-orbital.
b. Although scandium and zinc are d-block elements, they do not match this definition and are not classified as transition elements.
c. Scandium only forms the ion Sc3+ by loss of two 4s electrons and one 3d electron and has an empty d orbital. d. Zinc only forms the Zn2+ ion by the loss of two 4s electrons and has a full d orbital.

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4
Q

What properties do transition metals have?

A

a. They form compounds in which the transition element has different oxidation states. i. For example, iron (II) chloride and iron (III) chloride.
b. They form coloured compounds. i. For example, Cr2O72- (Cr +6 oxidation state) is orange and Cr3+ is green (Cr +3 oxidation state).
c. The elements and their compounds can act as catalysts. i. For example, in the Haber process, the reaction between nitrogen and hydrogen is catalysed by a finely divided iron catalyst.

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5
Q

What is often the nature of a transition element in its highest oxidation state?

A

A species containing a transition element in its highest oxidation state is often a strong oxidising agent.

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6
Q

What is a catalyst?

A

a. A catalyst is a substance that increases the rate of a chemical reaction without itself changing. A catalyst works by providing an alternative reaction pathway with a lower activation energy.
b. A catalyst is left unchanged in the reaction.

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7
Q

What transition metal elements and compounds are used as catalysts?

A

a. Iron catalyst in the Haber process.
b. Vanadium (V) oxide in the contact process.
c. Nickel catalyst in the hydrogenation of vegetable fats in the manufacture of margarine.
d. Manganese (IV) oxide in the catalytic decomposition of hydrogen peroxide forming oxygen.
e. All of these are heterogeneous catalysts.

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8
Q

What is a heterogeneous catalyst?

A

It is a catalyst in a different physical state to the reactants.

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9
Q

What is a homogeneous catalyst?

A

It is where the catalyst is in the same physical state as the reactants.

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10
Q

What is a ligand?

A

A ligand is a molecule or ion that donates a pair of electrons to a central metal ion to form a coordinate bond or a dative covalent bond.

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11
Q

What is a dative covalent bond or a coordinate bond?

A

A dative covalent or coordinate bond is where one of the bonded atoms provides both of the electrons for the shared pair.

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12
Q

What is the coordination number?

A

The coordination number is the number of coordinate bonds attached to the central metal ion.

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13
Q

What is a monodentate ligand and give some examples.

A

a. A monodentate ligand is a ligand that is able to donate one pair of electrons to a central metal ion.
b. Such examples include H20, NH3, Cl-, CN- and OH-.

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14
Q

What is a bidentate ligand and what are the most common examples?

A

a. A bidentate ligand is a ligand that can donate two lone pairs of electrons to the central metal ion, forming two coordinate bonds.
b. The most common bidentate ligands are 1,2-diaminoethane (frequently shortened to en) and the ethanedioate (oxalate) ion:

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15
Q

What is the colour of [CoCl4]2- and [CuCl4]2- complexes and what is the shape of these complexes?

A

The colour of [CoCl4]2- is a deep blue solution.

The colour of [CuCl4]2- is a yellow solution.

These complexes are a tetrahedral shape.

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16
Q

When do square planar complex shapes occur?

A

A square planar shape occurs in complex ions of transition metals with eight d-electrons in the highest energy d-sub-shell.

Platinum (II), Palladium (II) and Gold (III) fall in this category and tend to form square planar complexes.

This is similar to the octahedral shapes but without the ligands above and below the plane.

17
Q

How do transition metal compounds show colours?

A

For a compound to have colour it must absorb visible light.

When a compound absorbs visible light, the colour seen is the sum of the remaining colours that are not absorbed.

If a compound absorbs all wavelengths of visible light, the compound will appear black.

If a compound absorbs the wavelengths of every colour except blue, the compound will appear blue.

18
Q

What is a stereoisomer?

A

Stereoisomers have the same structural formula but a different arrangement of atoms in space.

19
Q

What type of stereoisomerism can complex ions display?

A

Cis-trans isomerism

Optical isomerism

20
Q

What are the different combinations of number and type of ligands attached to central metal ion to show the respective stereoisomerism?

A

In four coordinate square planar complexes that have no more than 2 identical ligands attached to the central metal ion, show cis-trans isomerism.

In six coordinate octahedral complexes containing 4 of one type of ligand and 2 of another type of ligand, show cis-trans isomerism.

Octahedral complexes containing 2 bidentate ligands and 2 monodentate ligands, also show cis-trans isomerism.

Octahedral complexes containing 2 or more bidentate ligands, show optical isomerism. Trans-isomers cannot form optical isomers as a mirror image is exactly the same and can be superimposed.

21
Q

How does cis-platin work?

A

Cis-platin works by forming a platinum complex inside of a cell which binds to DNA and prevents the DNA of the cell from replicating.

Activation of the cell’s own repair mechanism eventually leads to apoptosis.

22
Q

Describe how ligand substitution occur within haemoglobin?

A

The central metal ion in a haem group is Fe2+ which can bind to oxygen gas.

As blood passes through the lungs, the haemoglobin bonds to oxygen because of the increased oxygen pressure in the capillaries of the lungs.

A compound called oxyhaemoglobin forms, which releases this oxygen to body cells as and when required. In addition, haemoglobin can bond to carbon dioxide, which is carried back to the lungs. Carbon dioxide is then released from the red blood cells and carbon dioxide is exhaled.

Carbon monoxide can also bind to the Fe2+ ion in haemoglobin. The complex formed is known as carboxyhaemoglobin.

If carbon monoxide is breathed in, a ligand substitution takes place where the oxygen is replaced by carbon monoxide. Carbon monoxide binds to haemoglobin more strongly than oxygen. The bond is so strong that the process is irreversible. If concentration of carboxyhaemoglobin becomes too high, oxygen transport is prevented, leading to death.

23
Q

How can you test for the presence of NH4+ ions?

A

When heated with hydroxide ions, NH4+ reacts to produce ammonia gas, NH3.

i. NH4+(aq) + OH-(aq) ==> NH3(g) + H20(l)

To test for ammonium ions, aqueous sodium hydroxide is heated gently with the solution being analysed. If ammonia is evolved, damp red pH indicator paper will turn blue, confirming the presence of NH4+ ions.

24
Q

What is a ligand substitution reaction?

A

A ligand substitution reaction is one in which one ligand in a complex ion is replaced by another ligand.

25
Q

What complex do you produce when copper (II) sulfate is added to water?

A

Hexa aqua copper 2+, [Cu(H20)6]2+, which is a pale blue complex.

26
Q

What is produced when excess ammonia is added to hexa aqua copper 2+ ion?

A

When excess ammonia is added, a dark blue solution forms. The complex is [Cu(NH3)4(H20)2]2+.

[Cu(H20)6]2+ + 4NH3 ==> [Cu(NH3)4(H20)2]2+ + 4H20.

27
Q

What is produced when NH3 (not in excess) is added to hexa aqua copper 2+?

A

Hexa aqua copper acts as a weak acid, and NH3 acts as a base. As NH3 is an alkali it reacts with the small amount of H+ ions from the weak acid.

This shifts the equilibrium to the right forming a pale blue precipitate of copper hydroxide.

[Cu(H20)4(OH2)] or Cu(OH)2

[Cu(H20)6]2+ + 2NH3 ==> [Cu(H20)4(OH2)] + 2NH4+.

28
Q

What is produced when an excess of Cl- ions is added to hexa aqua copper 2+ ion?

A

A tetrahedral yellow solution is formed, an intermediate green colour is also formed when Cl- ions are added dropwise due to the yellow and blue solution mixing.

[Cu(H20)6]2+ + 4Cl- <==> [CuCl4]2- + 6H20

Pale blue complex. Yellow solution

29
Q

What complex is formed when chromium (III) potassium sulfate is dissolved in water?

A

Chromium (III) potassium sulfate, KCr(SO4)2.12H20, also known as chrome alum, when dissolved in water forms a pale purple complex solution [Cr(H20)6]3+ is formed.

30
Q

What complex is formed when chromium (III) sulfate is dissolved in water?

A

The complex ion [Cr(H20)5SO4]+ is formed which is a green solution.

31
Q

What is formed when hexa aqua chromium 3+ is added to excess ammonia?

A

It forms the complex ion [Cr(NH3)6]3+.

When added dropwise, initially a grey-green precipitate of Cr(OH)3 is formed. This precipitate then dissolves in excess ammonia to form the complex ion [Cr(NH3)6]3+.

[Cr(H20)6]3+ + 6NH3 ==> [Cr(NH3)6]3+ + 6H20

Violet solution Purple solution

32
Q

What is the reaction of Cu2+ with sodium hydroxide?

A

Cu2+ + 2OH- ==> Cu(OH)2

blue solution blue precipitate

Insoluble in excess sodium hydroxide

33
Q

What is the reaction of Fe2+ with sodium hydroxide and what happens when exposed in air?

A

Fe2+ + 2OH- ==> Fe(OH)2

Pale green solution green precipitate

In air:

Fe(OH)2(s) ==> Fe(OH)3(s)

green precipitate orange-brown precipitate

Insoluble in excess sodium hydroxide

34
Q

What is the reaction of Fe3+ with sodium hydroxide?

A

Fe3+ + 3OH- ==> Fe(OH)3

Pale yellow solution orange-brown precipitate

Insoluble in excess sodium hydroxide

35
Q

What is the reaction of Mn2+ with sodium hydroxide?

A

Mn2+ + 2OH- ==> Mn(OH)2

Pale pink solution light-brown precipitate (darkens on standing air)

Insoluble in excess sodium hydroxide

36
Q

What is the reaction of Cr3+ with sodium hydroxide?

A

Cr3+ + 3OH- ==> Cr(OH)3

Violet solution grey-green precipitate

Soluble in excess sodium hydroxide:

Cr(OH)3 + 3OH- ==> [Cr(OH)6]3-

grey-green precipitate dark-green solution

37
Q

How does Fe2+, Fe3+ and Mn2+ react with excess ammonia?

A

Fe2+, Fe3+ and Mn2+ react with an excess of aqueous ammonia in the same way as they react with sodium hydroxide, forming precipitates of

Fe(OH)2 - green precipitate

Fe(OH)3 - orange-brown precipitate

Mn(OH)2 - light-brown precipitate

These precipitates do not further react with ammonia and do not dissolve