Chapter 2 part 2 Flashcards

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1
Q

What activates zygotic transcription of Hunchback?

A

Bicoid, therefor zygotic hunchback will be localized in the anterior portion of the embryo

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2
Q

Why is zygotic hunchback referred to as a master gap gene?

A

Because hunchback will collaborate with maternal genes to specify the expression of other gap genes.

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3
Q

Why are gap genes called gap genes?

A

Because their absence will leave fairly large gaps in the embryo. They specify wide regions.

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4
Q

It is said that the domain of gap gene expression overlaps with the domain of phenotypic expression. What does this mean?

A

It means that the area expressing the gene, is getting the phenotype from the gene. It is a direct cause and effect relationship.

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5
Q

What are denticles?

What are denticles used for?

A

Bands which are used as landmarks on the ventral surface the embryo. You can tell which regions disappear based on the disappearance of denticles.

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6
Q

Concentration of bicoid dictates the domain of hunchback expression. There therefor must be threshold. Given that bicoid is an activation of transcription of hunchback, do we see hunchback expression at concentrations above or below the concentration of the threshold.

A

We see expression of hunchback above the threshold. Hunchback will be seen above because the protein bicoid must either be a transcriptional activator of hunchback or activate a chain of events which activates hunchback.

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7
Q

How could you test to confirm that hunchback is indeed being set by bicoid concentration?

A

You could double bicoid amounts. You would expect and extension of the expression domain of hunchback. I could make a bicoidless mutant, I would expect no zygotic formation of hunchback, which I could test for with a beta galactosidase gene. However this would be controversial, as it is possible that bicoid expression is so important that the embryo would fail to develop to the point of hunchback expression. This however I doubt would completely override the validity of this study.

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8
Q

Kruppel forms a band within the center of the embryo, this band is specified by hunchback, which has a gradient from anterior to posterior. How can it specify a single band?

A

Hunchback is both an inhibitor and activator of kruppel. Hunchback inhibitory site must have a lower affinity then it’s activating site. It’s inhibitory site must also override thee activator. Therefore we would see that at high concentrations the weaker inhibitor site is bound too. As we go lower the poor site cannot adequately inhibit the translation of kruppel, as concentration drops further even the higher affinity binding site of the activator can no longer be activated at significant levels by it’s higher affinity binding site, and thus expression disappears. Walla! A band of kruppel expression set by a single gradient of hunchback (zygotic).

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9
Q

How could we check and confirm that hunchback is acting a both an activator and inhibitor of kruppel?

A

I could increase hunchback expression across the whole cell, which would result in the loss of kruppel. I could remove zygotic hunchback and expect to also see the loss of kruppel expression. I could create a environment were hunchback is expressed over a larger region at the level between its too regulatory sites, and I would expect to see activation of kruppel across that entire zone. I do not believe however that this proves that hunchback is not activating another pathway which is doing the regulation. But that’s ok I suppose. It would prove that kruppel expression is being solely regulated by hunchback expression.

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10
Q

Hunchback is a…

A

Transcription factor!

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11
Q

The embryo is divided into parasegments, how do these parasegments relate to the actual segments.

A

Parasegments are spaced exactly one half segment out of phase from the actual segments which will form. Parasegments are aligning with pair in rule expression.

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12
Q

Eve (even-skipped) and Ftz (fushi tarazu) are pair in rule genes. They form segments which can be seen 2.7 hrs after fertilization. The same segments will have sharpened by 3.5 hours after fertilization. What allows for this sharpening of expression of eve and ftz?

A

Eve expression activates eve (positive feedback), amplifying it’s own expression, eve also inhibits ftz expression.
Ftz expression meanwhile is activating Ftz, positive feedback, and inhibiting expression of even-skipped. So we have a war between pair in rule genes which sharpens their band formation

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13
Q

How is expression of different stripes of Eve or Ftz achieved on the level of gene expression?

A

Each stripe is activated individually, they each have their own regulatory activating gene (identified by insertion of beta-galactosidase expression in the gene. Each one will have it’s own unique combination of activators and repressor to trigger expression.

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14
Q

Eve stripe 2 is a classic example of how this is achieved. Explain the regulation on eve stripe two.

A

Bicoid and hunchback are activators (so it is an anterior located stripe), Kruppel is an inhibitor, therefor stripe two cannot appear in the middle. Giant is also an inhibitor, and it is present anterior to eve 2 stripe. Therefor we see a single stripe, located posterior to giant, anterior to kruppel and where we see both bicoid and hunchback expression.

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15
Q

How could we experimentally show that each part of even stripe two regulation works as supposed?

A

Knock out of individual pieces. For example, if I knocked out giant, I would expect stripe two to try to extend further anterior, as its inhibitor is gone. This would however mean that its expression domain would overlap with ftz, a known inhibitor, so it is debatable whether expression would be seen as expected.

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16
Q

Where are segmentation genes expressed?

A

They are expressed in segments of the parasegments created by pair in rule genes. Further dividing them, and showing were we are at in the parasegment.

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17
Q

Syncytial define:

A

Multinucleated single cell.

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18
Q

Segmentation genes are not expressed in a syncytial manner, what does that mean?

A

It means that the expression occurs on an individual cell basis. Specification does not occur during the early embryo, but later in development based off of cell to cell communication.

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19
Q

What is included within a single parasegment in terms of expression domains of pair in rule genes.

A

A single parasegment would start at the cells expressing even skipped and end right before the cells expressing ftz. The next parasegment would start at the cells expressing ftz and end right before the cells expressing eve.

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20
Q

Segmentation genes:
Engrailed, hedgehog are expressed in the anterior portion of every segment, wingless is expressed in the posterior portion of every parasegment. What is the important part of this?

A

It shows that segmentation genes will be expressed on the same boundary lines of each parasegment regardless of Eve, or Ftz is signalling the existance of the parasegment. This also means that a cell can use engrailed, to know it is in the anterior of the parasegment, it can use bicoid, or hunchback to figure out how far anterior it is overall. Therefore we can create similirities between parasegment one and two as well as differences based on anterior and posterior presentation.

21
Q

Where is expression of eve and ftz highest? In the anterior or posterior portion of their parasegment?

A

Anterior portion of the parasegment, fading as they approach the posterior portion of their parasegment.

22
Q

How does the gradient of pair in rule genes expression help specify the segment genes expression domains?

A

Since we have the highest level of expression in the anterior regions, anterior activated segmentation genes, such as engrailed and hedgehog can be activated by Eve or Ftz. Wingless which is activate in the posterior of parasegments may be being inhibited by eve and ftz expression, and therefore only seen where the expression of pair rule genes is at its lowest.

23
Q

Where in the parasegment is engrailed expressed?
Hedgehog?
Wingless?

A

Anterior
Anterior
Posterior

24
Q

We know where engrailed lies in the parasegment (the anterior son) but in the segment engrailed lies posterior, why is this?

A

Because engrailed is setting the anterior boundary for the segment. The segment cannot go farther anterior then the site of engrailed expression. Engrailed is likely causing a specific form of adhesin protein, therefore cells in engrailed bind together and cells with poor adhesion to engrailed expressing cells cannot slide into the segment.

25
Q

Engrailed sets a compartmental boundary. Given what you know about segment boundaries and engrailed, what must a compartmental boundary be?

A

I know that engrailed sets the anterior limit of a segment. Cells from the posterior segment cannot cross the line of engrailed expressing cells. I also know that the reason these cells cannot cross must be due to the use of different adhesion molecules in engrailed expressing cells. Therefor I know that a compartmental boundary must be an invisible wall (except through staining) which cells from different lineages cannot cross over. A cell from the posterior region will not possess the addhesins to cross into engrailed expressing cells, and similarly engrailed cells will have little or no favorable interactions with cells posterior to them. Since daughter cells will have the same expression, we do not see any crossing of daughter cells into the less favorable environment.

26
Q

Wings develop on an imaginal disc straddling a boundary between compartmental boundaries. Loss of engrailed or wingless results in disrupted compartment boundaries and poor wing formation. What does this necessarily mean?

A

It means that both engrailed and wingless must be involved in creation of the compartmental boundary. Engrailed role is known. let’s check out winglessess expression domain.

27
Q

Do compartmental boundaries match anatomical boundaries?

A

No, they do not necessarily do that.

28
Q

Wingless (wint), engrailed and hedgehog all go together how?

A

Hedgehog is a ligand activated by the transcription factor engrailed. Wingless is a ligand. Wingless and Hedgehog maintain each others expression. This strengthens the boundaries of parasegment.

29
Q

Interactions between the ligands of hedgehog (stimulated by engrailed transcription factors) and wingless help to set the parasegment boundaries how? How does this help engrailed to maintain the segment boundaries?

A

Hedgehog stimulates production of wingless, wingless stimulates production of hedgehog (likely via increasing engrailed expression), engrailed expression causes production of an adhesion molecule specific to engrailed expressing cells. Thus, even though wingless and hedgehog are keeping a well defined parasegment line, they are also defining the segment line, because they are keeping engrailed expression constant and linear, and engrailed expression is key to maintaining compartmental boundaries of the segments. So a strongly maintained segment line provides a clean line to mark the anterior limit of a segment (Engrailed is posterior most in a segment, anterior most in a parasegment).

30
Q

Hedgehog is a morphogen and a ______.

A

Ligand.

Hedgehog is a morphogen and ligand.

31
Q

In Wnt signalling pathway, what occurs if the Wnt ligand is not bound too the receptor?

A

If Wnt is not bound to the receptor, then a complex of proteins will phosphorylate the transcription factor beta-catenin, marking it for destruction., therefore we will not have transcription of the genes regulated by beta-catenin

32
Q

If Wint is bound to its receptor what occurs in terms of intracellular signalling changes?

A

If Wnt is bound to its receptor, there is a morphological change causing the receptor to phosphorylate itself, bind to dishevelled and, bind to the proteins which are involved in phosphorylating beta-catenin for destruction. Since each receptor binds to one set of proteins responsible for the marking of beta-catenin for degredation, there will be a one to one stoichiometric inverse relationship between Wnt bound receptors and degredation of beta-catenin. It is therefore possible to cause a gradient response to Wnt, where the cell may destroy, all, none or half of its beta catenin based on the amount of receptors bound to wnt and the prevalence of these receptors in the cell.

33
Q

Segment gene expression is still seen in the adult, how does this differ from the genes mentioned prior to this point?

A

All genes mentioned prior to this point will be deactivated in the adult. They are only used in setting developmental axis.

34
Q

What are homeotic selector genes also called

A

Homeotic selector genes = HOX genes

35
Q

What does the homeotic selector (HOX) genes do?

A

They are activated by combinations of GAP genes, Pair in rule genes, segmentation genes, and that’s it, to specify exactly where in the animal we are, the hox gene activated is the specific limb, or specific body part that should be formed in that region.

36
Q

Define homeosis:

A

Homeosis is the transformation of one structure, into a related one. For example, the flies have something called a haltere, a haltere is used in balancing of the fly when it flies, this can be mutated into a wing by transplanting the hox genes into the same location

37
Q

In the example involving a haltere, it is also possible, and indeed easier, to produce a halfwing half haltere. Why is that?

A

This is easier because their is a segmental boundary occurring between these points, so if you do mutant a single homeotic selector gene, then you have only changed one half of the haltere into a wing.

38
Q

ectopic:

A

In the wrong/different place.

39
Q

How are hox genes/homeotic selector genes arranged on the chromosome?

A

They are arranged on the same chromosome, in order from anterior to posterior. The fly has a chromosomal split which has occurred recently separating these genes, but this is the exception not the norm, and the split separates them at a single point only.

40
Q

Why do legs appear where antenna should on the gain of function homeotic mutation causing this to happen?

A

This occurs because there is a chromosomal inversion, which places the promoter for antenna under the promoter for legs. Ant expression is seen normally only in the legs, if seen on the antenna, it will form a leg here.

41
Q

Protein binding domain refers to?

A

A domain designates an area on the protein, therefor a protein binding domain is a structural region on a protein which binds to a specific domain.

42
Q

All hox genes encodes for proteins which are?

A

Homeodomain transcription factors.

43
Q

Hox genes are found on all animals which are bilaterans, what is a bilateran?

A

A bilateran is an animal with bilateral symmetry.

44
Q

The order of hox genes is necessary.

A

The disruption of this order will lead to different expression.

45
Q

What does ultrathorax specify?

A

Ultrathorzx specifies T3 by itself, it also specifies abdominal segments A1 as a baseline.

46
Q

What does abdominal A do?

A

Abdominal A expression starts in A2, and specifies A2 down to about A4 with ultrathorax. Working with abdominal B it will specify A4 -> A8

47
Q

Morale: what do hox genes do?

A

Hox genes overlap to specify specific domains. The regions in which one is highly expressed represent the region specified by that specific signal. Regions which multiple are expressed in use combinatorial levels of the two in order to designate the regions

48
Q

Abdominal B runs:

A

Starting at Abdominal 8 and strengthening weakening in expression as it runs towards anterior

49
Q

What specifies the head?

A

Three non hox genes.