Chapter 2 - Localization Flashcards

1
Q

Define: local ring

A

A ring with just one maximal ideal

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2
Q

Discuss motivation for localization

A

See pg. 57-58

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3
Q

Define: multiplicatively closed set

A

A set U is multiplicatively closed if any product of elements in U is in U and 1 is in U

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4
Q

Define: localization of M at U

A

pg. 59 and Borcherds pg 115 - …

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5
Q

When does an element localize to 0? Proof?

A

An element m in M goes to 0 in M[U^-1] iff m is annihilated by an element u in U

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6
Q

Examples of localizations?

A
  1. Quotient field of integral domain
  2. Total quotient ring of arbitrary ring
  3. For P prime localization at R - P written R_P - write k(P) for the residue class field of R at P
  4. Local ring of an affine variety X at a point x in X
  5. Z and C[x] Borcherds
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7
Q

What is the localization of a map of R-modules? Functorial properties?

A

If f: M -> N is a map of R-modules, then there exists a map of R[U^-1]-modules f[U^-1]: M[U^-1] -> N[U^-1] that takes m/u to f(m)/u - called the localization of f. Makes localization into a functor from the category of R-modules to the category of R[U^-1] -modules.pg. 60

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8
Q

Discuss the universal property of localization

A

If f: R -> S is any ring hom with elements in U going to units, then there is a unique extension to a hom f’:R[U^-1] ->S. Pg. 60

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9
Q

Discuss the relationship between the ideal structure of R and its localization R[S^-1]. Spec R vs Spec R[S^-1]

A

See Borchards Lecture 17 and Prop 2.2 in Eisenbud

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10
Q

Discuss Spec C[x,y] localize at (0), (f), (x-a, y-b) vs quotient

A

See Borchards Lecture 17

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11
Q

Discuss C[x,y]/(xy) localized at (x,y)

A

See Borchards Lecture 17

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12
Q

Discuss functions on Spec R for R = C(X) continuous functions on compact Hausdorff space, R = C[x], R = Z

A

See Borchards Lecture 18

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13
Q

Why do nilpotents cause issues with trying to represent R as functions on Spec R? Solution? Examples?

A

See Borchards Lecture 18
Destroy injectivity. See Borchards Lecture 18
Discuss Nilradical. Instead of f: Spec R –> R/P do f: Spec R –> Rp (local ring at P)

Try C[x], Z with local rings

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14
Q

Define: Sheaf of rings on Spec R

A

See Borchards Lecture 18

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15
Q

What is the motivation for def of Affine Scheme of RIng?

A

Pretend R is a ring of functions on Spec R

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16
Q

Define: Affine Scheme of Ring

A

See Borchards Lecture 19

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17
Q

Discuss the algebra geometry dictionary

A

See Borchards Lecture 19

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18
Q

Define: tensor product of modules over a ring

A

Defined in terms if universal property i.e. universal module for bilinear maps from MxN. See Borchards Lecture 20.

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19
Q

Prove existence and uniqueness of tensor product

A
  1. Unique using universal
  2. Existence using massive free module construction

See Borchards Lecture 20.

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20
Q

Examples of tensor product - vector space and f.g. abelian groups-Z-modules?

Approach?

A

The def and construction is hard to compute with. Use 2 properties:

  1. (M1 + M2) x N = M1xN + M2xN
  2. R x_R M = M

Borcherds lec20

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21
Q

What problems can occur when taking tensor or hom of s.e.s.?

A

No problems if working over a field.

Otherwise lists 3 problems all using same s.e.s. 0–>Z–>Z–>Z–>0 where the second map is x2. Universal counterexample to everything

See Borchards Lecture 21.

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22
Q

Define: Hom_R(M,N)

A

If M and N R-modules, this is the abelian group of all homomorphisms from M to N. Actually an R-module

23
Q

Prove: Hom_R(R,N) isomorphic to N

24
Q

In what sense is Hom functorial? Left-exact functor? Right-exact?

A

pg 62-63 Borcherds Lec 21

25
Q

What is the relationship between Hom and tensor? Discuss properties of tensor in this context

26
Q

In what sense is tensor product functorial? Impact on s.e.s?

A

Pg 64-65 borcherds 21

27
Q

How can you calculate tensor product?

A

Borcherds 21

28
Q

What are direct limits? Impact of tensor product?

A

End of Borcherds 21

29
Q

Define: Flat module

A

M is flat if M tensor preserves exactness

Lec 22
66

30
Q

Prove: localization M[S^-1] preserves exactness.

A

Lecture 22

66

31
Q

What is M_p? Stalk? How to think about?

32
Q

Show R[S^-1] is flat over R

33
Q

Show vanishing is local

34
Q

Show exactness is local

35
Q

Show flatness is local

36
Q

How can you describe localization of module in terms of tensor product? Proof?

37
Q

Define: support of M

A

Supp M - the set of prime ideals st M_p != 0

38
Q

Exercise 2.1

39
Q

Exercise 2.4

40
Q

Exercise 2.6

41
Q

Exercise 2.19

42
Q

Exercise 2.20

43
Q

Given an extension S of R, discuss the relationship between R-modules and S-modules. What does this have to do with localization?

A

Given an S-module, easily get and R-module by restricting ring action. Given R-module, can induce an S-module by tensoring with S over R. B lecture 23. Pg 69

44
Q

Prove Hom_S(S (x) M, S (x) N) = S (x) Hom_R(M,N) if S is FLAT R-module

A

B163-166

Include proof of 5-lemma

See also pg69

45
Q

Prove: If R is any commutative ring, U < R a multiplicatively closed subset, and I < R an ideal maximal among those not meeting U, then I is prime. Corollaries?

A

It is a surprisingly general phenomenon that ideals maximal with respect to some property are prime

Pf. If f, g in R are not in I, then, by the maximality of I, both I + (f) and I + (g) meet U…pg71

Also do proof in terms of localization

Corollary. If I is an ideal in R, then rad I = intersection of all primes containing I. In particular, the intersection of all primes is the radical of (0), which is the set of all nilpotent elements of R.

46
Q

Define: Artinian ring/module, chain of submodules, composition series, length of module, module of finite length

A
  1. Descending chain condition on ideal/submodules
  2. Every set of ideals/submodules has a minimal element

If M is a module, a CHAIN of submodules of M is a sequence of submodules with strict inclusions:
M = M0 > M1 > … > Mn

Such a chain is said to have LENGTH n. The chain is sub a COMPOSITION SERIES if each Mj/Mj+1 is a nonzero simple module (ie. has no nonzero proper modules)

The LENGTH of M is the least length of a composition series for M or inf if M has no finite composition series.

47
Q

Examples displaying the relationship between Artinian and Noetherian modules?

A
1. Artinian and Noetherian
0, Z/nZ (over Z), any module with FINITE number of elements. Any f.d. vector space over a field
  1. Noetherian, not Artinian
    Z (over Z) Z > 2Z > 4Z > …
    Z_(2) = {a/b : b odd}
  2. Neither
    Q over Z … > 1/4 Z > 1/2 Z > Z > 2Z > 4Z > …
  3. Artinian NOT Noetherian
    Z[1/2]/Z
48
Q

Examples displaying the relationship between Artinian and Noetherian rings?

A

Noetherian, not Artinian
Z

Neither
Z[x1, x2, …}

Artinian and Noetherian

49
Q

Discuss (with proof) the relationship between modules of finite length and Artinian, Noetherian conditions

A

Thm. Let R be a ring, and let M be an R-module. M has a finite composition series <=> M is Artinian and Noetherian.

If M has a finite composition series M = M0 > M1 > … > Mn = 0 of length n, then:

a. Every chain of submodules of M has length <= n, and can be refined to a composition series

b. The sum of the localization maps M --> M_p, for P a prime ideal, gives an isomorphism of R-modules
M = (+) M_p where the sum is taken over all maximal ideals P s.t. some Mi/Mi+1 = R/P. The number of Mi/Mi+1 isomorphic to R/P is the length of Mp as a module over Rp, and thus independent of the composition series chosen

c. We have M = Mp <=> M is annihilated by some power of P.

Pf pg 72-74

50
Q

What conditions are equivalent to R being an Artinian ring? Proof?

A
  1. R is Noetherian and all all the prime ideals of R are maximal

    Pg 75
51
Q

Say A(X) is the coordinate algebra of an affine algebraic set and A(X) is Artinian. Discuss what this implies about the set

A

The following are equivalent:
1. X is finite

  1. A(X) is a f.d. vector space over k, whose dimension is the number of points of X
  2. A(X) is Artinian

pg 76

52
Q

Structure theorem for Artinian rings?

A

Any Artinian ring is a finite direct product of local Artinian rings.

Pf. This is essentially the same as (b) from our main theorem 2.13 about properties of modules of finite length. We just recognize that R has finite length as an R-module over itself and then show that the isomorphism of R with a product of local modules is actually a ring isomorphism

53
Q

Characterize modules of finite length over Noetherian rings

A

Cor. 2.17
Let R be a Noetherian ring, and let M be finitely generated R-module. TFAE:
1. M has finite length
2. Some finite product of maximal ideals annihilates M
3. All the primes that contain the annihilator of M are maximal
4. R / ann(M) is an Artinian ring

Combine this with Theorem 2.13
Let R be a ring and M an R-module. M has finite length (finite composition series) <=> M is Artinian and Noetherian.
1. Every chain of submodules has length <= length n and can be refined to composition series
2. M = (+) Mp where the sum is taken over all maximal ideals P s.t. some Mi/Mi+1 = R/P
3. M = Mp <=> M is annihilated by some power of P.

54
Q

How can we turn a finitely generated module into a module of finite length via localization?

A

Every f.g. module M over a Noetherian ring R can be made into a module of finite length by localization at a prime minimal over its annihilator.

Prop. Let R be a Noetherian ring, 0 != M a f.g. R-module, I the annihilator of M, and P a prime ideal containing I. The Rp-module Mp is a nonzero module of finite length <=> P is minimal among primes containing I.