Chapter 2 (Input/Output, Domain/Range, Piecewise, Inverses, Concavity) Flashcards
Sketch a function that is constant over the domain {-3 ≤ x≤ 2}
This will be a horizontal segment drawn from x = -3 to x = 2.
If H is a function of W, which is the input?
W is the input (and the independent variable)
Imagine a table of values for two variables, x and y, and two ordered pairs are (2, 4) and (2, 6). Can y be a function of x?
NO. There are two different outputs (y’s) for the same input (x = 2).
If T(w) = 3w +5, T(h) = 14 and d = h – 2, find d.
d = 1. First, solve T(w) for when T(h) = 14. This gives h = 3. Then subtract 2 to get d = 1.
If N(t) = 10 + 2t, find N(g).
10 + 2g
If T(y) = 8y – 5, find T(n + 3)
8(n + 3) – 5 = 8n + 24 – 5 = 8n + 19
Describe the domain of any quadratic function.
{all reals}
Describe the range of any quadratic function.
It will be either be {all reals ≤ Y} or {all reals ≤ Y}, where Y is the y-coordinate of the vertex of the parabola.
What is the domain of y = (x + 5) ÷ (x – 3) ?
{all reals ≠ 3}
What is the one exception in the range of f(x) = 2x ÷ (x – 3) ?
2 (i.e. the output, y, will never be 2)
What is the domain of g(x) = √(x + 6) ?
{all reals ≥ -6}
Assume your oxygen intake is a function of your heart rate. What would be a reasonable domain for this function?
INTEGERS between 50 and 140.
Given this piecewise function, find f(1).
2x + 6 for {0 ≤ x ≤ 2}
f(x) = -6 for {2 < x < 5}
12 – 4x for {5 ≤ x ≤ 8}
f(1) = 2(1) + 6 = 8 (Hint: the correct formula depends upon which domain your input falls)
Given this piecewise function, find f(5).
2x + 6 for {0 ≤ x ≤ 2}
f(x) = -6 for {2 < x < 5}
12 – 4x for {5 ≤ x ≤ 8}
f((5) = 12 – 4(5) = 12 – 20 = -8 (Hint: the correct formula depends upon which domain your input falls)
Given this piecewise function, find f(9).
2x + 6 for {0 ≤ x ≤ 2}
f(x) = -6 for {2 < x < 5}
12 – 4x for {5 ≤ x ≤ 8}
Undefined. The input 9 does not fall into any of the given domains.