Chapter 2 Flashcards

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0
Q

Current, I =

3

A

1) charge/time
Q/t
2) number of ions arriving per second x charge on ion
Nq
3) electron density x charge on 1 electron x average drift velocity x area
nevA

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1
Q

Potential difference

A

Made by uneven distribution of charge. Difference in potential energy of a charge going between those places, per unit charge. Anywhere there is a change in energy V, volts V

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2
Q

Potential difference, V =

A

Energy/charge

E/Q

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3
Q

Power

A

Rate of delivery of energy, P, watt W

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4
Q

Current

A

Rate of flow of charge, Q, amperes A

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5
Q

Power =

4

A

1) IV (current x p.d.)
2) I^2 R (using V=IR)
3) V^2/R (using I=V/R
4) E/t (energy over time)

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6
Q

Charge on an electron/singly charged ion (magnitude)

A

1.6x10^-19 C, e

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7
Q

Conductance, G =

A

current/potential difference

I/V

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8
Q

Conductance

A

Measure of how much currency flows for a given p.d. G, Siemens S

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9
Q

Resistance

A

How badly things conduct. NOT fighting back! Lack charge carriers which can move. How much current is lost in a circuit. Takes energy away from electrons. R, ohms

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10
Q

Resistance, R =

2

A

1) p.d./current (V/I)

2) 1/conductance (1/G)

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11
Q

Ohm’s law

A

Relates current through a conductor to p.d. States current is proportional to p.d. providing other physical conditions remain constant (e.g. heat).

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12
Q

Series circuits

A
  • current is constant

* Rt = R(1) + R(2)

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13
Q

EMF

A

Stands for electromotive force - misnomer! Where electrons gain potential difference (in the source). Energy given to each unit charge - not all in circuit due to internal resistance!

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14
Q

Kilowatt hour

A
1000W for 1hr.
1000Js^-1 for 1hr
1000Js^-1 for (60 x 60)
1000Js^-1 for 3600s
3.6MJ
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15
Q

Parallel circuits

A
  • 1/Rt = 1/R(1) + 1/R(2)

* p.d is the same across each branch

16
Q

EMF (funny E) =

A

1) V(R) + V(r)
2) I(R + r) –> deduced using V=IR
3) electrical potential energy gained in other forms/unit charged

17
Q

Terminal potential difference

A

V(c) = V(R) p.d across the cell - not EMF, as doesn’t take into account V(r)

18
Q

Working out EMF and internal resistance

A

• rearrange EMF = I(R + r) to
EMF = V(c) + Ir (expanding, V=IR)
• rearrange that to V(c) = -Ir + EMF
• find values, plot graph of V(c) on y axis, I on x axis.
• gradient is -internal resistance; EMF is y intercept

19
Q

Potential divider equation

A
  • V(1) = R(1)/R(1)+R(2) x V(c)

* for resistors in series - unravel parallel resistors first!