Chapter 14 concepts Flashcards

1
Q

Diluted Alcohols

A

Because they lack hydrogen bonding, they will have a sharper absorption

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2
Q

Symmetry

A

No change in bond dipole, no bond dipole

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3
Q

Ester vs ketone

A

Ketone’s sp3 CH has a higher wave number

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4
Q

vinylic ch

A

3100

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5
Q

why 2 signals for 12 sp3?

A

symmetric and asymmetric

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6
Q

degenerate

A

same energy level

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7
Q

hydrogen bond

A

dipole dipole

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8
Q

protic

A

one h bond to electronegative atom

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9
Q

frequency is directly proportional to

A

energy

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10
Q

frequency is inversely proportional to

A

wavelength

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11
Q

wavelength is inversely proportional to

A

energy

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12
Q

electromagnetic spectrum

A

gamma, x, uv, visible, ir, microwave, radio

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13
Q

radio

A

highest wavelength

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14
Q

gamma

A

highest frequency

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15
Q

ir tells you

A

functional groups

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16
Q

mr tells you

A

arrangement of c and h

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17
Q

uv vis spectroscopy

A

conjugated pi bond

18
Q

absorption of ir results in

A

vibrational excitement of the bonds in a compound, stretching and bending

19
Q

location of signal

A

wavenumber

20
Q

warm objects

A

emit more ir

21
Q

wavenumber unit

22
Q

stretching virbration

A

directly proportion to strength, inversely proportional to reduced mass

23
Q

vibration must result in

A

change of bond dipole

24
Q

primary amines have

A

symmetrical and asymmetrical stretching

25
Molecular ion
positively charged ion produced by ionization technique
26
base peak corresponds to
must abundant ion
27
molecular ion is produced by
loss of one electron
28
whats produced when a compound is bombarded with high energy electrons
radical cations
29
mass spectrometry would be used to determine
molecular formula and weight
30
OH
3200-3600
31
Carboxylic Acid
2200-3600, 1650-2000
32
sp
3300
33
Amine
3350-3500
34
sp2
3000-3100 3000-3100
35
sp3
2850-3000
36
Aldehyde
2750-2800
37
Ketone
1650-1820
38
C=C
1600-1700
39
C≡C
2100-2200
40