Chapter 1 Flashcards
Describe errors that may cause an observed capillary melting point of a pure sample to be LOWER than the correct melting point.
- Heating the sample too quickly (lag between real temperature and what thermometer reads)
- Using an uncalibrated thermometer
- Measuring a sample with an impurity
- Measuring a wet sample
Describe errors that may cause an observed capillary melting point of a pure sample to be HIGHER than the correct melting point.
- Using too large a sample size
- Packing a sample too loosely in the capillary tube
- Using an uncalibrated thermometer
- Measuring a sample with significant quantities of an impurity with much higher melting point than sample itself
Describe errors that may cause an observed capillary melting point of a pure sample to be BROAD in range (over several degrees).
- Measuring an impure sample
- Measuring a wet sample
- Heating the sample too quickly
- Using too large a sample size
- Measuring a sample with large crystals
True/False
An impurity always lower the melting point of an organic compound
False
Note: Usually true, except if impurity has a significantly higher m.p. and is present in large quantities
True/False
A sharp melting point for a crystalline organic substance always indicated a pure single compound
False
Note: Usually true with the exception of eutectic mixture
True/False
If the addition of a sample of compound A to compound X does not lower the melting point of X, X must be identical to A.
True
Note: Rare exception. If A has a higher melting temperature than X, and the addition of A to X creates a mixture with the same melting point as pure A, then the statement could be false (unlikely)
True/False
If the addition of a sample of compound A to compound X does lowers the melting point of X, X and A cannot be identical.
True
The melting points of pure benzoic acid and pure 2-naphtol are 122.5°C and 123°C, respectively. Given a pure sample that is known to be either pure benzoic acid or pure 2-naphtol, describe a procedure you might use to determine the identity of the sample.
Prepare 2 new samples (A and B), A with a mix of your pure sample and sample of benzoic acid, and B with a mix of your pure sample and a sample of 2-naphtol. Measure both melting points. If the melting point of the sample is broad and depressed, then that sample (A or B) is likely a mixture. If the melting point of the sample is sharp and the same temperature, then the sameple (A or B) is likely a pure sample (i.e. the 2 compounds in the mixture are identical).
Derive the mathematical relationship between frequency and wavenumber by using Equations 8.1 (E=Nhv=Nh(c/λ)) & 8.3 (ṽ(cm-1) = 10000/λ(µm)) and point out why it is imprecise to use the terms “frequency” and “wavenumber” interchangeably.
Equation 8.1
E=Nhv = Nh(c/λ)
Divide both sides by Nh, then get: v(s-1) = c(cm/s) / λ(cm)
Equation 8.3
ṽ(cm-1) = 10000/λ(µm)
Convert µm to cm (factor of 10000), then get: ṽ (cm-1) = 1 / λ(cm)
Rearrange to get: λ(cm) = 1 / ṽ (cm-1)
Combined Equation of 8.1 & 8.3
v = c / (1 /ṽ (cm-1)) = cṽ
Final Equation
v (s-1) = c(cm/s) x ṽ (cm-1)
It is incorrect to use the two interchangeably b/c they are in different units (frequency = s-1; wavenumber = cm-1)
Compute the reduced mass, m*, of a C-D bond and then use Equation 8.4 to determine the wavenumber at which the C-D stretching vibration occurs, assuming the corresponding vibration for the C-H bond is 3000cm-1.
Reduced mass Equation
Reduced mass m* = (mCatom x mDatom) / (mCatom + mDatom)
Solve for m:
m* = (12g/mol / 6.022 x 1023atom/mol) x (2g/mol / 6.022 x 1023atom/mol)
(12g/mol / 6.022 x 1023atom/mol) + (2g/mol / 6.022 x 1023atom/mol)
m* = 2.85 x 10-24g/atom
Equation 8.4
ṽ = (1 / 2πc) x sqrt k / m*
ṽ = (1 / (2π)(3 x 1010cm/s)) x sqrt (5 x 105dyne/cm / 2.85 x 10-24g/atom)
ṽ = 2225cm-1