chap 9- developing metals Flashcards

1
Q

what has to be the same in half equations before you can write the overall equation

A

number of electrons lost / gained must balance

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2
Q

what 3 things can you add to balance a half equation

A

e-, H2O and H+

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3
Q

what do redox titrations show

A

how much oxidising agent is needed to exactly react with a quantity of reducing agent but you need to know the conc of either the oxidising or reducing agent

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4
Q

outline the process of a redox titration where manganate (VII) ions are the oxidising agent

A
  1. measure out quantity of reducing agent eg Fe2+ using pipette and put in conical flask
  2. add some dilute sulfuric acid to flask as an excess
  3. add aqueous MnO4- (oxidising agent) using a burette and swirl conical flask
  4. stop when mixture in flask becomes tainted with colour of MnO4- and record vol of oxidising agent added
  5. repeat until you have concordant results
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5
Q

what is the colour change that occurs when manganate ions are added to the reducing agent

A

manganate ions are purple then when they start reacting with the reducing agent they’re reduced to colourless Mn2+. this continues until all the reducing agent has reacted at which point the colour will turn pink (colour of oxidisng agent)

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6
Q

why are electrochemical cells a redox process

A

there are always 2 reactions (one oxidation and one reduction)

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7
Q

what is an electrochemical cell

A

2 different metals dipped in salt solutions of their own ions and connected by a wire. oxidation happens at anode and reduction at cathode

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8
Q

describe the flow of electrons in an electrochemical cell

A

electrons flow through the wire from the most reactive metal to the least

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9
Q

what is the cell potential or Ecell

A

voltage between the 2 half cells. measured by a voltmeter in the external circuit and also measures the direction of flow of electrons

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10
Q

method of setting up an electrochemical cell involving 2 metals

A
  1. clean surface of each strip of metal with emery paper
  2. clean electrodes using propanone
  3. place each electrode in a beaker filled with a solution containing ions of that metal (sometimes you have to add acid to a half cell too)
  4. create a salt bridge by soaking piece of filter paper in salt solution and drape between 2 beakers so it’s immersed in both
  5. connect electrodes to voltmeter using wires and crocodile clips (if set up correctly, you’ll get a reading on voltmeter)
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11
Q

what is the rule for writing half equations

A

the reduction reaction is always written in the forward direction with the electrons being added on the left hand side (even though the reaction is reversible)

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12
Q

how would you set up a half cell between 2 ions of the same element in different oxidation states

A

conversion happens on the surface of the electrodes and as neither reactants or products are solid something that conducts electricity but is inert needs to be used for the electrodes eg platinum (expensive) or graphite

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13
Q

what solutions can be used for a salt bridge

A

KCl or KNO3

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14
Q

what is the role of the salt bridge

A

balances the charges between the 2 half cells and allows ions to flow through the cell completing the circuit

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15
Q

what is the standard electrode potential

A

the voltage measured under standard conditions when the half cell is connected to a standard hydrogen electrode

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16
Q

what are standard conditions for a standard electrode potential

A
  1. concentration of 1 mol dm -3
  2. 298K (25c)
  3. 100 kPa
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17
Q

what is the standard hydrogen electrode

A

half cell with a value of 0V

always shown on the left (doesn’t matter whether or not the other half cell is where oxidation happens)

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18
Q

how do you work out Ecell from standard electrode potentials

A

Ecell = (Epositive - Enegative)

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19
Q

what do mor reactive metals have

A

large negative electrode potentials as the more reactive the metal, the more it wants to lose electrons and form a + ion

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20
Q

what do more reactive non metals have

A

more positive standard electrode potentials as it wants to gain electrons to form a negative ion

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21
Q

which direction do different half equations go

A

the half equation with the more negative electrode potential moves to the left and the half equation with the more positive electrode potential moves to the right

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22
Q

how can you tell if a reaction is feasible from the half equations

A

when the redox created from the half equations matches the reaction described in the question and the feasible directionn

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23
Q

when can feasibility predictions be wrong

A
  1. if the rate of the reaction is so slow that the reaction appears not to happen
  2. if the reaction has a high activation enthalpy, this could stop it happening
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24
Q

what are the 2 half equations involved in rust formation

A

Fe2+ + 2e- = Fe and

2H2O + O2 + 4e- = 4OH-

25
Q

why is rust less likely to form in alkaline conditions

A

adding OH- ions to the reaction causes the equilibrium to shift in the iron half equation to the right so theres less Fe2+ and less rust

26
Q

what are the 2 main ways to prevent rust

A
  1. painting / coating with a polymer

2. oiling / greasing- used when moving parts are involved eg a bike chain

27
Q

what is the sacrificial method of preventing rust

A

placing a more reactive method with the iron so the water and oxygen react with this instead eg zinc is often used

28
Q

define what a transition metal is

A

a d block element that can form at least one stable ion with an incomplete d sub shell

29
Q

why are scandium and zinc not transition metals

A

1) scandium only forms one ion (Sc3+) which has an empty d sub shell
2) zinc only forms one ion (Zn2+) which has a full d sub shell

30
Q

what are the chemical properties of transition metals

A

1) can exist in variable oxidation states eg iron can exist as 2+ and 3+
2) they can form coloured ions in solution eg Cu2+ is blue, Fe2+ is pale green and Fe3+ is yellow

31
Q

why can transition metals have variable oxidation states

A

because the energy levels of the 4s and 3d sub shells are very close to one another so different numbers of electrons can be lost / gained using similar amounts of energy

32
Q

what is a complex ion

A

a central metal atom or ion surrounded by coordinately (datively) bonded ligands

33
Q

what is a coordinate bond

A

a dative bond- covalent bond where both electrons in the shared pair come from the same atom. in a complex they both come from the ligands

34
Q

what is a ligand

A

an atom, ion or molecule that donates a pair of electrons to a central transition metal ion to from a coordinate (dative covalent) bond (must have a lone pair of electrons)

35
Q

define monodentate ligand

A

ligands with one lone pair

36
Q

define bidentate ligand

A

ligands with 2 lone pairs so 2 coordinate bonds can be formed with a metal ion

37
Q

define polydentate ligand

A

ligands with more than 2 lone pairs eg EDTA 4- has 6 lone pairs so its hexadentate and can form 6 coordinate bonds with a metal ion

38
Q

what is the shape of a complex ion with 6 coordinate bonds

A

octahedral shape with all bond angles 40degrees

39
Q

what is the shape of a complex ion with 4 coordinate bonds

A

tetrahedral shape with all bond angles 109.5 degrees but .. sometimes forms a square planar shape eg cisplatin where all bond angles are 90

40
Q

what happens when ligands bond to transition metal ions

A

normally all the 3d orbitals of transition metal ions have the same energy but when ligands come and bond to the ions some of the orbitals gain energy so the 3d orbitals then split into 2 different energy levels

41
Q

what things affect the size of the energy gap that electrons have to jump

A

1) the central metal ion
2) oxidation state
3) ligands
4) coordination number

42
Q

what causes transition metals to be coloured

A

some frequencies of visible light are absorbed when electrons jump to higher orbitals. the freq absorbed depends on the energy gap. the rest of the frequencies are transmitted or reflected and these combine to make the complement of the colour of the absorbed frequencies (the colour you see)

43
Q

when does a compound look white or colourless

A

when there are no 3d electrons or the 3d subshell is full, then no electrons will jump so no energy will be absorbed and compound appears white or colourless

44
Q

what is ligand substitution

A

when one ligand is swapped for another ligand- usually results in a colour change (if ligands are of a similar size then the coordination number and shape doesn’t change)

45
Q

why do transition metals make good catalysts

A

because they can change oxidation states by gaining or losing electrons within their d orbitals so they can transfer electrons to speed up reactions

46
Q

what are the risks of using transition metal catalysts

A

many of the metals and their compounds are toxic eg long term exposure to copper can damage liver and kidneys and exposure to manganese can cause psychiatric problems

47
Q

why do transition metals make good HETEROGENEOUS catalysts

A

because they can use their s and d orbitals for bonding to the reactant molecules (strongly enough so they are held to the surface long enough to react but not attract too strongly so products don’t desorb)

48
Q

why do transition metals make good HOMOGENOUS catalysts (peroxodisulfate + iodide example)

A

this reaction is really slow as both ions are negatively charged so they repel each other and it’s unlikely they’ll collide/ react. Adding Fe2+ causes them to be oxidised to Fe3+ by the S2O8 2- and the Fe3+ can then oxidise the I- to iodide

49
Q

how is the colour of a transition metal determined

A

when white light hits a transition metal, one freq of light is absorbed and the rest of the frequencies are transmitted (the transmitted frequencies correspond to the colour you see) THE COLOUR OF THE TRANSITION METAL SOLUTION IS THE COMPLEMENT OF THE COLOUR ABSORBED)

50
Q

how does a colorimeter work

A

1) filters a source of white light into monochromatic light (narrower freq range, one colour)
2) pick a filter that produces a colour thats absorbed by the transition metal you want to look at
3) set colorimeter to 0 by measuring absorbance of a blank sample
4) samples should be placed in a clean cuvette
5) light passes through filter and sample (where some of it will be absorbed) remaining light travels to a detector which compares absorbance of sample to the blank
6) high absorbance means a lot of light has been absorbed and sample is very concentrated

51
Q

how can visible absorption spectroscopy be used to find concentrations of ions

A

1) beam of monochromatic light is passed through a solution of the complex. detector measures intensity of light before and after its passed through the solution (calc absorbance from this)
2) different freq of light are passed through solution to produce visible absorption spectrum (peaks in graph tell you which colours the complex absorbs most strongly)
3) calibration curve can be used to convert absorbance data into concentration

52
Q

why does Co (cobalt) have 3 unpaired electrons

A

because the 4S subshell fills up before the 3D does so Co has 27 electrons and the electron configuration ends with 3d7 4s2. also the 3d orbitals are occupied singly at first and only double up when they have to

53
Q

what are the chromium and copper exceptions

A

chromium- 4s orbital does start to fill up before 3d is full but electron configuration is 3d5 4s1 because it is more stable to have one electron in each orbital of the 3d sub shell
copper- electron configuration of 3d10 4s1 (more stable to have a full 3d sub shell and just one in 4s) when it forms Cu2+ it becomes 3d9

54
Q

give the half equation that shows how hydroxide ions are formed in rusting

A

2H2O + O2 + 4E- = 4OH-

55
Q

what is the oxidation state of iron in red-brown rust

A

+3

56
Q

what do you get if you mix 2 complementary colours of light

A

white light

57
Q

why do transition metals form coloured complexes but other elements don’t

A

when ligands bond with transition metal ions there is repulsion between the electrons in the ligands and the electrons in the d orbitals. the d orbital electrons are split into 2 groups and the energy difference between these 2 groups is directly proportional to the freq of visible light that this complex can absorb and the colour we see is the complementary colour

58
Q

what does the size of the energy gap between the 2 groups of d block electrons depend on

A

1) the nature of the transition metal ion
2) its oxidation state (as oxidation state increases so does the amount of splitting of the d orbitals)
3) the nature of the ligands (ligands with strong electrical fields cause a large energy gap when the d orbitals split)
4) coordination of the ion (splitting is greater in octahedral than tetrahedral)

59
Q

why can a titration with manganate be done without indicator

A

because MnO4^2- is pink coloured so induces a colour change of colourless to pink solution to mark the end point