CH-11: Photosynthesis in Higer Plants - SET 2 Flashcards

1
Q

What steps are involved in the photochemical phase of photosynthesis?

A
  1. Light absorption
  2. Water splitting
  3. Release of oxygen
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2
Q

What is the photochemical phase of photosynthesis responsible for?

A

The photochemical phase or the light reactions are thought to be responsible for the formation of high-energy chemical intermediates, ATP and NADPH

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3
Q

What are photosynthetic units or pigment systems?

A

Group of pigment molecules which take part in the conversion of light energy into chemical energy

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4
Q

Name the two photosynthetic units.

A
  1. Photosystem I (PS-I)
  2. Photosystem II (PS-II)
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5
Q

What is a reaction centre?

A

Possessed by each photosynthetic unit, the reaction center is made of a specific chlorophyll a molecule which absorbs light energy of long wavelength. It ca release electron upon absorption of energy.

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6
Q

What is the absorption peak of the reaction center in PS-I?

A

700nm
(hence the reaction center is known as P700)

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7
Q

What is the absorption maximum of the reaction center in PS-II?

A

680nm
(hence the reaction center is known as P680)

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8
Q

What is the reaction center surrounded by?

A

It is surrounded by a number of light harvesting pigment (LHP) molecules (also called antenna molecules)

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9
Q

What is the function of the antenna molecules?

A

They absorb photons of different wavelengths and transfer this energy to the reaction center

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10
Q

What are the complexes of the harvesting molecules occur known as?

A

Light harvesting complexes
LHC-I and LHC-II

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11
Q

What are the pigment molecules of the light harvesting complexes bound to? What is its function?

A

Proteins. They help to make photosynthesis more efficient.

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12
Q

What is the reaction center of Photosystem I/ Pigment system I known as?

A

P700

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13
Q

What is the reaction center of Photosystem II/ Pigment system II known as?

A

P680

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14
Q

Where does the PS I lie?

A

On the outer surface of the thylakoids

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15
Q

Where does the PS II lie?

A

On the inner surface of thylakoids

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16
Q

Where is the PS I found?

A

Found in grana and stroma lamellae

17
Q

Where is the PS II found?

A

Found in grana only

18
Q

In which type of flow of electrons does the PS I participate in?

A

It participates in both cyclic and non-cyclic flow of electrons

19
Q

In which type of flow of electrons does the PS II participate in?

A

It is involved only in non-cyclic flow of electrons

20
Q

Which photosystem is associated with splitting of water and release of oxygen?

21
Q

What term did Arnon use to refer to ATP and NADPH?

A

Assimilatory powers

22
Q

Define photophosphorylation.

A

The process of formation of ATP and ADP and inorganic phosphate (iP) utilizing light energy is called photophosphorylation

23
Q

What is the electron transport chain?

A

A series of electron carriers over which electrons pass in a downhill journey releasing energy at every step that is used in generating an electrochemical proton (H+) gradient which helps in synthesizing ATP

24
Q

In which series do the two photosystems work during non-cyclic photophosphorylation?

A

First PS II and then PS I

25
What connects the two photosystems during non-cyclic photophosphorylation?
Electron transport chain
26
Describe the process of non-cyclic photophosphorylation.
STEP 1: In PS II, the P680 molecule absorbs 680 nm wavelength of red light causing electrons to become excited and jump into an orbit which is farther from the atomic nucleus. STEP 2: This excited electron is then picked up by the primary electron acceptor of PS II STEP 3: The primary electron acceptor of PS II passes the electron to an electron transport system of cytochromes STEP 4: The electrons are then passed onto the pigments of PS I. Simultaneously, electrons in P700 are excited when they receive light of wavelength 700 nm. STEP 5: These electrons are transferred to the electron acceptor of PS I that has a greater redox potential STEP 6: These electrons are then moved downhill to a molecule of NADP+ STEP 7: The addition of these electrons reduces the NADP+ to NADPH + H+ ion
27