carboxylic acid and its derivatives Flashcards

1
Q

comment on the bp of carboxylic acids

A
  • higher than alc as it forms stronger H bonding than alcohol as O-H bond is more polarised due to presence of electron donating inductive carbonyl group
  • carboxylic acid dimerise in the liquid state forming 2 H bonds between each pair of molecules
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2
Q

comment on the solubility of carboxylic acids

A

lower acids can form H bonds and are soluble but solubility decreases as HC chain increases

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3
Q

why are carboxylic acids more acidic than alcohols

A

alc - ROH <—> RO- and H+
carboxylic acid - RCO2H <—> RCOO- and H+

in RCO2- ion, the p-orbitals in the CO2- group overlap with one another resulting in RCO2- having a resonance stabilized structure. This helps disperse the negative charge on the O atom, stabilizing it and increasing the strength of acid as POE of eqn 2 lies more to the right than eqn 1

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4
Q

what are the reactions that carboxylic acids undergo

A
  1. reaction with reactive metals, acids, carbonates and hydrogen carbonates
  2. reaction with alcohols to form esters (reversible)
    conc H2SO4(aq) and heat
  3. conversion to acyl chlorides
    PCl3 and SOCl2 at rtp or PCl5 with heat
  4. reduction to form pri alc
    LiAlH4 in dry ether at rtp
  5. decarboxylation to alkanes
    soda lime (CaO and NaOH) and heat
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5
Q

how to form carboxylic acids

A
  1. From oxidation of primary alc or aldehydes
    K2Cr2O7(aq), H2SO4(aq) and HUR for both or KMnO4 … for aldehydes
  2. acid hydrolysis of nitiriles
    conc H2SO4 (aq) and heat
  3. side chain oxidation of benzylic H
    KMnO4 in H2SO4 and heat
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6
Q

what is a distinguishing test for carboxylic acids

A

acid hydrolysis to form carboxylic acid as NH3 is produced which turns red litmus blue

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7
Q

which reducing agent is stronger and why - LiAlH4 in dry ether at rtp vs NaBH4 in ethanol

A

LiAlH4 is the stronger reducing agent due to the larger electronegativity diff between H and the Al as compared to H and B, making the H more electron rich

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8
Q

comment on the bp of acyl chlorides and esters

A

acyl chlorides and esters dont form intermolecular H bonds as they lack H atom directly bonded to a highly electronegative atom. Thus, molecules are only attracted by weaker pd-pd int so they have lower bp

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9
Q

comment on the solubility of acyl chlorides and esters

A

esters solubility varies with the R groups while acyl chlorides are very reactive with water

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10
Q

how to form esters

A
  1. alc and carboxylic acid with conc H2SO4(aq) and heat
  2. alc and acyl chlorides at rtp
  3. phenols and acyl chlorides with addition of NaOH(aq) ( to generate stronger nucleophile C6H5O- )
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11
Q

what reaction does esters undergo

A

acid hydrolysis or base hydrolysis followed by addition of acid
H2SO4 of NaOH both with heat —> carboxylic acid or carboxylic salt

note: acid hydrolysis is reversible while base hydrolysis is not

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12
Q

how to form acyl chlorides

A

conversion of carboxylic acid to acyl chlorides
PCl5 with heat or PCl3/SOCl2 at rtp

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13
Q

what reactions do acyl chlorides undergo

A
  1. hydrolysis with water to form carboxylic acid
    - gives white fumes of HCl
  2. alc or phenol to give esters
    rtp for alc and NaOH for phenol
  3. react with ammonia/amines to give amides
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14
Q

compare the ease of hydrolysis of
RCOCl C6H5COCl RCH2Cl and C6H5Cl

A

comparing the acyl chlorides to RCH2Cl and C6H5Cl, the alpha carbon is bonded to 2 highly electronegative atom, Cl and O, which exerts an electron-withdrawing inductive effect that makes the alpha carbon highly electron deficient and more susceptible to nu attack

comparing the 2 acyl chlorides, C6H5COCl faces more steric hindrance due to the presence of the huge benzene ring making it harder for nucleophiles to approach

comparing the 2 non-acyl chlorides, the p orbitals of Cl in C6H5Cl overlap with the p orbitals of the carbon in the benzene ring resulting in delocalization of lp of electrons which imparts double bond character on the C-Cl bond making it harder to break and less reactive

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