Calculations using moles and the Avogadro constant Flashcards
a mole is
the amount of substance that contains the same number of particles as the number of carbon atoms in exactly 12g of the C-12 isotope.
atoms are
very tiny particles that cannot be seen by the human eye
sand is made of
the silicon and oxygen compound SiO2
the Avogadro constant is
the scaling-up factor from atoms to grams,
6.02 x 10(23) mol-1
relative atomic masses are used to
compare the relative masses of atoms
in a water molecule, the oxygen atom has a mass that is
16 times the mass of a hydrogen atom
the number of oxygen atoms in 16.0g of oxygen is the same as the number of
hydrogen atoms in 1.0g of hydrogen
The symbol L is used for
the Avogadro constant
the Avogadro constant is represented using the symbol
L
how many atoms of He are in 4.0g of helium?
6.02 x 10(23)
there are…………. atoms of Na in 23.0g of sodium
6.02 x 10(23)
you can use the mole to count
atoms, molecules, ions, electrons and other species
when using moles, it is important to include the
exact description of the species being referred to
one mole of water has mass
18.0g
when talking of the mass of one mole of oxygen or hydrogen (for example), it depends on whether you are referring to
atoms or molecules
the symbol…..is used for the amount of substance inmol
n
it is good practice to refer to both
the formula and name when using moles, e.g.
the amount, in moles, of O in 16.0g of oxygen atoms is (1mol)
the amount, in moles, of O2 in 16.0g of oxygen molecules is (0.5mol)
the equation for calculating moles is
amount of substance= mass in grams / molar mass
n= m/M
when working with L in calculations, you can be asked to
calculate the number of particles in a given mass of a substance
calculate the mass of a given number of particles of a substance
the steps you would go through when calculating the number of H2O molecules in 1.25g of water are:
1) calculate the mol
n= m/M so n= 1.25 / 18 = 0.0694mol
2) calculate the number of molecules
L x 0.0694 = 4.18 x 10(22)
L =
6.02 x 10(23)
the mass of 100 million atoms of gold can be calculated by
1) n = 100,000,000 / 6.02 x 10(23) = 1.66 x 10(-16) mol
2) m= 1.66 x 10(-16) x 197.0 = 3.27 x 10(-14) g of gold