Calculations II Flashcards

1
Q

(NS) normal saline =

A

0.9% (w/v) NaCl

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2
Q

1/2 NS

A

0.45% (w/v) NaCl

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3
Q

D5W

A

5% (w/v) dextrose in water

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4
Q

D20W

A

20% (w/v) dextrose in water

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5
Q

% w/v =

A

g / 100mL (solid mixed into a liquid)

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6
Q

% v/v =

A

mL / 100mL (liquid mixed into a liquid)

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7
Q

% w/w =

A

g / 100g (solid mixed into a solid)

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8
Q

Ratio Strength:

Express 0.04% as a ratio strength:

step 1) 0.04 = 1 part

                                                     0.04 step 2)      0.04% ------->            \_\_\_\_\_\_\_\_\_
                                                     100

Step 3) Set up problem: 0.04/100 = 1 part/x parts

step 4) Solve for x x = 2500

*Step 5) put in appropriate form ——-> ratio strength is 1:2500

A

Ratio Strength is 1 part of some number of other parts.

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9
Q

Express 1:4000 as a percentage strength:

Step 1: 1 part / 4000 parts

Step 2: Set up to solve for percentage “100”

1 part / 4000 parts = x / 100

Step 3: solve for x ————-> x = 0.025%

A

Another way to solve problem:

Express 1:4000 as a percentage strength:

1) Take 4000 / 100 = 40

2) Then divide 1/40 = 0.025

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10
Q
A
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11
Q

PPM = Parts Per Million

part / 1,000,000 parts

A
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12
Q

Express 0.00022% (w/v) as PPM

remember- set up what we know:

0.00022 g / 100mL = x parts / 1,000,000

solve for x:

X = 2.2 PPM

A

Quick TIP:

If going from: percentage strength ———> PPM

Then move decimal point to the right 4 places*

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13
Q

Express 5 PPM of iron in water as a percentage

5 parts / 1000000 = X g / 100 mL

X = 0.0005%

A

Quick TIP:

If going from PPM ———–> percentage strength

Then move decimal point to the left 4 place*

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14
Q
A
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15
Q

Specific Gravity equation:

2) What is Specific Gravity (SG)?

A

SG = weight of the substance (g) / weight of equal volume of water (g)

OR more simply ***SG = g / mL

2) SG is the ratio of the density of a substance to the density of water

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16
Q

Water has a specific gravity of _____. Which means _

A

1

1gram water = 1 mL water

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17
Q

Substances with a specific gravity < 1 are ____________ than water

A

lighter

18
Q

Substances with a specific gravity > 1 are _________ than water

A

heavier

19
Q
A
20
Q

Dilution AND Concentration:

Q1 x C1 = Q2 x C2

Q1 = old quantity
C1 = old concentration
Q2 = new quantity
C2 = new quantity

A

Make sure Units match on both sides!!

21
Q

It the prescription calls for an ingredient that is PURE, the concentration is _______

A

100%

22
Q

A diluent, (e.g. petrolatum, lanolin, alcohol, ointment base, lactose, Aquaphor) does NOT contain any drug - the concentration of the diluent is _________

A

0%

23
Q
A
24
Q

Alligation:

A

Is used to obtain a new strength (percentage) that is between two strengths the pharmacist has in stock.

It is used when the problem deals with 3 concentrations

25
Q

Setting up an Alligation Problem:

1) Higher % goes up higher: Top left

2) Lower % goes down lower: Bottom left

3) Desired % in the middle

4) Subtract diagonally along the X lines to obtain the number of parts. *(no negative signs on the right side of X)

5) For some problems, it will be necessary to add up the total number of parts

A

Higher % _____ parts of Higher% Xg
- =
Desired %
- =
Lower % _____ parts of Lower% Xg

26
Q
A
27
Q

Osmolarity:

equation:

A
  • is a measure of the total number of particles (or solutes) per Liter of a solution = mOsmol/L

mOsmol/L = ( weight (g/L) / MW (g/mole) ) x (# of particles) x 1000

28
Q

The number of particles in a given solution is directly proportional to its ___________.

The particles are usually measured in ___________

A

osmotic pressure

milliosmoles (mOsmol)

29
Q

Number of dissociation particles for:

Dextrose is

A

1

30
Q

Number of dissociation particles for

Mannitol is

A

1

31
Q

Number of dissociation particles for

potassium chloride (KCl) is

A

2

32
Q

Number of dissociation particles for

sodium chloride (NaCl)

A

2

33
Q

Number of dissociation particles for

sodium acetate (NaC2H3O2) is

A

2

34
Q

Number of dissociation particles for

magnesium sulfate (MgSO4) is

A

2

35
Q

Number of dissociation particles for

Calcium chloride (CaCl2) is

A

3

36
Q

Number of dissociation particles for

sodium citrate (Na3C6H5O7)

A

4

37
Q

Isotonicity:

  • when solutions are prepared, the solutions used in humans must match the tonicity of body fluid as closely as possible.
  • body fluids are isotonic [osmotic pressure similar to normal saline (0.9% NS)]
A

E = (58.5) (i) / (MW of drug) (1.8)

i = dissociation factor based on number of dissociated ions

The E-value is something pharmacists use to figure out how much different products to use when compounding a particular drug to make it isotonic.

38
Q

isotonicity is desired when preparing _______

A

eye drops and nasal solutions

39
Q

The relationship between the amount of drug that produces a particular osmolarity and the amount of sodium chloride that produces the same osmolarity is called the ______________

A

“sodium chloride equivalent” or E-value

40
Q

moles AND millimoles:

moles =

mmols =

A

moles = g / MW

grams of a substance divided by the MW

mmols = mg / MW

  • a millimole (mmol) is 1/1000 of the molecular weight (MW)
41
Q

Milliequivalents:

mEq =

A

mEq = mg x valence / MW

mEq = mmols x valence

42
Q
A