C8-9. DC Electricity I Flashcards

1
Q

How do we define electrical current?

A

The rate of flow of electrical charge. Represented by the symbol I, and measured in amperes.

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2
Q

What equation links current, charge and time?

A

I = Q/t. We can think of this as ‘current is the number of coulombs of charge passing a point over a given time’.

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3
Q

What are the base and derived units of electrical charge?

A

Coulombs (Q) and, from the equation I = Q/t, ampere-seconds (A s).

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4
Q

What types of particles can be considered charge carriers?

A

Electrons and charged ions.

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5
Q

What is the value of the elementary charge e, and what does it represent?

A

This is given as 1.6 * 10^-19 C, and this represents the charge on one proton, from which all relative charges such as that of an electron, or a charged 1+/ 2-/etc. ion, are derived from.

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6
Q

Why do we describe the charge on an object as quantised?

A

Charges must always be multiples of 1.6 * 10^-19 (the elementary charge) so there is a limited set of values charge can have. Therefore, the value of charge is ‘quantised’.

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7
Q

How can we express the net charge on an object?

A

This must always be some multiple of e, and we calculate it using the equation Q=ne, where n is the number of electrons and Q is the charge passing through the given point per second.

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8
Q

How do most objects obtain a net charge?

A
  • Most of the time, a net charge on an object arises due to the gain or loss of electrons by the object.
  • If the object starts in a neutral (uncharged) state, if it gains (negatively charged) electrons, it will gain an overall negative charge.
  • The opposite happens if electrons are lost.
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9
Q

What are the charge carriers when current flows in the solid state?

A

Electrons are usually the charge carriers in the solid state.

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10
Q

What are the charge carriers when current flows in the liquid state?

A

Charged ions are usually the charge carriers in the liquid state.

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11
Q

How might we model the flow of charge through a (metallic) wire?

A
  • The wire itself has a metallic lattice (crystalline) structure, with a pool of delocalised electrons surrounding positive metal ions.
  • If the wire becomes charged on opposite ends, the electrons will be drawn towards the oppositely-charged positive end, hence the charge carriers move and current flows.
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12
Q

What factors might cause an increase in current?

A

We can think about this using the equation I=Q/t ir we need to:
- A greater number of electrons per second flowing increases the current (this might be caused by increased cross-section)
- The same number of electrons moving past a point more quickly increases the current

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13
Q

What is the difference between conventional current and electron flow?

A
  • Conventional current flows between positive - negative termini.
  • Electron flow runs in the reverse direction - i.e. from negative to positive terminals of a source of emf.
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14
Q

What do we call a liquid that can carry an electrical current?

A

These are called electrolytes, and are used in the process of electrolysis, wherein an ionic solution is split into positive and negatively charged ions which are attracted to oppositely-charged electrodes.

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15
Q

How does electrolysis result in the flow of an electric current?

A
  • The ionic solution (salt) splits into +ve metal ions and -ve non-metal ions.
  • These are attracted towards -ve and +ve electrodes respectively.
  • This is the movement of charge carriers, so a current flows through the electrolyte.
  • The +ve metal ion accepts an electron, which is donated by the -ve non-metal ion when it reaches an electrode. This flow of electrons causes a current to flow in the metal circuit.
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16
Q

Ideally, should ammeters have a high or low resistance?

A

They should have a low resistance. They are connected in series to the rest of the circuit, so a lower resistance would reduce the effect they have on the size of the current.

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17
Q

What discovery did Millikan’s experiment help him to make?

A

It proved that electrical charge is a quantised value, through investigation the motion of droplets between oppositely-charged metal plates.

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18
Q

How did Millikan’s experiment work?

A
  • When the oil droplets were sprayed they experienced air resistance, upthrust and gravitational force.
  • Some were held stationary as the force of gravity = the electrostatic force of the charged plates
  • Some drifted slowly through the induced electric field of the plates.
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19
Q

Describe the law of conservation of charge.

A

Electrical charge can neither be created nor destroyed, so the total amount of charge in the universe is constant.

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20
Q

What is Kirchhoff’s 1st Law?

A

For any point/junction in an electrical circuit, the sum of currents into that point is equal to the sum of currents flowing out of the point.

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21
Q

How do we classify conductivity of a material?

A

Conductivity is based on a material’s number density. The higher the number density, the greater number of free electrons per unit volume, so the electrical conductivity increases.

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22
Q

What is the definition of number density?

A

This is the number of free charge carriers per unit volume in a material.

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23
Q

What is the (functional) difference between a conductor and a semiconductor?

A
  • Semiconductors have a much lower number density than conductors.
  • This means that, in order to carry the same current, more charge must flow per unit time, so the electrons must be moving more quickly for a constant cross-section.
  • This incidentally causes the temperature of a semiconductor to increase.
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24
Q

Do charge carriers move at a high or low velocity?

A

Although the effects of charge flowing seem instant, charge carriers actually move at a relatively slow velocity. This is because free electrons collide frequently with metal ions, so their path is very indirect and therefore their velocity is very low overall.

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25
Q

What equation links current, cross sectional area, number density, elementary charge and mean drift velocity?

A

I=Anev, often rearranged as I=nAve for memorability.

26
Q

What is the definition of mean drift velocity?

A

The average velocity of electrons as they travel through a given medium, colliding with +ve metal ions.

27
Q

How does cross-sectional area affect mean drift velocity?

A

We can consider the equation I=nAve. The narrower the wire (i.e. the smaller the cross-sectional area), the greater the drift velocity must be in order to maintain a constant value of current.

28
Q

How do we define potential difference?

A

Potential difference is a measure of energy transferred to other stores by charge carriers in a circuit, per coulomb of charge. It is measured in Volts.

29
Q

What equation links voltage, energy transferred and charge?

A

V = E/Q

30
Q

What are the base and derived units for voltage?

A
  • Volts (V)
  • Joules per coulomb (J C^-1)
31
Q

Why are voltmeters connected in parallel to the rest of the circuit?

A
  • Voltmeters have high resistance so that, in parallel, their resistance has little effect on the current passing through the main loop of the circuit.
  • If connected in series, this high resistance would significantly reduced the current.
32
Q

What is the difference between potential difference and electromotive force?

A
  • Potential difference describes when work is done by the charges i.e. energy is transferred to other stores.
  • EMF is used to describe when work is done on charge carriers, i.e. energy is transferred from other stores to the charges.
33
Q

Give some examples of sources of EMF (electromotive force).

A
  • Solar cells
  • A dynamo
  • Thermocouples
34
Q

What is an electron gun?

A

This is an electric device which produces a narrow beam of electrons, used to ionise particles through the addition/removal of electrons.

35
Q

Summarise how an electron gun works.

A
  • A metal wire - the cathode - is heated by a current such that thermionic emission occurs, and electrons are released into a vacuum containing an anode with a hole.
  • The electrons accelerate towards the anode, gaining kinetic energy.
  • The hole ensures that electrons exit the electron gun with specific kinetic energy.
36
Q

How can we link work done on an electron to its gain in kinetic energy?

A
  • The work done on a single electron as it accelerates = elementary charge * accelerating p.d. (eV)
  • This is equal to kinetic energy due to the law of conservation of energy.
  • Therefore eV=1/2*mv^2
37
Q

How does the kinetic energy of electrons change with accelerating p.d.?

A

The greater the p.d., the more energy is transferred to electrons, so they move faster (i.e. with more kinetic energy).

38
Q

How do we define resistance of a component?

A

The resistance of a component is the ratio between the the p.d. across the component and the current flowing through it.

39
Q

What is the equation linking resistance, current and voltage?

A

R = V/I
- Where R is given in Ohms, V is given in Volts and I is given in Amperes

40
Q

What is the definition of an Ohm?

A

The resistance of a component when a potential difference of 1V is produced per ampere of current.

41
Q

Describe Ohm’s law.

A

For a metallic conductor maintained at a constant temperature, the current in the wire is directly proportional to the potential difference across its ends.

42
Q

How does the current through a wire affect its resistance, and why?

A

When we increase current through a wire whilst maintaining a fixed potential difference, the temperature of the wire increases.
- This occurs because charge carriers collide more frequently with positive ions in the wire, causing them to do more work, inhibiting the flow of current.
- This causes resistance to increase.

43
Q

What is the shape of the I-V graph of a fixed resistor, and what does this tell us about…
- Ohmic properties?
- Changes in resistance with current?

A
  • The shape is a straight line passing thru. the origin
  • This is an Ohmic conductor
  • Resistance is constant - I is proportional to V
44
Q

What is the shape of the I-V graph of a filament lamp, and what does this tell us about…
- Ohmic properties?
- Changes in resistance with p.d.?

A
  • The shape is a curve passing thru. the origin
  • This is a non-Ohmic component
  • Resistance increases with p.d., due to an increase in temperature of the wire
45
Q

Why are light-emitting diodes more useful today than filament lamps?

A

They transfer electrical energy directly into light through a different process to filament lamps - i.e., they do not increase in temperature in order to achieve light emission. This means that they are able to achieve the same result considerably more efficiently, drawing much less power.

46
Q

What is the shape of the I-V graph of a semiconducting diode, and what does this tell us about…
- Ohmic properties?
- Changes in resistance with p.d.?

A
  • The shape is a flat line until the threshold p.d., after which the line curves
  • This is a non-Ohmic component
  • Resistance is very high in the reverse bias and remains so until the threshold p.d. at around 0.7V usually, before significantly decreasing
47
Q

How do diodes only enable a current to flow in one direction (polarity)?

A

The resistance of a diode is (infinitely) high when a potential difference is applied in the reverse direction. This means that the diode is unable to conduct electrical current.

48
Q

What factors can affect the resistance of a component?

A
  • The material it is made from
  • The length of the wire
  • The wire’s cross-sectional area
49
Q

What is the difference between resistance and resistivity?

A

Resistance considers a specific component, whereas resistivity is used to describe the electrical property of a material.

50
Q

How is resistance linked to…
- Length?
- Cross-sectional area?

A
  • Resistance and length of wire are proportional. If length is doubled, so must be resistance.
  • Resistance is inversely proportional to the cross-sectional area of a wire. If cross-sectional area doubles, resistance must halve.
51
Q

What is the equation for resistivity? From this equation, determine the units of resistivity.

A

resistivity = (resistance * cross-sectional are) / length of wire, where resistivity is given in units ohm-metres

52
Q

How can we define resistivity? Consider its equation.

A

The resistivity of a material at a constant temperature is given as the product of the resistance of a component made from the material and its cross-sectional area, divided by its length.

This makes resistivity a constant of proportionality for a material.

53
Q

What is the difference in resistivity between conducting and insulating materials?

A

Conductors have resistivity of the order of 10^8 ohm-metres, compared to 10^16 ohm-metres for insulators. Semiconductors fall between these values.

54
Q

What characterises a thermistor?

A

It is a component made from a semiconducting material with a negative temperature co-efficient. As the temperature of the thermistor increases, its resistance drops significantly.

55
Q

What is meant by a negative temperature coefficient?

A

The resistance of the component drops as its temperature increases.

56
Q

Explain why resistance decreases with an increase in temperature for a thermistor.

A
  • In some semiconducting materials, as the temperature of the material increases, the number density of the charge carriers also increases.
  • Therefore, resistance must decrease as temperature increases.
  • This is called a negative temperature co-efficient.
57
Q

What is the definition of electrical power?

A

The rate of energy transfer by an electrical component, measured in Watts.

58
Q

What equation links power, current and voltage? How could this be further derived using V=IR?

A

P=IV, where power is measured in Watts, I is current in Amperes and V is voltage in Volts.
- We could derive this as P=I^2R or P=V^2/R.

59
Q

What equation links power, energy transferred and time?

A

P=W/t, which can we used to allow us to calculate W=VIt

60
Q

What factors does the energy transferred to a component depend on?

A

The power rating of the component, and the time it is used for.

61
Q

What is the definition of a kilowatt-hour?

A

The energy transferred by a device with power 1kW operated over 1 hour - meaning that 1kWh is equivalent to 3.6MJ. We use this unit since the joule is comparatively small in a domestic context.