C Flashcards
V =
iR
KVL (Kirchoffs Voltage Law)
The voltage leaving and entering the element is equivalent to zero
KCL (Kirchoffs Current Law)
The current leaving and the entering the element is equivalent to zero
Resistors In Parallel =
Req = ((R1)(R2)(Rn))/ R1 + R2 + Rn
Resistors in Series
R1 + R2 + Rn = Req
Current through a parallel resistor =
In = I(total) * ((Rtotal) / Rn))
Current in series =
Remains constant throughout
Voltage in parallel =
Same through each element in parallel
Inductor Voltage -
CAN change instantly
Capacitor Voltage -
can NOT change instantly
Inductor Current
can NOT change instantly
Capacitor Current
CAN change instantly
Natural or “Transient Response” equation
v(t) = V0exp (-t / RC)
RC stands for -
Resistor- Capacitor
Time constant Tau (τ) =
RC
What is τ telling us?
The rate at which the voltage discharges
Time constant
time required for the signal to reach 37%
exp^1 =
.3678
v(t) =
Vo exp (-t / τ)
Power Dissipated in a Resistor
PR(t) = V(t) * IR(t) (Wat)
PR(t) =
Vo exp( - t/ τ) * (Vo/R)exp(-t/τ)
Power is measured in
Watts
Pr(t) =
Vo^2/R exp(-2t/τ) (W)
Energy =
Integral of power with respect to time
Integral of Power with respect to time (energy) =
Vo^2/R exp (-2λ / τ) * -τ/2 from 0 to t (lambda is a dummy variable for t)
1st Law of Thermodynamics
Energy can not be created nor destroyed
During Steady State an Inductor acts like a
Short Circuit
During Steady State a Capacitor acts like a
Open Circuit
Voltage Division V1 =
(Vo * Resistor 1 ) / (R1)(R2)
Current Divider Formula (In) =
I(total) (Rtotal/ Rn )
i =
dq/dt
Integral of current =
charge
Voltage is equal to
the energy required to move one coulomb of change through an element
Power is equal to
the change of work over time
