Buffers and Neutralisation (Chapter 21) Flashcards
What is a buffer solution?
A system that minimises pH changes on addition of small amount of an acid or base
What are the two components of a buffer solution and what are their roles?
1) weak acid (HA) - to remove added alkali
2) its conjugate base (A-) - to remove added acid
What are the two ways to prepare a buffer solution?
1) from a weak acid and its salt
2) by partial neutralisation of the weak acid
Describe how you would prepare a buffer solution from a weak acid and its salt
Mix a solution of a weak acid (e.g. CH3COOH) with a solution of one of its salts (e.g. CH3COONa)
Describe how mixing a solution of a weak acid (e.g. CH3COOH) with a solution of one of its salts (e.g. CH3COONa) makes a buffer solution
1) in water, CH3COOH partially dissociates and the amount of ethanoate ions (CH3COO-) is very small
2) ∴ CH3COOH is the source of the weak acid component of the buffer solution: CH3COOH <=> CH3COO- + H+
3) in water, CH3COONa completely dissolves (as it is an ionic compound)
4) ∴ CH3COONa is the source of the conjugate base component of the buffer solution component of the bugger solution: CH3COONa + aq => CH3COO- + Na+
Describe the preparation of a buffer solution by partial neutralisation of the weak acid
1) add an aqueous solution of an alkali e.g. NaOH to an excess of the weak acid
2) the weak acid is partially neutralised by the alkali, forming the conjugate base
3) some of the weak acid is left over unreacted ∴ the resulting solution contains a mixture of the salt and any unreacted weak acid
How does the CH3COOH/CH3COO- buffer solution become almost a 100% solution of CH3COOH and CH3COO-?
1) in the CH3COOH equilibrium, the equilibrium position lies well towards the acid
2) ∴ when CH3COO- ions are added to CH3COOH, the equilibrium position shifted even further to the left, reducing the already small [H+] and leaving a solution containing mainly CH3COOH and CH3COO-
Describe the CH3COOH/CH3COO- buffer solution
- CH3COOH and CH3COO- act as 2 reservoirs that are able to act independently to remove acid and alkali
- This is achieved by shifting the buffer’s equilibrium system either to the right or left
How can a buffer solution lose its buffering ability?
1) when acids and alkalis are added to a buffer, the two components in the buffer solution react and will eventually be used up
2) as soon as one component has all reacted, the solution loses its buffering ability towards acids or alkalis - as the
3) as the buffer works, pH does change but only by a small amount - it does not stay constant
What controls the pH in an acid buffer solution?
- The conjugate acid-base pair HA/A- in an acid buffer solution controls the pH
- This control can be explained by shifts in equilibrium position
Explain what happens when acid (H+) is added to a buffer solution
1) [H+] increases
2) H+ ions react with the conjugate base A-
3) ∴ equilibrium shifts to the left, removing most of the H+ ions - the conjugate base removes the added acid
Explain what happens when alkali (OH-) is added to a buffer solution
1) [OH-] increases
2) the small [H+] reacts with the OH-, decreasing the [H+]
3) HA dissociates, shifting the equilibrium position to the right to restore most of the H+ ions
How does the weak acid used in a buffer solution affect the buffer solution?
Different weak acids result in buffer solutions that operate over different pH ranges
When is a buffer most effective a remove either added acid or alkali?
When there are equal concentrations of the weak acid and its conjugate base in the buffer solution
What happens to the pH of a buffer solution when [HA]=[A-]?
- Ka = [H+] ∴ the pH of the buffer solution = the pKa value of HA (pH=pKa)
- The operating pH is typically over about 2 pH units, centred at the pH of the pKa value
- The ratio of concentrations of the weak acid and its conjugate base can then be adjusted to fine-tune the pH of the buffer solution
If the pKa of CH3COOH is 4.76, what is the typical operating pH range of its buffer solution?
3.76 to 5.76
How do you calculate the [H+] for a buffer solution?
- [H+] = Ka x [HA]/[A-] ([salt])