bromination, epoxdation, dihydroxylation Flashcards

1
Q

what is the stereochemistry of additions

A

the sp2 centre can be attacked by nu from either top or bottom forming enantiomers in racemate, no difference between them so no energetic preference

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2
Q

why is only trans product formed when mixing an alkene with bromine water

A

bromonium ion is formed forming other Br atom to the opposite side.
Bromonium ion - positive ion formed where 1 Br bonds to both C atoms of double bond.
Can also be argued to be due to sterics

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3
Q

describe formation trans Bromine product

A

Alkene pi orbital attacks sigma* on Br2 , Br-Br bond broken, forming Bromonium ion,
Nu attacks electrophile, opening the bromonium ion. Br nu orbital attacks C-Br sigma*, opening C-Br bond-forming dibromide products.
Backside attack as Br atom must come in from opposite side to C-Br bond.

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4
Q

how can bromonium ions be intercepted

A

with suitable nucleophilic solvent eg MeOH, opens up ion attacks more substituted position
NUCLEOPHILE ATTACKS MOST SUBSTITUTED END OF BROMONIUM ION

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5
Q

what is the stereospecificity of E and Z alkene bromination

A

E - meso products (mirror plane not chiral)

Z - forms racemate enantiomers chiral with no mirror image.

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6
Q

what is an epoxide

A

a three membered ring containing O which can be isolated in contrast to bromonium
Are electrophiles which are opened by nu and quenched by water forming anti product

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7
Q

what makes epoxide more reactive than an ethee

A

Ring strain

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8
Q

how are epoxides formed

A

electron-rich alkenes react with peroxy acid in concentrated syn addition
more electron rich alkenes are epoxidized faster.

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9
Q

what is the process of dihydroxylation

A

Alkene reacts with OsO4 osmium tetroxide in concerted (single step) syn cycloaddition giving 1,2-diols after hydolysis

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10
Q

what are the issues with OsO4

A

toxic and volatile

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