Book 1 - Year 11 Flashcards

1
Q

Complete the square

x² - 2x - 16

A

(x - 1) ² - 17

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Complete the square

3x² + 2x - 4

A

3(x + 1/3)² - 13/3

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

What is the name of the u or n shape on a quadratic graph?

A

Parabola

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Find the turning point of

-2x² + 4x - 1

A

( 1, -1)

[the completed square -2(x - 1)² + 1]

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Solve as a surd

x² - 10x - 5 = 0

A

x = 5 +/-√30

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Solve to 2 dp

x² + 2x - 9 = 0

A
x = 2.16
x = -4.16
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

What is the discriminant?

A

b² - 4ac

the section under the √ in the quadratic formula

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

How many roots does a positive discriminant suggest?

A

2 solutions/ roots

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

How many roots does a negative discriminant suggest?

A

0 solutions/ roots

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

How many roots does a discriminant that equals 0 suggest?

A

1 solutions/ roots

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Find the discriminant of the equation x² + 3x + 5 = 0 and explain what it tells you

A

0=[(3)²-4(1x5)]
=-11
it is a negative discriminant meaning that there are no real solutions

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Find the discriminant of the equation 25x² - 30x + 9 = 0 and explain what it tells you

A

0=[(-30)²-4(25x9)]
=0
the discriminant =0 meaning there is 1 possible solution

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Find the discriminant of the equation 3x² + 2x - 4 = 0 and explain what it tells you

A

0=[(2)²-4(3x-4)]

=52it is a positive discriminant meaning there are 2 possible solutions

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Show that x² - 12x + 40 > 0 for all real values of x

A
= x² - 12x + 40
= (x - 6)² + 4 
(x - 6)² ≥ 0
Therefore (x - 6)² + 4 ≥ 4
Therefore x² - 12x + 40 > 0 for all real values of x QED
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

[Show that x² - 12x + 40 > 0 for all real values of x
(x - 6)² + 4
(x - 6)² ≥ 0
x - 6)² + 4 ≥ 4]
What does this tell you about the graph of y = x² - 12x + 40?

A

(Draw the graph)

The graph doesn’t cross the x axis and therefore there are no real solutions

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Find the values of k for which 2x² + kx + 25/8 = 0 has real roots

A
2x² + kx + 25/8 = 0 
16x² + 8kx + 25 = 0 
a = 16
b = 8k
c = 25
(8k)² - 4(16 x 25) ≥ 0
64k² - 1600 ≥ 0
(k + 5) (k - 5)  ≥ 0
Draw a graph of the discriminant (with roots 5 and negative 5)
ANSWER:
k ≥ 5
k ≤ -5
17
Q

Find the values of k for which 2x² + kx + 25/8 = 0 has no real roots

A
2x² + kx + 25/8 = 0 
16x² + 8kx + 25 = 0 
a = 16
b = 8k
c = 25
(8k)² - 4(16 x 25) < 0
64k² - 1600 < 0
(k + 5) (k - 5)  < 0
Draw a graph of the discriminant (with roots 5 and negative 5)
ANSWER:
-5 < k < 5
18
Q

What is the fastest way to find the x-coordinate of the turning point if you have the roots?

A

Find the midpoint of the roots

19
Q

What are the other names for turning point?

A

Stationary point

Maximum/ Minimum point

20
Q

Find the y-intercept, roots and turning point of the graph y = x² + 8x - 65 by completing the square

A
y = (x + 4)² - 16 - 65
y = (x + 4)² - 81
tp: (- 4, -81)
0 = (x + 4)² - 81
81 = (x + 4)² 
\+/-9 = x + 4
- 4 +/- 9 = x
x = 5
x = -13
roots = ( 5, 0) and ( -13, 0)
y intercept = ( 0, -65)
21
Q

Find the y-intercept, roots and turning point of the graph y = x² + 10x + 16 by factorising

A
y = x² + 10x + 16 
y = (x + 8) (x + 2)
x = -8
x = -2
roots = ( -8, 0) and ( -2, 0)
(-8 + -2) ÷ 2= -5
(tp:(-5, y))
y = (-5)² + 10(-5) + 16 
y = 25 - 50 + 16
y = -9
tp: ( -5, -9)
y intercept = 16
22
Q

Describe how the intersection method works to solve quadratics?

A

You find the difference between the graph they have drawn and the one you need to solve and draw the line of the difference
(This is where the x axis would be on your graph)
The intersects are the solutions

23
Q

How would you complete the intersection method for x² -9x - 10 = 0 if you have a graph of y = x² - x - 10

A

y = x² - 8x - 10
0 = x² -9x - 10 (subtract these from each other)
__________
y = x
you would draw the line y = x onto the graph they have given
where both lines intersect is the solution