Block 2 Flashcards

1
Q

Absolute value inequality form [A] < c is equivalent to:

A
  • c < A < c

”(-) negative c is LESS THAN A which is LESS THAN c”

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2
Q

Absolute value inequality form [A] = c is equivalent to:

A
  • c = A = c

”(-) negative c is LESS than or EQUAL to A which is LESS than or EQUAL to c”

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3
Q

Absolute value inequality form [A] > c is equivalent to:

A

A < - c
“A is LESS THAN (-) negative c”

OR

A > c
“A is GREATER THAN c”
(duh this is the form given just without the absolute value)

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4
Q

Absolute value inequality form [A] >/= c is equivalent to:

A

A = -c
“A is LESS than or EQUAL to (-) negative c”

OR

A >/= c
“A is GREATER than or EQUAL to c”
(duh this is the form given just without the absolute value)

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5
Q

What is an Absolute Value?

A

The distance from 0 on the number line

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6
Q

[u] < k is equivalent to:

A
  • k < u < k
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7
Q

[u] > k is equivalent to:

A

u < -k

OR

u > k (the form given)

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8
Q

What form will you give your answer in if it says Interval Notation?

A

The ( , ) or [ , ] to determine inclusive or not

With infinities if needed

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9
Q

y = f(x)
How are you going to transform it to:
y = af(x)

A
  • Multiply y-coords by a

This will result in VERTICAL stretching/shrinking

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10
Q

y = f(x)
How are you going to transform it to:
y = f(ax)

A
  • Divide x-coords by a

This will result in HORIZONTAL stretching/shrinking

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11
Q

y = f(x)
How will you reflect it to:
y = - f(x)

A

Reflect over the x-axis

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12
Q

y = g(x)
How will you reflect it to:
y = g(-x)

A

Reflect over the y-axis

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13
Q

What is the formula for finding DISTANCE between two points on a graph?

A

d = Square root of:

(x2 - x1)^2 + (y2 - y1)^2

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14
Q

What is the formula for finding the MIDPOINT of a segment?

A

(x1 + x2 / 2 , y1 + y2 / 2)

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15
Q

What is the standard equation of a circle?

A

(x - h)^2 + (y - k)^2 = r^2

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16
Q

If you are given the Center and Radius of a circle, how will you find the Circle’s Equation?

A

Plug and chug (h , k) and r

(x - h)^2 + (y - k)^2 = r^2

17
Q

Find the equation of a circle if it’s Center is (-6, -2) and it passes through (4, -5)

A

Plug and chug (x - h)^2 + (y - k)^2 = r^2

Get r = square root of 109
When you plug that is the square root and power of 2 cancel, so you just get 109 for the radius

(x+6)^2 + (y+2)^2 = 109