Biology Flashcards

1
Q

Explain how a leaf and its cells are adapted for photosynthesis

A

Broad and Flat - Large surface area to trap more energy

Palisade Cells - These are packed with chloroplasts to trap sunlight energy

Leaf Stomata - Microscopic pores allow for gas exchange

Guard Cells - Controls the Opening/Closing of the Stomata

Thin Cells - Reduces diffusion pathway for gas exchange

Spongy Mesophyll Tissue - Contains air spaces which increase the rate of gas exchange

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2
Q

Explain the effect of removing a prey from a food web on predator populations

A
  • By removing their prey, there isn’t enough food for the predators to hunt, therefore they will begin to starve and population will subsequently decrease
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3
Q

Explain the effect of removing a predator from a food web on prey populations

A
  • By removing predator from a population, the population of prey will therefore increase as they will be hunted less.
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4
Q

Devise a method to determine the population of a named organism in a garden

A

<span><b><u>CORRECT WAY </u></b></span>(this way was in the revision guide… makes more sense in my head)

Take a 1m x 1m quadrat and place it in the selected region

  • Count the number of (organism) in the square.
  • Repeat with a different square 4 times, and average the 5 results.
  • Multiply the average by (total area) to estimate the number of (organism) in the field.
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5
Q

Explain how organisms in a food chain of a garden contribute to the carbon cycle

A
  1. Plants respire and photsynthesise both releasing and taking in carbon
  2. Animals feed off plants taking in carbon to their biomass and release it through respiration
  3. When organisms die, their biomass is compressed into fossil fuels which release carbon through combustion
  4. Soft tissue in the dead organism is eaten by decomposers which release carbon through respiration
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6
Q

Explain how fertlisiers increase the nitrate content of the soil

A
  • Fertilisers, like manure or compost, recycles the nutrients left in plant animal waste and returns them to the soil through decomposition.
  • Note that proteins and urea are present in animal excretion, which can be broken down (by soil bacteria) into ammonia, then converted into useful nitrates by nitrifying bacteria.
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7
Q

Explain why bacteria are important for soil fertility

A
  • Bacteria is a decomposer - it releases nitrogen compounds together with carbon compounds when they decompose dead plants and animals and their wastes.
  • Therefore, they release nitrogen which is required for soil fertility.
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8
Q

Explain how crop rotation can increase the nitrogen content in the soil

A
  • Rotating which crops are planted when in a certain area.
  • This means that the root nodules of one plant rotation make the soil more fertile and useful for the next crop planted increasing the next crop’s yield
  • Furthermore, the root nodules of a plant contain nitrogen-fixing bacteria, which convert nitrogen gas in the air into nitrogen compounds in the soil.
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9
Q

Describe the different roles of bacteria in the nitrogen cycle

A
  • Nitrogen, from the air, is taken into the plant by nitrogen-fixing bacteria
  • The plant then uses this nitrogen to make proteins
  • Animals eat the plant, and these proteins contribute to animal biomass, as amino acids. (note that excess amino acids = urea)
  • Excretion and Death of these animals returns these animal proteins and urea to the soil, where decomposing bacteria breaks down proteins and urea and turs them into ammonia.
  • Then nitrifying bacteria turns ammonia in decaying matter into nitrates.
  • Sometimes, denitrifying bacteria can turn nitrates back into nitrogen gas
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10
Q

Why do organisms need to respire?

A

All living things respire because they need energy for

  • Moving
  • Keeping Warm
  • Producing and Breaking Down Substances
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11
Q

Explain the importance of sweating in thermoregulation of body activities

A
  • Sweating is crucial in the body’s response to hyperthermia or fever
  • Sweat glands secrete a layer of sweat onto the epidermis, this layer of sweat then evaporates, transferring energy from the skin to the environment.
  • Therefore, the body’s temperature cools down.
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12
Q

Explain the importance of thermoregulation in homeostasis

A

Homeostasis is the maintenance of the body’s internal conditions

Thermoregulation is the control of the body’s internal temperature at 37 degrees

Therefore, thermoregulation is just one crucial aspect of homeostasis.

Maintaining a constant body temperature is important because:

  • Enzymes in the body, that catalyse many reactions in the body, have an optimum temperature at which they work best
  • Straying too far from this optimum temperature can cause the enzymes to denature (if temp is too high) or become inactive (if too low)
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13
Q

Explain how Xylem tissue is adapted to it’s function:

(also state it’s function)

A

XYLEM:

FUNCTION: To transport water and mineral ions

  1. Thick cellulose cell walls strengthened by lignin prevents it from bursting due to the water pressure.
  2. Lignin kills the xylem cells, this ensures no water is used up in cell processes.
  3. End walls are also broken to create one long tube, so water flow isn’t impeded.
  4. Xylem cells have no subcellular structures e.g cytoplasm, nucleus, vacuole or chloroplasts so the path of water isn’t obstructed.
  5. Tiny pores allow water and mineral ions to enter and leave the xylem vessels
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14
Q

Explain how phloem tissue is adapted to it’s function

(also state it’s function)

A

FUNCTION: To translocate sucrose made from the glucose and starch in photosynthesis.

ADAPTATIONS:

  1. No nucleus or little cytoplasm as they aren’t needed and would be a waste of energy. They create more room for the central channel
  2. Companion cells to pump have many mitochondria so they have energy to actively transport sucrose
  3. Pores through whcih sucrose solution can be pumped
  4. Holes in the end walls allow liquids to flow from one sieve cell to the next
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15
Q

Describe how transpiration occurs

A
  • Transpiration is the loss of water vapour from the leaves and stems of the plant. It is a consequence of gaseous exchange, as the stomata are open so that this can occur.
  1. Water evaporates at the open stomata (pores) on the leaf surfaces
  2. As water molecules are attracted to each other, when some molecules leave the plant the rest are pulled up through the xylem
  3. This results in more water being taken up from the soil resulting in a continuous transpiration stream through the plant
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16
Q

Explain the causes and treatment of diabetes, both:

1) Type 1
2) Type 2

A

TYPE 1 DIABETES:

CAUSES : Pancreatic cells don’t produce insulin as they have been destroyed by the body’s immune system

This means they cannot control blood glucose levels naturally

TREATMENT : A type 1 diabetic would have to inject insulin into the fat layer below the skin to reduce blood glucose levels

TYPE 2 DIABETES:

CAUSES: Insulin releasing cells don’t produce enough insulin or target organs don’t respond to insulin

TREATMENT: Lifestyle changes, such as a diet or exercise, to naturally reduce your blood glucose concentration. Some type 2 diabetics may take drugs to make organs respond to insulin

17
Q

Explain how the structure of the nephron allows filtration

A

Blood flows through a network of capillaries (glomerulus) in the bowman’s capsule

Here, the smaller molecules (water urea glucose) move into the nephron while larger particles (protein blood cells) stay

ADAPTATIONS:

  • This can happen as there are microscopic pores in the glomerulus, which allow these smaller molecules to pass through whilst the larger particles stay.
  • The afferent arteriole has a much larger diameter than the efferent arteriole, which causes a build up of pressure in the glomerulus.

*

18
Q

Explain how the structure of the nephron supports reabsorption of glucose

(adaptations of the nephron for selective reabsorption of glucose)

A
  • Selective Reabsorption of Glucose happens at the proximal convulated tubule and the distal convulated tube.

ADAPTATIONS:

  1. There is a large surface area of contact between the nephron and capillaries
  2. The cell membrane of the cells lining the first convoluted tubule has tiny folds called microvilli. These increase the surface area:volume ratio of the cells.
  3. Cells that have protein pumps in their cell membranes contain many mitochondria
19
Q

Explain how the structure of the nephron supports reabsorption of water

A

Water is selectively rebsorbed at the loop of Henle and the collecting duct

ADAPTATIONS:

  • Collecting duct is thin and permeable to allow water to move by osmosis back into the blood
20
Q

What does urine contain and how is urea formed?

A
  • Urine contains excess water, excess glucose and urea.

Urea is formed from the breaking down of amino acids in the liver.

21
Q

Explain how clomifene is used to stimulate ovulation

A
  • Clomifene is a drug, containing LH and FSH
  • This is used in infertility treatment, it increases the concentration of LH in the women, which promotes ovulation.
22
Q

Explain how hormones are used in IVF treatment

A
  • Egg follicle maturation is stimulated by hormones, LH and FSH
  • Eggs are released by many follicles and they are taken from the ovary
  • Sperm cells are taken from the man
  • The egg cells and sperm cells are allowed to combine in a petri dish for fertilisation
  • One or two healthy embryos are re-inserted into the uterus
23
Q

Describe how changes in hormones affect:

1) The Uterus Wall
2) Ovulation
3) Menstruation

A
  1. The Uterus Wall - Thickens as a result of oestrogen being produced. This thickness is maintained through the release of progesterone.
  2. Ovulation - This is triggered by a spike in LH around day 14
  3. Menstruation - This is triggered by the falling levels of oestrogen and progesterone, which reveal to the body that fertlisation hasn’t occured.
24
Q

Explain how oestrogen, progesterone, FSH and LH interact in the menstrual cycle

A
  1. Days 1-5ish: Menstruation is when the lining of the uterus breaks down and is lost with an unfertilised egg Levels of FSH here begin to increase.
  2. Days 10-12ish: The uterus lining starts to thicken again FSH increases, which stimulates the production of oestrogen from the ovaries. This is what causes the uterus lining to thicken again.
  3. Days 13-15: The new egg is released from the ovary (ovulation) Oestrogen inhibits the production of FSH, but stimulates the production of LH from the pituitary gland. This spike in LH triggers ovulation around day 14.
  4. Days 16-28: Uterus lining continues to thicken Following ovulation, a bundle of cells is left behind in the ovaries called the corpeus luteum. This releases progesterone, which inhibits production of both LH and FSH.
  5. Day 23ish: The egg cell travels along the oviduct to the uterus
  6. Falling levels of Progesterone and Oestrogen towards the end of the cycle trigger menstruation
25
Q

State the equation that relates cardiac output, stroke volume and heart rate

A

Cardiac Output = Stroke Volume x Heart Rate

26
Q

Compare the variation in stroke volumes fo an Olympic athlete and an officer worker

A
  • Stroke volume is the volume of blood pushed into the aorta in each beat.
  • Regular exercise increases the strength of heart muscle and ventricle size.
  • Therefore, fitter people, like the Olympic athelete, will have bigger stroke volumes and their hearts can beat more slowly to achieve the same cardiac output as a less fit person.
27
Q

Describe the flow of blood through the heart

A
  • Deoxygenated blood from the body enters through the vena cava
  • This leaves the heart through the pulmonary artery, to the lungs where it will become oxygenated
  • Then, it reenters the heart through the pulmonary veins.
  • When the top chambers (atriums) are full, the muscles around them contract to push blood into the ventricles.
  • The muscles in the ventricle walls then contract, forcing blood out of the heart.
28
Q

Explain adaptations of the heart for pumping blood around the body

A
  • When certain parts of the heart contract, valves close to stop blood flowing the wrong way
  • The left ventricle has a thicker muscle wall, contracting more strongly from the right. This allows it to pump blood into the aorta, and therefore to the entire body. Whereas, the right ventricle doesn’t need a wall that thick as it only pumps blood to the lungs.
29
Q

Describe adaptations of the lungs for gas exchange

A
  • The lungs contain millions of alveoli (air sacs) which increase the surface area and so increase the rate of gas exchange
  • These alveoli have a thin cell membrane which reduces the diffusion pathway for gases
  • They also have a large point of contact with blood capillaries, which also increases the area in which gases can be exchanged
30
Q

Explain the importance of surface area:volume ratios in the breathing systems

A
  • A larger SA:V ratio means a substance has more surface area per unit volume
  • The larger a cell’s surface area, the more of a substance can diffuse in and out of it in a certain time.

However, larger organisms tend to have smaller SA:V volume ratios, therfore a cell can’t get enough raw materials fast enough. Therefore, larger organisms have organs that move substances in and out of the body.

Furthermore, SA:V ratios are used in alveoli, they have a large SA:V volume ratio, increasing the surface area and increasing the rate of gas exchange.

31
Q

Describe the factors affecting the rate of diffusion:

A
  1. Surface Area - A larger surface area means more space which particles can pass, therefore the overall rate of diffusion will increase if surface increases
  2. Concentration Gradient - The bigger the difference in concentrations, the steeper the concentration gradient and the faster the rate of diffusion
  3. Distance - The further the particles have to diffuse, the slower the rate of diffusion
32
Q

State Fick’s Law

A

rate of diffusion ∝ (surface area x concentration difference) / thickness of membrane