Biologia Spellbook Flashcards
In eukaryotes, the ultimate yield of ATP from NADH is lower when the NADH is produced by:
A) Glycolysis
B) Pyruvate Dehydrogenase Complex
C) Krebs Cycle
D) Electron Transport and Oxidative Phosphorylation
(A) because in order for the NADH produced during glycolysis to be utilized by the ETC in ATP formation, the electrons must be shuttled into the mitochondria. When shuttled in, the electrons are typically used to reduce Coenzyme Q and bypass NADH dehydrogenase. This results in pumping of fewer protons out of the mitochondrial matrix, and ultimately in fewer ATP being formed.
Some inhibitors bind irreversibly to enzymes by covalent attachment. Would the kinetics seen under these conditions (V vs [S] curve) be similar to those seen with a reversible noncompetitive inhibitor?
A) Yes, because it would reduce the Km of the reaction
B) Yes, because the net effect would be a loss of active enzyme available for the reaction
C) No, because if enough substrate binds to the active site the reaction will reach Vmax
D) No, because Km will increase and Vmax will stay the same, similar to competitive inhibition
(B) An irreversible inhibitor will permanently deactivate the enzyme, reuducing effective enzyme concentrations.
Some enzymes can modify their substrate and by this means, regulate its activity. In many instances, these modifications are not permanent since other enzymes can reverse them. Which of the following categories of enzymes will irreversibly modify their substrate?
A) A kinase
B) A protease
C) A phosphatase
D) An acetylase
(B) Proteases are enzymes that cleave their substrates at specific sites, permeantnly removing part of the protein. A kinase adds a phosphate to its substrate, which can be removed by a phosphatase and an acetylase will add an acetyl group which can be removed.
A common cause of strep throat is a Streptococcal pharyngitis infection. When S. pharyngitis undergoes aerobic cellular respiration, which of the following regions would have the lowest pH?
A) Matrix of the mitochondria
B) Intermembrane space of the mitochondria
C) Cytoplasm
D) Extracellular
(D) Prokaryotes do not have any membrane bound organelles such as mitochondria, so the protons return to the cytoplasm through the ATP synthase on the plasma membrane, thereby producing ATP. Thus, the most acidic place is outside the cell.
Salicyclic acid (aspirin) if taken in excess may act as an uncoupling agent. Uncoupling agents increase the permeability of the inner mitochondrial membrane, resulting in the dissipitation of the proton gradient. Which of the following would most likely be true in the presence of an uncoupling agent?
A) Electron transport at the inner mitochondrial membrane would cease
B) The energy from the proton-motive force would likely be dissipitated as heat rather than in producing ATP from ADP
C) H+ ions would flow through the inner membrane into the intermembrane space
D) There would be an increase in biosynthesis
(B) The proton gradient obtained by the electron transport chain is necessary in order to create ATP by the ATP synthase. This unharnessed energy would be dissipirated into heat, and since the ions would pass through the ATP synthase, less ATP would be created.
For a given enzyme concentration at a low substrate concentration, how does reaction rate change as the substrate concentration increases?
A) Logarithmically
B) Linearly
C) Exponentially
D) Indirectly
(B) At low substrate concentrations, the reaction rate increases linearly as the substrate concentration increases. Near saturation, the reaction rate begins to level off and does not change regardless of how much substrate it added.
A new enzyme inhibitor for Enzyme X has been discovered. Keeping the enzyme concentration constant, experiments show that the addition of large amounts of substrate causes the enzyme-substrate-inhibitor reaction to occur at the same maximum reaction rate as an enzyme substrate reaction. This is because:
A) The inhibitor binds at the active site and the addition of large amounts of substrate out-competed the enzyme inhibitor via noncompetitive inhibition
B) The inhibitor binds at an allosteric site and the addition of large amounts of substrate out-competed the enzyme inhibitor via noncompetitive inhibtion
C) The inhibitor binds at the active site and the addition of large amounts of substrate out-competed the enzyme inhibitor via competitive inhibition
D) The inhibitor binds at an allosteric site and the addition of large amounts of substrate out-competed the enzyme inhibitor via competitive inhibition
(C) The question states that large amounts of substrate added can out-compete the inhibitor and result in the same Vmax which is characteristic of competitive inhibition. Then, the inhibitor only binds at an active site. Noncompetitive inhibition occurs when an enzyme inhibitor binds to an allosteric site.
Which of the following is NOT an example of feedback inhibition?
A) The effect of estrogen on luteinizing hormone one week before ovulation
B) The effect of high serum calcium on parathyroid hormones
C) The effect of estrogen on luteinizing hormone one day before ovulation
D) The effect of cortisol on ACTH
(C) During the early stages of the menstrual/ovulatory cycle, lower levels of estrogen inhibit the release of luteinizing hormone. However, as ovulation approaches, high levels of estrogen stimulate the release of luteinizing hormone. High serum calcium inhibits parathyroid hormones and cortisol inhibits ACTH.
Carbon dioxide is an allosteric inhibitor of the formation of oxyhemoglobin. Which of the following best describes its effects on the binding of oxygen to hemoglobin?
A) It decreases the affinity of hemoglobin for oxygen and shifts the oxygen dissociation curve to the left
B) It decreases the affinity of hemoglobin for oxygen and shifts the oxygen dissociation curve to the right
C) It increases the affinity of hemoglobin for oxygen and shifts the oxygen dissociation curve to the left
D) It increases the affinity of hemoglobin for oxygen and shifts the oxygen dissociation curve to the right
(B) An inhibitor of the formation of oxyhemoglobin would have to decrease the affinity of hemoglobin for oxygen and lowered affinity means that the hemoglobin will be less saturated so a right-shifted curve is correct.
Protein phosphatases regulate the activity of metabolic pathways by:
A) proteolytic cleavage
B) allosteric regulation
C) constitutive activity
D) covalent modification
(D) A protein phosphatase removes a phosphate from a protein; this is a covalent modification.
Carbon monoxide is a competitive inhibitor of the formation of oxyhemoglobin. Which of the following best describes its effects on the binding of oxygen with hemoglobin?
A) It binds to the active site and it decreases Vmax
B) It binds to an allosteric site and it decreases Vmax
C) It binds to the active site and it has no effect on Vmax
D) It binds to an allosteric site and it has no effect on Vmax
(C) Competitive inhibitors bind to the active site of enzymes. Competitive inhibitors reduce V, but do not affect Vmax.
A competitive inhibitor of eukaryotic RNA polymerase III would have the greatest effect on:
A) replication
B) reverse transcription
C) translation
D) mutation
(C) RNA polymerase II transcribes tRNA which then carries amino acids to ribosomes for use in translation . Thus, polymerase plays no role in replication and reverse transcription. Blocking the action of this enzyme would not alter the base sequence, so mutation would not be affected.
In the lac operon, transcription is regulated by a repressor protein and only takes place in the presence of lactose. Which of the following statements is correct?
A) The repressor protein binds to the promoter site to inhibit transcription
B) Lactose binds to the promoter site to initiate transcription
C) Lactose binds to the repressor protein to inhibit transcription
D) The repressor protein binds the operator site to inhibit transcription
(D) The lac operon includes an operator site to which the repressor protein binds. The operator protein is located between the promoter region and the start transcription site. When the repressor is bound, RNA polymerase cannot move forward to the start site, thus transcription is inhibited. Lactose binds to the repressor protein at an allosteric site, causing a conformational change so that the repressor protein can no longer bind to the operator so RNA polymerase can move forward to the start site and transcription will occur.
Which of the following could not be caused by a single point mutation in the DNA?
A) Ala-Gln-Cys-Asp-Leu -> Ala-Gln
B) Ala-Gln-Cys-Asp-Leu -> Ala-Gln-Cys-Asp-Leu
C) Ala-Gln-Cys-Asp-Leu -> Ala-Gln-Cys-His-Lys
D) Ala-Gln-Cys-Asp-Leu -> Ala-Gln-Cys-His-Leu
(C) A point mutation is a single base pair substation. There are few possibilities that can result if a single base is substituted. If the new codon is now a STOP codon, the polypeptide will be truncated—which is a point mutation. If the new codon codes for the same amino acid before the mutation, then the silent mutation has occurred and no change will be seen (Choice B). If the mutation leads to a single new amino acid, then a missense point mutation has occurred (Choice D). There was a frameshift mutation, which can come from a single point mutation.
Which DNA base pair requires the most energy to break?
A) A-T
B) C-A
C) G-C
D) U-A
(C) Guanine and cytosine base pairs involve three hydrogen bonds whereas adenine and thymine only involves two hydrogen bonds.
Which of the following is NOT a similarity between replication and transcription
A) Both processes occur with the same fidelity
B) Polymerization in both processes is based on reading a template
C) A pyrophosphate is removed from every nucleotide as polymerization occurs
D) Both processes occur in the 5’ to the 3’ direction
(A) Because RNA polymerases do not proofread, transcription is less accurate. DNA polymerase moves along in the 3’ to 5’ direction while the new chain is made in the 5’ to the 3’ direction.
Telomeres are guanine-rich caps on the ends of each chromosome. Which of the following is the most likely function of a telomere?
A) High guanine content stabilizes parental strands to prevent excess tension during DNA unwinding
B) Protect the ends of the chromosomes from damage due to incomplete replication
C) Provide a site for helicase attachment
D) Seal the gaps left by Okazaki fragments in the lagging strand
(B) Because DNA polymerase can only elongate DNA from a primer, the ends of the lagging strands do not replicated. Thus, with each round of replication, the chromosomes get shorter. Once the telomere are shortened, the cells enter senesces (hibernation) and are marked for destruction.
Which of the following has 3’ to 5’ exonuclease activity but NOT 5’ to 3’ exonuclease activity
A) DNA pol III
B) DNA pol I
C) RNA pol II
D) RNA pol III
(A) RNA polymerases do not have exonuclease activity because they do not proofread, and DNA polymerase I has both exonuclease activities.
Which of the following physiological responses would be expected to occur in a patient with a severe peanut allergy?
I. Vasodilation
II. Reddening of the skin and increased skin temperature
III. Increased glomerular filtration
I and II. Vasodilation is where the vessels constrict in order to increase the temperature of the body as the blood cannot flow to cool off.
A person with a known allergy to Brazil nuts inadvertently ingests some of these nuts. Which of the following would be expected within 3 hours of the ingestion?
I. Levels of epinephrine would increase in the blood
II. Levels of glucose would increase in the blood
III. Levels of glucagon would decrease in the blood.
II and III. Ingestion of carbohydrates increases glucose levels in the blood and decreases glucagon levels in the blood.
Ribozymes and Enzymes differ principally in what way?
Ribozymes are built from nucleic acids while enzymes are built from amino acids.
Does this part of the passage refer to the innate or adaptive immune system?
“This is the first layer that a pathogen will encounter in the human body. This system consists of macrophages, mast cells, leukocytes, and other cell types. These cells provide an imediate, but generally nonspecific response to a pathogen. As such, there is no immunological memory of a pathogen the body was previously exposed to.”
Innate immune system.
Does this part of the passage refer to the adaptive or innate immune system?
“This system provides a more specific response to the pathogen. Due to the necessary alteration in gene expression, this immune response results in a time delay between pathogen exposure and maximal immune response. This immune system provides an immunological memory for pathogens to which the body was previously exposed. This immunological memory has been hypothesized to be a cause of sensitization in exposure to allogens.”
Adaptive immune system.
In which of the following individuals would the removal of the thymus have the most deleterious effect on the individual’s immune system?
A) A 5 year old child
B) A 35 year old man
C) A 35 year old woman
D) A 55 year old woman
(A) The thymus is critical for development of the immune system in children and adolescents. The thymus atrophies after adolescence. Thus, removal of the thymus in a 5 year old child will affect that child’s immune system the most.
Although rare, exposure of the fetus to teratogens results in compromised neuronal development and may lead to premature neuron death. This premature death often triggers paralysis of muscles. In which layer of the embryo must the teratogen act for this to occur?
Ectoderm, where the nervous system development occurs.
Surgical treatment to move the ulnar nerve to reduce pinching must involve cutting which structure?
A) epiphysis of the ulna bone
B) smooth muscle of the forearm
C) tendon and smooth muscle of the forearm
D) fibrous connective tissue
(D). To reach the ulnar nerve, fibrous connective tissue must be cut. Fibrous connective tissue holds the ulnar nerve in place. Epiphysis of bones (growth plate) would not be cut. Smooth muscle would only be cut if an artery needed to be cut.
Conn’s syndrome is characterized by excessive levels of aldosterone, which normally stimulates Na+ reabsorption from the proximal convoluted tubules of the kidneys. How would blood volume and pressure change in Conn’s syndrome?
Excessive aldosterone levels will cause high Na+ levels which will increase blod volume and pressure by its osmotic effects.
Cellular repolarization in neurons is most correctly described by which of the following statements?
A) Na+ ions move out of the cell
B) Na+ ions move into the cell
C) K+ ions move out of the cell
D) K+ ions move into the cell
(C) Depolarization results from soidum ions moving into cells and repolarization from potassium moving out of the cell.
One of the reasons why the HIV virus selectively attacks CD4+ T lymphocytes as opposed to other cell types may be that:
The HIV virus displays the CCR5 receptor necessary for HIV to enter the cell.
Discuss the difference in mitochondria levels in a cancer cell and a normal cell.
A cancer cell has a higher metabolic rate than a normal cell, so it is expected to have a higher number of mitochondria to supply its energy. The cancer cell also shows a decreased time for its cell cycle as it reproduces faster.
During which phases of the cell cycle do mitochondria increase in number?
S, G1, and G2
Radioactive glucose will be absorbed the most by which of the following cell types?
A) Epithelial cell
B) Sarcomere
C) Pancreas cell
D) Schwann cell
(B) A sarcomere is a cell of the skeletal muscle system that needs large amounts of glucose for proper contraction.
Distinguish between the function of the smooth and rough endoplasmic reticulum.
Lipid production (smooth) and protein production (rough)
What is the site of the electron transport chain within the eukaryotic cell?
Inner mitochondrial membrane
Which of the following is correct about the human female reproductive cycle?
A) On day 14 of the menstrual cycle, an FSH surge occurs
B) The number of primary oocytes does not change after birth
C) Oogonia start dividing only after birth to create oocytes
D) Oocytes start dividing immeidately after birth to create oogonia
(B) Oocytogenesis is the process by which primordial follicles develop into oogonia which then divide between fertilization and birth to create primary oocytes. These begin mitosis but remain halted in prophase I. The process restarts at menarche, when a few of the oocytes continue development. On Day 14, a LH surge occurs, not FSH
Which of the following is an example of the skins role in the immune system?
A) Erector pili muscles controlling hair
B) Sensory nerve cells at various levels
C) Stored fat cells
D) Langerhans cells
(D) Langerhands cells are involved in processing microbial antigens
It turns out that alcoholics, who often have limited glycogen stores, can also suffer from ketoacidosis. Of note, the enzyme used to metabolize ethanol also reduces a molecule of NAD+ to NADH. Why might alcoholics be susceptible to ketoacidosis?
Ketoacidosis occurs as a result of increase ketone synthesis from Acetyl CoA. Increased ketone synthesis is stimulated by the absence of insulin in untreated Type I Diabetics. Impaired gluconeogenesis will result in low blood sugars and stimulate the hormone glucagon, which, in turn, will stimulate fatty acid oxidation that will result in accumulating Acetyl CoA and eventually ketone production.
Cyanide poisoning can be deadly. What is a plausible reason for why taking barbiturates is not toxic if it also inhibits part of the electron transport chain?
FADH2 can still donate electrons at Complex II with barbiturate poisoning
An inhibitor of Complex II would cause (three things):
- Impaired oxidative phosphorylation
- Potential damage to cells from reactive oxygen species
- A build-up of FADH2
Although Complex II doesn’t directly contribute to the proton gradient, it is decreasing electron flow to the downstream complexes (III and IV) that DO contribute to the protein gradient. Therefore, the proton gradient will decrease (it has to for ATP production to decrease as well). Note that a build-up in oxygen that normally is reduced by electrons in Complex IV will cause an increase in reactive oxygen species. Also note FADH2 can’t donate its electrons to Complex II anymore and therefore will not be re-oxidized to FAD.
A spirometer is used to measure a lung vital capacity at 4800 mL. Total lung capacity is estimated at 6000 mL. The difference between the two measurements reflects:
A) tidal volume
B) expiratory reserve volume
C) inspiratory reserve volume
D) residual volume
(D) Vital capacity is the maximum volume of air that can be moved into and out of the lungs. Residual volume refers to the amount of air left in the lungs after maximum exhalation. Total lung capacity is the vital capacity plus the residual volume.
A patient with osteoporosis would be expected to have high or low osteoclast and high or low osteoblast activity?
High osteoclast and low osteoblast activity because osteoblast cells deposit new bone whereas osteoclast cells reabsorb bone cells.
In a pancreatic abscess, all of the following would be expected to be found EXCEPT:
A) macrophages
B) viruses
C) bacteria
D) antigens on the surface of bacteria on walls
(B) An abscess results from tissue dying and becoming infected with bacteria. The macrophages of the immune system recognize the antigens on the bacteria cell wall and trigger endocytosis of the bacteria. Viruses need a living cell as a host and are not found in an abscess.
The result of oxygen and glucose deprivation to the brain is:
A) apoptotsis of presynaptic neurons due to high levels of Na+
B) apoptosis of postsynaptic neurons due to high levels of Ca2+
C) mitochondrial damage in postsynaptic neurons due to high intracellular glutamate
D) mitochondrial damage in presynpatic neurons due to high extracellular glutamate
(B) Oxygen deprivation results in disruption of the electrochemical gradient of the cell because of the failure of the sodium potassium pump. Glutamate transporters reverse direction, resulting in high levels of extracellular glutamate and triggering prolonged release of calcium ions into the post-synaptic neuron, leading to mitochondrial and apoptosis.
The electrochemical gradient of the cell is maintained at resting potential by:
A) simple diffusion of Na+ out of the cell
B) facilitated diffusion of Ca2+ into the cell
C) active transport of K+ out of the cell
D) active transport of Na+ out of the cell
(D) The sodium potassium pump requires ATP to pump Na+ out of the cell and K+ into the cell, thereby creating a net export of positive charge.
Some bacteria are small enough to live within a host cell, such as an epithelial cell in the small intestine. Suppose some bacteria were able to infect the cells in the ectoderm of an embryo. Which tissue or organ, in a newborn infant, would most likely be least damaged?
A) eyes
B) brain
C) small intestinal epithelial cells
D) hair follicles
(C). The ectoderm of an embryo cell will develop into the eyes, brain, and hair follicles. The endoderm develops into the digestive tract, including small intestinal epithelial cells.
In gastropod mollusks, a midgut gland situated on top of the stomach functions in secretion of digestive enzymes and in detoxification, absorption and excretion of the products of digestion and metabolism. These functions are analogous organs in mammals:
A) Spleen and kidneys
B) livers and pancreas
C) bile duct and sweat glands
D) stomach and small intestine
(B) The liver is responsible for detoxification of metabolic byproducts, glycogen storage, breakdown of red blood cells, and secretion of bile. The pancreas secretes digestive enzymes.
The population of bacteria in the small intestine may increase in the presence of an antibiotic if:
a) the bacteria are mutualistic
b) the pH of the small intestine decreases
c) the bacteria can undergo conjugation
d) the bacteria are not capable of sexual reproduction
(C) Conjugation is the transfer of genetical material from one bacteria to another and increases genetic variability.
Women infected with the HPV virus may develop cervical cancer. However, the probability of a woman developing colon cancer as a result of a bacterial infection in the colon is low because:
a) bacteria cannot undergo meiosis
b) bacteria can live inside a mammalian cell
c) bacteria do not contain oncogenes
d) bacteria do not directly insert or delete genes in the human genome.
Unlike viruses, bacteria do not insert genes directly into host cells.
A characteristic of fungi that is not shared with at least some animals is:
a) extracellular secretion of digestive enzymes
b) structural use of the polysaccharide chitin
c) haploid life cycle
d) asexual reproductoin
C. Animals have a haploid germ line, but it does not constitute a separate phase of the life cycle capable of independent reproduction.
Which of the following taxonomic categories would include taxa with the fewest nucleotide differences in rRNA sequence?
a) Domain
b) Phylum
c) Kingdom
d) Order
(D) The taxonomic categories are hierarchical, with more closely related organisms with the lowest sequence differences in the lower level taxa (order).
Kingdom | Phylum | Class | Order | Family | Genus | Species
Genetically modified λ bacteriophages are used as vectors to clone recombinant DNA by the process of:
a) transformation
b) transfection
c) transduction
d) conjugation
(C) Bacteriophages are viruses that infect bacteria so insertion of foreign DNA into a bacterium by a viral vector is called transduction.
GFR (glomerular filtration rate) measures the rate of filtrate passing from capillaries into the:
a) nephric duct
b) Bowman’s capsule
c) proximal convoluted tubules
d) ureter
(B) Water and solutes pass through the capillaries of the glomerulus into Bowman’s capsule
Which of the following would NOT be a consequence of low GFR?
a) electrolyte imbalance
b) changes in extracellular fluid volume
c) high levels of urea in urine
d) high blood creatinine
(C) Low filtration rate would result in lower levels of urea in the urine, not higher.
Malpighian tubules function as part of which organ system?
a) respiratory
b) circulatory
c) excretory
d) digestive
(C) These tubules remove nitrogenous waste from the body.
The fact that scar tissue on skin does not contain sweat glands can be explained how?
Differentiated cells have their fates determined and cannot be altered to generate another cell time. Sweat glands do result from differentiation of the ectoderm; but they cannot be formed from other differentiated cells.
Examinatiion of actively infested host cells with a light microscope would reveal:
a) viral DNA within the host cell nucleus
b) the remains of intracellular capsids
c) new virions budding from host cell membrane
d) no evident virions
D. Because of their small size, virions are not visible under a light microscope.
Viral mRNA is synthesized in the:
nucleus by RNA polymerase.
Which of the following would be involved in the cell-mediated immune response to combat cell-to-cell infection with a virus?
a) antibodies
b) immunoglobins
c) B cells
d) macrophages
(D). Macrophages and T-lymphocytes are components of the cell-mediated immune response.
The most likely target of host antibodies would be viral:
a) phospholipids
b) glycoproteins
c) DNA
d) capsid proteins
(B) Glycoproteins are virally-encoded proteins on the outer envelope of the virion which encloses the capsid. Phospholipids in the same envelope are derived from host nuclear membrane and would not elicit an immune response.
Synthesis of new viral glycoproteins would involve:
post-translational modifications in the lumen of the rough endoplasmic reticulum and Golgi body.
If the researcher is correct about increased albumin concentration in the interstitial fluid of the brain following focal ischemia (tissue dysfunction from reduced blood flow), which of the following interactions would most likely be affected?
A. Ependyma and cerebrospinal fluid
B. Microglia and lymphocytes
C. Schwann cells and axons
D. Astrocytes and blood vessels
(D) Schwann cells form the myelin sheath around axons of neurons in the peripheral nervous system. Microglia present antigens to lymphocytes. Astrocyte end feet surround blood vessels of the central nervous system to contribute to the blood brain barrier
Which cell type would most likely respond to brain tissue injury caused by focal ischemia by phagocytosis of debris from dead cells?
A. Ependymal cells
B. Microglia
C. Oligodendrocytes
D. Astrocytes
(B) The ependyma is a leaky barrier composed of ependymal cells between the cerebrospinal fluid and the interstitial fluid of the central nervous system. Oligodendrocytes form the myelin sheath around the axons of neurons in the central nervous system. Microglia secrete cytotoxic molecules, phagocytose cells and debris, and present antigens to immune cells.
Which cell type normally maintains homeostasis of the interstitial fluid in the brain, including the concentration of potassium ions?
A. Ependyma
B. Microglia
C. Neurons
D. Astrocytes
(D). The ependyma is a leaky barrier composed of ependymal cells between the cerebrospinal fluid and the interstitial fluid of the central nervous system. Neurons process and transmit information in the nervous system. Astrocytes maintain homeostasis of the interstitial fluid of the central nervous system.
Which cell type most likely removes damaged myelin in multiple sclerosis?
A) Ependyma
B) Microglia
C) Oligodendrocytes
D) Astrocytes
(B) Microglia phagocytose debris in the central nervous system, therefore they most likely remove damaged myelin in multiple sclerosis.
If the researcher is correct about a virus infecting cells of the central nervous system leading to loss of myelin by immune attack on these cells in multiple sclerosis, which cell type would most likely be infected?
A. Microglia
B. Neurons
C. Oligodendrocytes
D. Astrocytes
(C) Oligodendrocytes form the myelin sheath around axons of neurons in the central nervous system; therefore they would be the cells most likely to be infected if the hypothesis is correct.
The scientist transiently opens sodium channels on a dendrite of a cultured neuron. Which membrane potential term best describes what most likely happens to the membrane around the open channel during this event?
Since the membrane potential went from -60 mV to -50 mV, this indicates that depolarization is occurring.
Gigantism, a disease of accelerated growth, can be caused by primary tumors of the anterior pituitary gland. In patients with tumor-induced gigantism, levels of Growth Hormone Releasing Hormone would expected to be:
The hypothalamus would respond to increased levels of GH by reducing production of GHRH.
Hormones that stimulate their target tissue via the intermediate endocrine glands are categorized as:
Tropic hormones. The tropic hormones are those with other endocrine glands as their target. They are mostly produced and secreted by the anterior pituitary gland and include the hormones FSH, LH, ACTH, and TSH.
Describe how a graph would look like if it were to measure hormone concentration using a radioimmunoassay to measure hormones.
Initially, hormone concentration is low and radioactivity is high, but radioactivity decreases as hormone concentration is elevated.
Low serum levels of Iodine, a necessary component to the production of thyroid hormones would lead to which of the following:
I. goiter
II. hypothyroidism
III. elevated serum TSH
All three of them. The question stem states that Iodine is necessary in the production of thyroid hormones. Insufficient levels of iodine would result in decreased thyroid hormone production. When thyroid hormone levels are low, the thyroid gland is stimulated to increase production by the anterior pituitary hormone TSH (Thyroid Stimulating Hormone). Hypothyroidism is a medical condition characterized by low circulating levels of the thyroid hormones T3 (triiodothyronine) and T4 (thyroxine). When thyroid hormone levels are low, the anterior pituitary gland releases the hormone TSH in order to stimulate the thyroid gland to increase production of its hormones. This can result in thyroid tissue growth (goiter) to compensate for decreased efficacy.
Increased production of cortisol in response to stress would most likely accompany increased:
A. bone formation
B. constriction of pupils
C. blood pressure
D. secretion of digestive enzymes
C. Cortisol is produced in the cortex (outer layer) of the adrenal gland which is situated atop the kidneys. During times of stress, the corticotropin-releasing hormone (CRH) from the hypothalamus triggers adrenocorticotropic hormone (ACTH) from the anterior pituitary to be produced, and this in turn stimulates cortisol production in the adrenal glands. Cortisol has many effects on the body. One important effect is that it increases blood pressure by increasing the sensitivity of the vasculature to epinephrine and norepinephrine
Discuss the pathway of blood from being deoxygenated to becoming oxygenated
DEOXYGENATED
capillaries –> venules -> veins -> superior/inferior vena cava -> right atrium -> right venticle -> pulmonary artery -> lungs
OXYGENATED
Lungs –> pulmonary vein -> left atrium -> left ventricle -> aorta -> arteries -> arterioles -> capillaries
Where does blood entering the right atrium come from? A. Left atrium
B. Right ventricle
C. Pulmonary circulation
D. Systemic circulation
(D) Systemic circulation captures the blood flow that occurs through the arteries, capillaries, and veins that are between the left ventricle and the right atrium. Therefore blood entering the right atrium comes from the systemic circulation.
Why would it be unlikely for a clot formed in the venous system to cause a heart attack or stroke?
A. Venous blood is less likely to clot due to its lower oxygen concentration.
B. A clot formed in the venous system would get trapped in the lungs before getting into systemic circulation.
C. Venous clots are rare because pressure in the venous system is so low.
D. Clots fall apart as they travel through the blood.
(B) The venous system (systemic circulation) is a low-pressure system that carries blood with low oxygen concentration. Relative to the arterial system, clot formation in the venous system is not a particularly “rare” event. Blood from the venous system (systemic circulation) moves towards the right side of the heart. If a blood clot formed in the venous system it would move through veins into the superior or inferior vena cava and then into the right atrium, right ventricle, and the lungs. A clot needs to be in the arterial side of the systemic circulation to cause a heart attack or stroke. When a blood clot goes into the pulmonary circulation, it will often get stuck in pulmonary arteries, or arterioles, or capillaries, and hence never reach the arterial side of the systemic circulation.
Which of the following would you NOT expect to increase systolic blood pressure?
A. Taking a medication that Increases fluid retention in the kidneys
B. Experiencing a nightmare
C. Taking a medication that causes vasoconstriction
D. Changing from lying down to standing up
(D). Systolic blood pressure will increase with increased blood flow or resistance. Vasoconstriction will cause increased resistance. Fluid retention will cause increased blood flow (volume/time) due to increased total blood volume. Experiencing a nightmare will raise your heart rate. Heart rate multiplied by stroke volume equals blood flow. Therefore a nightmare will increase blood flow. Changing from lying to standing up will decrease blood pressure because gravity would cause blood to “pool” in lower extremity venous system. This reduces the blood flow because the “pool” of blood in the legs is not effectively circulating.
Which of the following is true regarding the coronary arteries?
A. The coronary arteries carry blood to the heart from the lungs.
B. The coronary arteries carry blood to the lungs from the heart.
C. The coronary arteries are part of systemic circulation.
D. All blood from systemic circulation passes through the coronary arteries before going back to systemic circulation.
(C). The lungs are connected to the heart by the pulmonary arteries and veins (pulmonary circulation), as well as bronchial arteries and veins (systemic circulation). The coronary arteries come off the base of the aorta, and are the first branches off of the aorta. Just like other tissues in the body, the heart needs to be perfused by blood to get oxygen and clear wastes. The blood in the atria and ventricles do not fulfill this purpose because they do not divide into capillary beds.
Which of the following are most important in explaining how the body changes the resistance of arterioles to blood flow?
A. Endothelial cells
B. Smooth muscle cells
C. Skeletal muscle fibers
D. Arterial valves
(B) Arterial walls can be opened (vasodilation) or closed (vasoconstriction) to change the internal diameter of the vessel. Valves do not play an important role in changing the size of the blood vessel. Contraction of smooth muscle cells will cause arteriole vasoconstriction and will increase resistance to blood flow.
How might blood flow to the kidneys during excerise decrease?
During exercise blood needs to get redistributed to the areas doing work (skeletal muscles). Vessels that are wide open (vasodilated) offer less resistance to blood flow, then vessels that are narrow (vasoconstricted). During exercise, blood vessels in skeletal muscle dilate to offer more blood to those areas. In addition, blood vessels going to other organs (e.g. kidney) constrict.
Over which of the following blood vessel types is the drop in blood pressure typically greatest?
A. Arterioles
B. Arteries
C. Capillaries
D. Venules
(A). If you take someone’s blood pressure, typically you measure the pressure in their brachial artery. It does not significantly matter how far along the brachial artery you measure. Pressures in the venous system are generally low and do not drop significantly. One arteriole divides into many capillaries, and hence much more blood needs to force through an arteriole than a capillary. More blood pressure is needed to force blood through arterioles than capillaries, even though one arteriole would have lower resistance than one capillary. As a result, the drop in blood pressure is greatest along the arterioles.
Partial pressure of gas X in inspired air: 18 mmHg
Inspirational volume: 700 mL
Partial pressure of gas X in expired air: 6 mmHg
What is the residual volume in the lungs?
The total volume in the lungs after inspiration is x + 700 mL, if x is the residual volume. Therefore the partial pressure in the expired gas will be diluted by a factor (x + 700 mL) / 700 mL.
The residual volume will be 1400.
What is a result of the fact that we have residual volume in our lungs?
Air we breathe in has oxygen, while residual volume will mostly have given its oxygen to the blood..
Oxygenated air we breathe in is diluted by de-oxygenated air already in the lungs
On inspiration, will where gas X go after the trachea?
The order is mouth → trachea → bronchi → bronchioles → alveoli
Vasoconstriction of which of the following vessels will most effectively reduce fat absorption from the small intestine into the bloodstream?
A) Lacteals inside intestinal villi of the small intestine
B) Capillaries in the smooth muscle of the small intestine
C) Lacteals in the peritoneum around the small intestine
D) Capillaries in the peritoneum around the small intestine
(A). If the lacteals of the intestinal villi were to contract, it would reduce fat absorption because ingested facts collect in the lacteals for transport into the venous circulation.
An intravenous infusion causes a sharp rise in the serum level of albumin which will most likely cause an:
a) increase in the immune response
b) increase in tissue albumin levels
c) outflow of blood fluid to the tissues
d) influx of tissue fluid to the bloodstream
(D) The plasma proteins can not cross the walls of the blood vessels, but water molecules can. The walls of the artery acts as a semipermeable membrane setting up the conditions needed for osmosis to occur. An increase in plasma albumin will upset the osmotic balance because blood will become hypertonic (with respect to the tissue). So water will have to flow into the bloodstream to reestablish equilibrium. One of the causes of edema, increased fluid in body tissues, is a decrease in the plasma protein level.
A lower than normal blood pressure will cause which of the following effects on the rate of plasma clearance?
A) an increase because the concentration of a substance in the urine wil increase
B) an increase because ADH levels will be very low
C) a decrease because the decreased rate of urine output will allow more reabsorption by the kidney
D) a decrease because ADH levels will be very high
(C) Low blood pressure could have an effect on ADH levels, but there’s not enough information to decide. The best answer is C. Low blood pressure DECREASES the glomerular filtration rate, allowing more time for reabsorption and decreasing the amount of a certain substance in the urine.
What would happen to the blood in the glomerular capillaries if the heart stopped?
Fluid in the space around the glomerulus would flow back into the capillary bloodstream because the protein-rich blood would be hypertonic with respect to the protein-poor fluid in the capsular space so that the fluid would flow down the osmotic gradient into the blood.
The increased blood pressure resulting from higher than normal concentration of ADH most likely affected the urinary output of a substance by increasing the:
Glomerular filtration rate. Increasing blood pressure should increase the flow of fluid through the kidney system and decrease, rather than increase, water reabsorption.
Postmenopausal women receiving estrogen and progesterone therapy will most likely experience which of the following side effects?
A) breast tissue will atrophy
B) vaginal tissue will dry out
C) periodic menstruation will resume
D) lactation will be induced
(C) Estrogen and progesterone are actively secreted by the ovaries of premenopausal women and act to maintain the uterine cycle. With advancing age, the ovary becomes less responsive to pituitary gonadotropins and cyclical changes in the endometrium of the uterus disappear. The menstrual cycle can be restablished by administration of estrogen and progesterone in a regiment that approximates the rise and fall of hormone levels in pre-menopausal women.
Production of which of the following hormones will be inhibited by the administration of dietary calcium to prevent osteoporosis?
A) growth hormone
B) calcitonin
C) thyroid hormone
D) parathyroid hormone
(D) Calcium levels in the blood need to be kept constant. Parathyroid hormone and calcitonin regulate blood levels of calcium. Calcitonin puts calcium in the bones. Parathyro_id_ hormone gets rid of calcium from the bones.
Which of the following describes the solubility of methionine?
A) High in both water and lipids.
B) High in water and low in lipids.
C) Low in water and high in lipids.
D) Low in both water and lipids.
(C) Methionine is a non-polar, hydrophobic amino acid. Water is a polar solvent, and lipids are nonpolar. Thus, methionine will have low solubility in water and high solubility in lipids.
Most serum homocysteine exists in a form bound to other thiol amino acids and proteins in the form of disulfides (e.g. cystine-homocystine and homocystine-homocystine). Disulfide bonds play a role in which levels of protein structure?
Tertiary & Quarternary structure. Primary structure is determined by covalent peptide bonds. Secondary structure is determined by hydrogen bonding between distance side chains of amino acids in the same polypeptide. Disulfide bonds play a role in determining tertiary and quaternary structure.
RNA interference (RNAi) is a mechanism by which short RNA sequences bind onto specific targets of RNA molecules. One of its consequences is the targeting of RNA molecules for intracellular destruction. This protects cells against viral and other infectious RNA molecules. In this capacity, RNAi’s function is analogous to which of the following?
A macrophages
B cytotoxic T cells
C antibodies
D apoptosis
(C) Antibodies are proteins which bind to antigens, or structures the immune system has targeted. The antibody-antigen relationship is highly specific, with antibodies generally targeting a specific site on the antigen. Antigens that have been bound by antibodies are easier to capture and destroy by the immune system. This is analogous to the function of RNAi wherein RNA sequences bind onto specific target RNA sequences for destruction like infections molecules.
Which of the following is always true concerning the base composition of DNA?
A) in each single strand, the number of adenine residues equals the number of thymine residues
B) in each single strand, the number of adenine residues equals the number of guanine residues
C) in a molecule of double stranded DNA, the ratio of adenine residues to thymine residues equals the ratio of cytosine residues to guanine residues
D) in a molecule of double stranded DNA, the number of adenine residues plus thymine residues equals the number of cytosine residues plus guanine residues
(C) Since A always binds with T and C always binds with G, the A/T ratio and the ratio of G/C is equal to one.
A molecule of DNA contains all of the following EXCEPT:
a) deoxyribose sugars
b) polypeptide bonds
c) phosphodiester bonds
d) nitrogenous bases
(B) DNA is a nucleotide polymer. A nucleotide is a ribose sugar, phosphate group, and a nitrogenous base. The nucleotides in DNA are held together by phospodiester bonds.
Which of the following is a carbohydrate polymer that is stored in plants and digestible by animals?
a) starch
b) glycogen
c) cellulose
d) glucose
(A) Plants store carbohydrates as starch. Animals store carbohydrates as glycogen. Glucose is not a polymer. Cellulose is found in plant cell walls and is not digestible by humans.
Proline is not technically an alpha amino acid. Due to the ring structure of proline, it cannot conform to the geometry of the alpha helix, and creates a bend in the polypeptide chain. This phenomenon asists in the creation of what level of protein structure?
A) primary
B) secondary
C) tertiary
D) quaternary
(C) The bending of the polypeptide chain is the tertiary structure of a protein.
Translation in eukaryotic cells is associated with each of the following organelles EXCEPT:
a) mitochondrial matrix
b) cytosol
c) nucleus
d) rough endoplasmic reticulum
(C) Translation does not occur in the nucleus.
How many chromosomes does a human primary spermatocyte contain?
A) 23
B) 46
C) 92
D) 184
(B) A primary spermatocyte has finished the S stage of interphase but not the first meiotic division.
Thus, it has 46 chromosomes