Biochemistry Midterm 1 Flashcards

1
Q

What is the definition of a hydrogen bond?

A

dipole-dipole/charge-dipole interactions that arise between covalently bonded H atom and a lone pair of electrons on an electronegative atom

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2
Q

average number of bonds in liquid water vs ice

A

3.4 vs 4

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3
Q

why do micelles form?

A

by clustering non-polar tails together as a result of the hydrophobic effect, entropy is increased compared to if the hydrophobic regions were all separately interacting with water (minimized to ordered shell around micelle)

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4
Q

define van der waals interactions

A

weak interactions between atoms at the maximum between attraction (due to polarity and dipole) and repulsion (due to atom size)

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5
Q

van der waals qualities

A

between any 2 atoms, determine steric compatibility, individually easily broken, strong in numbers, stabilize macromolecules

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6
Q

colligative vs non colligative properties

A

colligative properties are only dependent on solute concentration and not on solute nature: boiling point, melting point and osmolarity
non colligative properties are dependent on solute nature: viscosity, surface tension, taste, color

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7
Q

adhesion vs cohesion

A

adhesion - binding between unlike molecules
cohesion - binding between like molecules (water surface tension)

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8
Q

water dissociation constant and dissociation at 25°

A

1.0 x 10^-14 M^2, at 25° 2 in every 10^9 molecules is dissociated

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9
Q

proton hopping definition

A

protons moving between hydrogen bonded water molecules causing net movement of a photon over long distance quickly`

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10
Q

ionic product of water

A

Kw = [H+][OH-]

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11
Q

A strong acid Ka and pKa

A

high Ka and low pKa

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12
Q

buffering capacity is greatest when

A

pH = pKa which is also when the acid is 50/50 concentration

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13
Q

buffer systems in vivo

A

phosphate, bicarbonate, histidine

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14
Q

peptide bonds are formed

A

through condensation reaction between carboxyl group and amino group of two amino acids

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15
Q

2 cysteine amino acids that form a disulfide bond is

A

cystine

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16
Q

histidine properties

A

not actively positively charged R group called imidazole but often involved in reactions as a proton donor. Imidazole is cyclic

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17
Q

uncommon amino acid that can be incorporated by ribosomes

A

selenocysteine

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18
Q

how do modified amino acids arise?

A

post-translational modifications, permanent or transient

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19
Q

high pH vs. low pH charged of amino acids

A

low pH amino acids will be positively charged (H is still attached to carboxyl group). High pH amino acids will be negatively charged (H is donated and NH2 is formed)

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20
Q

zwitterion

A

net 0 charge of amino acid, both negative and positive charges on amino acid. This occurs at pI for amino acid

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21
Q

how to calculate pI

A

without ionizable R group: average of pka1 and pka 2
with ionizable R group: average of pka closest to pkaR and pkaR

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22
Q

protein structures are stabilized by

A

non covalent forces: H bonds, ionic bonds, van der waals interactions, hydrophobic effect

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23
Q

why are disordered regions important

A

for interactions with other proteins - gives flexibility and ability for conformational change

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24
Q

common protein structural patterns

A

alpha helices, beta turns, beta sheets

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25
Q

why doesn’t the peptide bond rotate?

A

it is a resonance structure between O=C-N

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26
Q

phi vs. psi angle around alpha carbon

A

phi is amide nitrogen bond side, psi is on carbonyl carbon side

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27
Q

peptides are read in what direction:

A

amino (left) to carboxyl (right)

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28
Q

how are alpha helices and beta sheets stabilized?

A

H bonds. Alpha helices H bond between nearby residues amino acid backbones. Beta sheets stabilize parallel or antiparallel between adjacent segments (may or may not be nearby)

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29
Q

random coil

A

irregular arrangement of polypeptide (disordered)

30
Q

1Å =

A

1x10^-10 m

31
Q

residues per turn of alpha helix

A

3.6. Every n + 4 H bonds

32
Q

alpha helix breakers and why

A

proline due to cyclic R ground not able to rotate and it doesn’t H bond. Glycine has a lot of flexibility because it is small, better in tight coils like collagen

33
Q

5 constraints that affect helix stability

A
  1. amino acid propensity for helix (small, hydrophobic) 2. R group interactions 3-4 amino acids away. 3. bulkiness of R groups 4. Proline and glycine. 5.
34
Q

proline and glycine in beta turns

A

proline position 2 (cis), glycine position 3

35
Q

native globular form

A

condensed tertiary protein structure stabilized through hydrophobic effect

36
Q

motifs are? Globular proteins are?

A

specific arrangement of many secondary structures, recur across many proteins. Globular proteins are different motifs folded together

37
Q

domain is?

A

part of a polypeptide chain that is independently stable and functional

38
Q

fibrous protein solubility

A

insoluble due to many hydrophobic R groups

39
Q

alpha keratin description

A

strong double twisted left handed alpha helices. Disulfide bonds stabilize between different polypeptide twists. Found in hair, nails, and feathers.

40
Q

collagen description

A

3 separate polypeptide alpha chains supertwisted left handed alpha chains coiled together in a right hand twist, very strong.
Cross-linking stabilizes supercoils parallel adjacent to each other. Found in connective tissue, bones and cornea

41
Q

silk fibroin description

A

antiparallel beta sheet structures stacked with small R groups. Stabilized by weak interactions for flexibility and strength.

42
Q

quaternary structure

A

assembly of individual polypeptides into a large functional cluster

43
Q

enzymes increase specificity how?

A

by creating an environment in which the desire product is favored to be produced

44
Q

benefits of enzymes

A

higher reaction rates, milder conditions, avoids side products, regulation of pathways

45
Q

cofactors include:

A

coenzymes (organic), inorganic (minerals), prosthetic groups (tightly bound cofactor)

46
Q

apoenzyme vs holoenzyme

A

no coenzyme, yes coenzyme

47
Q

6 classes of enzymes

A

oxidoreductases: transfer of electrons
transferases: group transfer
hydrolases: hydrolysis (breaking of bonds using water)
lysases: cleavage of C-C, C-N, or C-O bonds
Isomerases: transfer of groups within molecule
ligases: formation of C-C, C-S, C-O or C-N bonds via condensation rxn

48
Q

what is desolvation?

A

enzyme-substrate binding replaces H bonds water had with enzyme(which decreases entropy)

49
Q

how do enzymes lower activation energy?

A

organizing reactive groups into proximity and proper orientation to make the reaction thermodynamically favorable

50
Q

what compensates for thermodynamically unfavorable free energy change associated with induced fit?

A

weak interactions formed in transition state of ES complex

51
Q

categories of catalysis (enzymes use one or more)

A

acid-base: proton transfer, often from water
covalent catalysis: transient covalent bond, requires nucleofile on enzyme
metal ion catalysis: interacts with substrate to facilitate binding

52
Q

chymotrypsin function

A

cuts peptide bonds adjacent to aromatic amino acids

53
Q

Km =

A

[S] when V = 1/2 Vmax

54
Q

turnover number =

A

Kcat = K2 = Vmax/[ET]
number of substrate molecules converted to product in a given unit of time by a single enzyme molecule at saturation

55
Q

Niacin is necessary as

A

a precursor of NAD coenzyme required by many oxidoreductase enzymes

56
Q

steady state vs equilibrium

A

Steady state: when rate of product creation and rate of product breakdown is is equal (amount of ES produced = amount ES broken down into product)
Equilibrium: rate of reaction is equal in both directions (forwards and backwards) and reactants and products are present

57
Q

Slope at any point on a product concentration vs time graph

A

velocity of enzymatic reaction

58
Q

Km =

A

[S] when V0 is 1/2 Vmax
(K2 + K-1)/K1

59
Q

saturation kinetics

A

at high [S], velocity is not proportional to [S] (velocity flatlines due to all enzymes being occupied)

60
Q

Turnover and Kcat equations

A

Kcat = K2
Kcat = Vmax/[ET]
turnover is equal to the slowest K

61
Q

rate limit equation/enzyme efficiency

A

limited by specificity
kcat/Km

62
Q

Lineweaver-Burk double reciprocal plot x and y intercepts

A

x intercept = -1/Km
y intercept = 1/Vmax
slope is Km/Vmax

63
Q

reversible enzyme inhibitors

A

bind to and dissociate from enzymes
often structural analogs of substrates or products

64
Q

competitive inhibition definition and plot

A

competes with substrate for enzyme, binds to active site
does not effect catalysis (Vmax)
lines intersect at y axis and apparent increase of Km

65
Q

Uncompetitive inhibition definition and plot

A

binds to ES complex, inhibits catalysis (not substrate binding)
decrease in Vmax (and apparent decreased in Km), lines are parallel

66
Q

mixed inhibition definition/noncompetitive inhibition and plot

A

binds enzyme (with or without S)
inhibits both substrate binding and catalysis
lines intersect left of the y axis

67
Q

allosteric inhibitor

A

noncompetitive inhibitor or uncompetitive inhibitor which binds to a part of the enzyme outside the active site

68
Q

myosin structure

A

2 heavy chains of supercoiled alpha helices with amino terminal globular heads

69
Q

enzymes differ from other catalysts in that only enzymes…

A

display specificity towards a single reactant

70
Q

what does Keq equilibrium constant say about free energy?

A

Keq = [P]/[S] reflects the lower energy state of the product compared to the substrate
a catalyzed reaction where at equilibrium there is more product than substrate is thermodynamically favorable

71
Q

Transition state definition

A

momentary perfect bind match with enzyme and substrate after it has changed conformation