Benzene - a molecule with two models Flashcards
aromatic means
the bonding in a compound contains delocalised electrons forming pi (π) bonding in a hydrocarbon ring
the physical properties of benzene are:
- colourless liquid
- boiling point of 80 degrees C
- insoluble in water
- carcinogenic
benzene’s molecular formula is
C6H6
the Kekule structure of benzene implies that there are
3 double bonds in benzene
the 4 problems with the kekule structure are
- if benzene had 3 double C=C bonds, it should decolourise bromine water, yet it does not and instead a substitution reaction which is evidence there are not any double C=C bonds present in bromine
- if there were 3 C=C bonds, then there would be four isomers of dibromobenzene, C6H4Br2, but there are only 3 known isomers, which emans the bonds within benzene are all the same
- data on bond length shows all of benzen’s bonds are the same length, while they should be different as the C=C bond is usually shorter than a C-C bond. benzene’s bond length data is between the C-C and C=C bond data, so suggests its bonding has an intermediate character
- benzene’s enthalpy change value of hydrogenation should be three times that of cyclohexene at -360 kJ mol-1, yet has an actual value of -208 kJ mol-1, which means benzene does not contain any C=C bonds
instead of the kekule structure, benzene is now thought to have
a ring of 6 delocalised electrons, with each carbon atom providing one electron and forming a delocalised π-bond instead
how does the new structure for benzene overcome the 4 problems of the kekule structure?
1) there are no individual C=C double bonds so no addition reaction with bromine
2) there are three and not four isomers of C6H4Br2
3) the C-C bonds are all the same lengths as there are not C=C bonds
4) when charge is spread around in a species. there is an increase in stability, which explain’s benzen’s greatre stability than cyclohexe 1,3,5-triene
why does benzene undergo a substitution reaction with bromine to form C6H5Br and not an addition reaction to form C6H4Br2 ?
it is more stable to keep the delocalised ring of electrons rather through substitution rather than loose some in addition. the addition reaction would produce a compound with two C=C double bonds taht would have a reduced stability than the delocalised pi bond