BB Flashcards
- What type of serological testing does the blood bank technologist perform when determining the blood group of a patient?
A. Genotyping
B. Phenotyping
C. Both genotyping and phenotyping
D. Polymerase chain reaction
Blood bank/Apply knowledge of laboratory operations/Genetics/1
B Phenotyping, or the physical expression of a genotype, is the type of testing routinely
- If anti-K reacts 3+ with a donor cell with a genotype KK and 2+ with a Kk cell, the
antibody is demonstrating:
A. Dosage
B. Linkage disequilibrium
C. Homozygosity
D. Heterozygosity
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/Kell/3
A Dosage is defined as an antibody reacting stronger with homozygous cells (e.g., KK) than with heterozygous cells (e.g., Kk). In addition to Kell, dosage effect is seen commonly with antigens M, N, S, s, Fya, Fyb, Jka, Jkb, and the antigens of the Rh system.
- Carla expresses the blood group antigens Fya, Fyb, and Xga. James shows expressions of
none of these antigens. What factor(s) may account for the absence of these antigens in
James?
A. Gender
B. Race
C. Gender and race
D. Medication
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/2
C The frequency of Duffy antigens Fya and Fyb varies with race. The Fy(a-b-) phenotype
occurs in almost 70% of African Americans and is very rare in whites. Xga antigen is
X-linked and, therefore, expressed more frequently in women (who may inherit the
antigen from either parent) than in men.
- Which of the following statements is true?
A. An individual with the BO genotype is homozygous for B antigen
B. An individual with the BB genotype is homozygous for B antigen
C. An individual with the OO genotype is heterozygous for O antigen
D. An individual with the AB phenotype is homozygous for A and B antigens
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/ABO/1
B An individual having the BB genotype has inherited the B gene from both parents and,
therefore, is homozygous for B antigen.
- Which genotype is heterozygous for C?
A. DCe/dce
B. DCE/DCE
C. Dce/dce
D. DCE/dCe
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/Rh/2
A The genotype DCe/dce contains one C and one c gene and is heterozygous for C and c
antigens.
- Which genotype(s) will give rise to the Bombay phenotype?
A. HH only
B. HH and Hh
C. Hh and hh
D. hh only
Blood bank/Apply knowledge of fundamental biological characteristics/ABO/Bombay/1
D The Bombay phenotype will be expressed only when no H substance is present. The
Oh type is expressed by the genotype hh. Bombay phenotypes produce naturally
occurring anti-H, and their serum agglutinates group O red blood cells (RBCs) in
addition to RBCs from persons who are groups A, B, and AB.
- Meiosis in cell division is limited to the ova and sperm producing four gametes
containing what complement of DNA?
A. 1N
B. 2N
C. 3N
D. 4N
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/1
A Meiosis involves two nuclear divisions in succession resulting in four gametocytes,
each containing half the number of chromosomes found in somatic cells or 1N.
- A cell that is not actively dividing is said to be in:
A. Interphase
B. Prophase
C. Anaphase
D. Telophase
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/1
A Interphase is the stage in between cell divisions. The cell is engaged in metabolic
activity. Chromosomes are not clearly discerned; however, nucleoli may be visible
- Which of the following describes the expression of most blood group antigens?
A. Dominant
B. Recessive
C. Codominant
D. Corecessive
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/1
C The inheritance of most blood group genes is codominant, meaning that no gene or
allele is dominant over another. For example, a person who is group AB expresses both
the A and B antigen on his or her RBCs.
- What blood type is not possible for an offspring of an AO and BO mating?
A. AB
B. A or B
C. O
D. All are possible
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/ABO/2
D A mating between AO and BO persons can result in an offspring with blood type A,
B, AB, or O.
- The alleged father of a child in a disputed case of paternity is blood group AB. The
mother is group O, and the child is group O. What type of exclusion is this?
A. Direct/primary/first order
B. Probability
C. Random
D. Indirect/secondary/second order
Blood bank/Evaluate laboratory data to verify test results/Genotype/Paternity testing/2
D An indirect/secondary/second order, exclusion occurs when a genetic marker is absent
in the child but should have been transmitted by the alleged father. In this case, either
A or B should be present in the child.
- If the frequency of gene Y is 0.4 and the frequency of gene Z is 0.5, one would expect
that they should occur together 0.2 (20%) of the time. In actuality, they are found
together 32% of the time. This is an example of:
A. Crossing over
B. Linkage disequilibrium
C. Polymorphism
D. Chimerism
Blood bank/Apply principles of genetics/3 Answers to Questions 6–12
B Linkage disequilibrium is a phenomenon in which alleles situated in close proximity
on a chromosome associate with one another more than would be expected from
individual allelic frequencies.
- In the Hardy-Weinberg formula, p2 represents:
A. The heterozygous population of one allele
B. The homozygous population of one allele
C. The recessive allele
D. The dominant allele
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/1
B In the Hardy-Weinberg formula (p2 + 2pq + q2), p2 and q2 represent homozygous
expressions, and 2pq represents heterozygous expression. This formula is used in
population genetics to determine the frequency of different alleles.
- In this type of inheritance, the father carries the trait on his X chromosome. He has no
sons with the trait because he passed his Y chromosome to his sons; however, all his
daughters will express the trait.
A. Autosomal dominant
B. Autosomal recessive
C. X-linked dominant
D. X-linked recessive
C In X-linked dominant inheritance, there is absence of male-to-male transmission because a male passes his Y chromosome to all of his sons and his single X
chromosome to all his daughters. All daughters who inherit the affected gene will
express the trait. An example of this type of inheritance is the Xga blood group.
- Why do immunoglobulin M (IgM) antibodies, such as those formed against ABO
antigens, have the ability to directly agglutinate RBCs and cause visible agglutination?
A. IgM antibodies are larger molecules and have the ability to bind more antigen
B. IgM antibodies tend to clump together more readily to bind more antigen
C. IgM antibodies are found in greater concentrations than IgG antibodies
D. IgM antibodies are not limited by subclass specificity
Blood bank/Apply knowledge of fundamental biological characteristics/Antibodies/1
A An IgM molecule has the potential to bind up to 10 antigens compared with a
molecule of IgG, which can bind only two.
- Which of the following enhancement mediums decreases the zeta potential, allowing
antibody and antigen to come closer together?
A. Low ionic strength solution (LISS)
B. Polyethylene glycol
C. Polybrene
D. Dithiothreitol-papain (ZZAP)
Blood bank/Apply knowledge of fundamental biological characteristics/Antigens/1
A LISS contains a reduced concentration of NaCl (0.2%) and results in a reduction in
charged ions within the ionic cloud, decreasing the zeta potential and facilitating
antigen–antibody interaction
- This type of antibody response is analogous to an anamnestic antibody reaction.
A. Primary
B. Secondary
C. Tertiary
D. Anaphylactic
Blood bank/Apply knowledge of fundamental biological characteristics/Antibodies/1
B An anamnestic response is a secondary immune response in which memory
lymphocytes respond rapidly to foreign antigen in producing specific antibody. The
antibodies are IgG and are produced at lower doses of antigen than in the primary
response.
- Which antibodies to a component of complement are contained in the rabbit
polyspecific anti-human globulin (AHG) reagent for detection of in vivo sensitization?
A. Anti-IgG and anti-C3a
B. Anti-IgG and anti-C3d
C. Anti-IgG and anti-IgM
D. All of these options
Blood bank/Apply knowledge of fundamental biological characteristics/AHG/2
B In the direct antiglobulin test (DAT), rabbit polyspecific antisera contains both an
anti-human IgG component and an antibody against the C3d component of
complement.
- Which of the following distinguishes the A1 blood group from the A2 blood group?
A. A2 antigen will not react with anti-A, A1 will react strongly (4+)
B. An A2 person may form anti-A1; an A1 person will not form anti-A1
C. An A1 person may form anti-A2, an A2 person will not form anti-A1
D. A2 antigen will not react with anti-A from a nonimmunized donor; A1 will react with any
anti-A
Blood bank/Apply knowledge of fundamental biological characteristics/ABO blood group/2
B The group A1 comprises both A1 and A antigens. Anti-A will react with both A1- and
A2-positive RBCs. A person who is group A2 may form anti-A1, but an A1 person will
not form anti-A1 (which would cause autoagglutination).
- A patient’s serum is incompatible with O cells. The patient RBCs give a negative
reaction to anti-H lectin. What is the most likely cause of these results?
A. The patient may be a subgroup of A
B. The patient may have an immunodeficiency
C. The patient may be a Bombay phenotype individual
D. The patient may have developed alloantibodies
Blood bank/Apply principles of special procedures/ABO blood group/3
C Bombay phenotype is the only ABO phenotype incompatible with O cells. The RBCs
of a Bombay phenotype individual show a negative reaction to anti-H because the cells
contain no H substance.
- What antibodies are formed by a Bombay phenotype individual?
A. Anti-A and anti-B
B. Anti-H
C. Anti-A,B
D. Anti-A, B, and H
Blood bank/Apply knowledge of fundamental biological characteristics/ABO blood
group/Bombay/1
D A Bombay phenotype individual does not express A, B, or H antigens; therefore, anti-
A, -B, and -H are formed. Because a Bombay phenotype individual has three
antibodies, the only compatible blood must be from another Bombay phenotype donor
- Acquired B antigens have been found in:
A. Bombay phenotype individuals
B. Group O persons
C. Persons of all blood groups
D. Group A persons
Blood bank/Apply knowledge of fundamental characteristics/ABO/1
D The acquired B phenomenon is only seen in group A persons.
- Blood is crossmatched on an A-positive person with a negative antibody screen. The
patient received a transfusion of A-positive RBCs 3 years ago. The donors chosen for
crossmatching were A-positive. Crossmatching was run on the automated analyzer and
yielded 3+ incompatibility. How can these results be explained?
A. The patient has an antibody to a low-frequency antigen
B. The patient has an antibody to a high-frequency antigen
C. The patient is an A2 with anti-A1
D. The patient is an A1 with anti-A2
Blood bank/Apply principles of special procedures/ABO/3
C The patient is likely an A2 with anti-A1, which is causing reactivity in the
crossmatching. A negative antibody screen rules out the possibility of an antibody to a
high-frequency antigen, and two donor units incompatible rules out an antibody to a
low-frequency antigen.
- A patient’s RBCs forward as group O, serum agglutinates B cells (4+) only. Your next
step would be:
A. Extend reverse typing for 15 minutes
B. Perform an antibody screen, including room-temperature incubation
C. Incubate washed RBCs with anti-A1 and anti-A,B for 30 minutes at room temperature
D. Test patient’s RBCs with Dolichos biflorus
Blood bank/Apply principles of special procedures/RBCs/ABO discrepancy/3
C The strong 4+ reaction in reverse grouping suggests the discrepancy is in forward
grouping. Incubating washed RBCs at room temperature with anti-A and anti-A,B will
enhance reactions.