BB Flashcards
- What type of serological testing does the blood bank technologist perform when determining the blood group of a patient?
A. Genotyping
B. Phenotyping
C. Both genotyping and phenotyping
D. Polymerase chain reaction
Blood bank/Apply knowledge of laboratory operations/Genetics/1
B Phenotyping, or the physical expression of a genotype, is the type of testing routinely
- If anti-K reacts 3+ with a donor cell with a genotype KK and 2+ with a Kk cell, the
antibody is demonstrating:
A. Dosage
B. Linkage disequilibrium
C. Homozygosity
D. Heterozygosity
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/Kell/3
A Dosage is defined as an antibody reacting stronger with homozygous cells (e.g., KK) than with heterozygous cells (e.g., Kk). In addition to Kell, dosage effect is seen commonly with antigens M, N, S, s, Fya, Fyb, Jka, Jkb, and the antigens of the Rh system.
- Carla expresses the blood group antigens Fya, Fyb, and Xga. James shows expressions of
none of these antigens. What factor(s) may account for the absence of these antigens in
James?
A. Gender
B. Race
C. Gender and race
D. Medication
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/2
C The frequency of Duffy antigens Fya and Fyb varies with race. The Fy(a-b-) phenotype
occurs in almost 70% of African Americans and is very rare in whites. Xga antigen is
X-linked and, therefore, expressed more frequently in women (who may inherit the
antigen from either parent) than in men.
- Which of the following statements is true?
A. An individual with the BO genotype is homozygous for B antigen
B. An individual with the BB genotype is homozygous for B antigen
C. An individual with the OO genotype is heterozygous for O antigen
D. An individual with the AB phenotype is homozygous for A and B antigens
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/ABO/1
B An individual having the BB genotype has inherited the B gene from both parents and,
therefore, is homozygous for B antigen.
- Which genotype is heterozygous for C?
A. DCe/dce
B. DCE/DCE
C. Dce/dce
D. DCE/dCe
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/Rh/2
A The genotype DCe/dce contains one C and one c gene and is heterozygous for C and c
antigens.
- Which genotype(s) will give rise to the Bombay phenotype?
A. HH only
B. HH and Hh
C. Hh and hh
D. hh only
Blood bank/Apply knowledge of fundamental biological characteristics/ABO/Bombay/1
D The Bombay phenotype will be expressed only when no H substance is present. The
Oh type is expressed by the genotype hh. Bombay phenotypes produce naturally
occurring anti-H, and their serum agglutinates group O red blood cells (RBCs) in
addition to RBCs from persons who are groups A, B, and AB.
- Meiosis in cell division is limited to the ova and sperm producing four gametes
containing what complement of DNA?
A. 1N
B. 2N
C. 3N
D. 4N
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/1
A Meiosis involves two nuclear divisions in succession resulting in four gametocytes,
each containing half the number of chromosomes found in somatic cells or 1N.
- A cell that is not actively dividing is said to be in:
A. Interphase
B. Prophase
C. Anaphase
D. Telophase
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/1
A Interphase is the stage in between cell divisions. The cell is engaged in metabolic
activity. Chromosomes are not clearly discerned; however, nucleoli may be visible
- Which of the following describes the expression of most blood group antigens?
A. Dominant
B. Recessive
C. Codominant
D. Corecessive
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/1
C The inheritance of most blood group genes is codominant, meaning that no gene or
allele is dominant over another. For example, a person who is group AB expresses both
the A and B antigen on his or her RBCs.
- What blood type is not possible for an offspring of an AO and BO mating?
A. AB
B. A or B
C. O
D. All are possible
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/ABO/2
D A mating between AO and BO persons can result in an offspring with blood type A,
B, AB, or O.
- The alleged father of a child in a disputed case of paternity is blood group AB. The
mother is group O, and the child is group O. What type of exclusion is this?
A. Direct/primary/first order
B. Probability
C. Random
D. Indirect/secondary/second order
Blood bank/Evaluate laboratory data to verify test results/Genotype/Paternity testing/2
D An indirect/secondary/second order, exclusion occurs when a genetic marker is absent
in the child but should have been transmitted by the alleged father. In this case, either
A or B should be present in the child.
- If the frequency of gene Y is 0.4 and the frequency of gene Z is 0.5, one would expect
that they should occur together 0.2 (20%) of the time. In actuality, they are found
together 32% of the time. This is an example of:
A. Crossing over
B. Linkage disequilibrium
C. Polymorphism
D. Chimerism
Blood bank/Apply principles of genetics/3 Answers to Questions 6–12
B Linkage disequilibrium is a phenomenon in which alleles situated in close proximity
on a chromosome associate with one another more than would be expected from
individual allelic frequencies.
- In the Hardy-Weinberg formula, p2 represents:
A. The heterozygous population of one allele
B. The homozygous population of one allele
C. The recessive allele
D. The dominant allele
Blood bank/Apply knowledge of fundamental biological characteristics/Genetics/1
B In the Hardy-Weinberg formula (p2 + 2pq + q2), p2 and q2 represent homozygous
expressions, and 2pq represents heterozygous expression. This formula is used in
population genetics to determine the frequency of different alleles.
- In this type of inheritance, the father carries the trait on his X chromosome. He has no
sons with the trait because he passed his Y chromosome to his sons; however, all his
daughters will express the trait.
A. Autosomal dominant
B. Autosomal recessive
C. X-linked dominant
D. X-linked recessive
C In X-linked dominant inheritance, there is absence of male-to-male transmission because a male passes his Y chromosome to all of his sons and his single X
chromosome to all his daughters. All daughters who inherit the affected gene will
express the trait. An example of this type of inheritance is the Xga blood group.
- Why do immunoglobulin M (IgM) antibodies, such as those formed against ABO
antigens, have the ability to directly agglutinate RBCs and cause visible agglutination?
A. IgM antibodies are larger molecules and have the ability to bind more antigen
B. IgM antibodies tend to clump together more readily to bind more antigen
C. IgM antibodies are found in greater concentrations than IgG antibodies
D. IgM antibodies are not limited by subclass specificity
Blood bank/Apply knowledge of fundamental biological characteristics/Antibodies/1
A An IgM molecule has the potential to bind up to 10 antigens compared with a
molecule of IgG, which can bind only two.
- Which of the following enhancement mediums decreases the zeta potential, allowing
antibody and antigen to come closer together?
A. Low ionic strength solution (LISS)
B. Polyethylene glycol
C. Polybrene
D. Dithiothreitol-papain (ZZAP)
Blood bank/Apply knowledge of fundamental biological characteristics/Antigens/1
A LISS contains a reduced concentration of NaCl (0.2%) and results in a reduction in
charged ions within the ionic cloud, decreasing the zeta potential and facilitating
antigen–antibody interaction
- This type of antibody response is analogous to an anamnestic antibody reaction.
A. Primary
B. Secondary
C. Tertiary
D. Anaphylactic
Blood bank/Apply knowledge of fundamental biological characteristics/Antibodies/1
B An anamnestic response is a secondary immune response in which memory
lymphocytes respond rapidly to foreign antigen in producing specific antibody. The
antibodies are IgG and are produced at lower doses of antigen than in the primary
response.
- Which antibodies to a component of complement are contained in the rabbit
polyspecific anti-human globulin (AHG) reagent for detection of in vivo sensitization?
A. Anti-IgG and anti-C3a
B. Anti-IgG and anti-C3d
C. Anti-IgG and anti-IgM
D. All of these options
Blood bank/Apply knowledge of fundamental biological characteristics/AHG/2
B In the direct antiglobulin test (DAT), rabbit polyspecific antisera contains both an
anti-human IgG component and an antibody against the C3d component of
complement.
- Which of the following distinguishes the A1 blood group from the A2 blood group?
A. A2 antigen will not react with anti-A, A1 will react strongly (4+)
B. An A2 person may form anti-A1; an A1 person will not form anti-A1
C. An A1 person may form anti-A2, an A2 person will not form anti-A1
D. A2 antigen will not react with anti-A from a nonimmunized donor; A1 will react with any
anti-A
Blood bank/Apply knowledge of fundamental biological characteristics/ABO blood group/2
B The group A1 comprises both A1 and A antigens. Anti-A will react with both A1- and
A2-positive RBCs. A person who is group A2 may form anti-A1, but an A1 person will
not form anti-A1 (which would cause autoagglutination).
- A patient’s serum is incompatible with O cells. The patient RBCs give a negative
reaction to anti-H lectin. What is the most likely cause of these results?
A. The patient may be a subgroup of A
B. The patient may have an immunodeficiency
C. The patient may be a Bombay phenotype individual
D. The patient may have developed alloantibodies
Blood bank/Apply principles of special procedures/ABO blood group/3
C Bombay phenotype is the only ABO phenotype incompatible with O cells. The RBCs
of a Bombay phenotype individual show a negative reaction to anti-H because the cells
contain no H substance.
- What antibodies are formed by a Bombay phenotype individual?
A. Anti-A and anti-B
B. Anti-H
C. Anti-A,B
D. Anti-A, B, and H
Blood bank/Apply knowledge of fundamental biological characteristics/ABO blood
group/Bombay/1
D A Bombay phenotype individual does not express A, B, or H antigens; therefore, anti-
A, -B, and -H are formed. Because a Bombay phenotype individual has three
antibodies, the only compatible blood must be from another Bombay phenotype donor
- Acquired B antigens have been found in:
A. Bombay phenotype individuals
B. Group O persons
C. Persons of all blood groups
D. Group A persons
Blood bank/Apply knowledge of fundamental characteristics/ABO/1
D The acquired B phenomenon is only seen in group A persons.
- Blood is crossmatched on an A-positive person with a negative antibody screen. The
patient received a transfusion of A-positive RBCs 3 years ago. The donors chosen for
crossmatching were A-positive. Crossmatching was run on the automated analyzer and
yielded 3+ incompatibility. How can these results be explained?
A. The patient has an antibody to a low-frequency antigen
B. The patient has an antibody to a high-frequency antigen
C. The patient is an A2 with anti-A1
D. The patient is an A1 with anti-A2
Blood bank/Apply principles of special procedures/ABO/3
C The patient is likely an A2 with anti-A1, which is causing reactivity in the
crossmatching. A negative antibody screen rules out the possibility of an antibody to a
high-frequency antigen, and two donor units incompatible rules out an antibody to a
low-frequency antigen.
- A patient’s RBCs forward as group O, serum agglutinates B cells (4+) only. Your next
step would be:
A. Extend reverse typing for 15 minutes
B. Perform an antibody screen, including room-temperature incubation
C. Incubate washed RBCs with anti-A1 and anti-A,B for 30 minutes at room temperature
D. Test patient’s RBCs with Dolichos biflorus
Blood bank/Apply principles of special procedures/RBCs/ABO discrepancy/3
C The strong 4+ reaction in reverse grouping suggests the discrepancy is in forward
grouping. Incubating washed RBCs at room temperature with anti-A and anti-A,B will
enhance reactions.
- Which typing results are most likely to occur when a patient has an acquired B antigen?
A. Anti-A 4+, anti-B-3+, A1 cells neg, B cells neg
B. Anti-A 3+, anti-B neg, A1 cells neg, B cells neg
C. Anti-A 4+, anti-B 1+, A1 cells neg, B cells 4+
D. Anti-A 4+, anti-B 4+, A1 cells 2+, B cells neg
C In forward typing, a 1+ reaction with anti-B is suspicious because of the weak reaction
and the normal reverse grouping that appears to be group A. This may be indicative of
an acquired antigen. In the case of an acquired B antigen, the reverse grouping is the
same for a group A person. Choice A is indicative of group AB; choice B is indicative
of a group A who may be immunocompromised. Choice D may be caused by a
mistyping or an antibody against antigens on reverse cells.
- Which blood group has the least amount of H antigen?
A. A1B
B. A2
C. B
D. A1
Blood bank/Apply knowledge of fundamental biological principles/ABO/1
A The A1B blood group has the least amount of H antigen. This occurs because both A
and B epitopes are present on RBCs, compromising the availability of H epitopes. A1B
cells will yield weak reactions with anti-H lectin.
- What type RBCs can be transfused to an A2 person with anti-A1?
A. A only
B. A or O
C. B
D. AB
Blood bank/Apply knowledge of fundamental biological principles/ABO/3
B A person who is in need of RBC transfusion and is an A2 with anti-A1 can be
transfused with A or O cells because the anti-A1 is typically only reactive at room
temperature.
- What should be done if all forward and reverse ABO results as well as the autocontrol
are positive?
A. Wash the cells with warm saline, and autoadsorb the serum at 4°C
B. Retype the sample using a different lot number of reagents
C. Use polyclonal typing reagents
D. Report the sample as group AB
Blood bank/Evaluate laboratory and clinical data to specify additional tests/RBCs/ABO
discrepancy/3
A These results point to a cold autoantibody. Washing the cells with warm saline may
elute the autoantibody, allowing a valid forward type to be performed. The serum
should be adsorbed using washed cells until the autocontrol is negative. Then, the
adsorbed serum should be used for reverse typing.
- What should be done if all forward and reverse ABO results are negative?
A. Perform additional testing, such as typing with anti-A1 lectin and anti-A,B
B. Incubate at 22°C or 4°C to enhance weak expression
C. Repeat the test with new reagents
D. Run an antibody identification panel
Blood bank/Evaluate laboratory and clinical data to specify additional tests/RBCs/ABO
discrepancy/3
B All negative results may be caused by weakened antigens or antibodies. Room
temperature or lower incubation temperature may enhance expression of weakened
antigens or antibodies
- N-acetyl-D-galactosamine is the immunodominant carbohydrate that reacts with:
A. Arachis hypogaea
B. Salvia sclarea
C. Dolichos biflorus
D. Ulex europeaus
Blood bank/Apply knowledge of fundamental biological principles/ABO/2
C The immunodominant sugar N-acetyl-galactosamine confers A antigen specificity
when present at the terminus of the type 2 precursor chain on the RBC membrane.
Therefore, its presence would cause RBCs to react with anti-A1 lectin, Dolichos
biflorus
A stem cell transplant recipient was retyped when she was transferred from another hospital. What is the most likely cause of the following results?
Patient cells: Anti-A: neg; Anti-B: 4+
Patient serum: A1 cells: neg; B cells: neg
A. Viral infection
B. Alloantibodies
C. Immunodeficiency
D. Autoimmune hemolytic anemia
C The transplant recipient is probably taking immunosuppressive medication to increase
graft survival. This can contribute to the loss of normal blood group antibodies as well
as other types of antibodies
- What reaction would be the same for an A1 and an A2 person?
A. Positive reaction with anti-A1 lectin
B. Positive reaction with A1 cells
C. Equal reaction with anti-H
D. Positive reaction with anti-A,B
Blood bank/Evaluate laboratory data to make identifications/ABO discrepancy/2
D Anti-A,B should react positively with group A or B and any subgroup of A or B (with
exception of Am). An A1 (not A2) would react with anti-A1 lectin; only an A2 person
with anti-A1 would give a positive reaction with A1 cells; an A2 would react more
strongly with anti-H than A1.
- A female patient at 28 weeks’ pregnancy yields the following results:
Patient cells: Anti-A: 3+; Anti-B: 4+
Patient serum: A1 cells: neg; B cells: 1+; O cells: 1+
Which of the following could be causing the ABO discrepancy?
A. Hypogammaglobulinemia
B. Alloantibody in patient serum
C. Acquired B
D. Weak subgroup
Blood bank/Evaluate laboratory data to make identifications/ABO discrepancy/3
B The patient is most likely an AB person who has formed a cold-reacting alloantibody
reacting with B cells and O cells. An identification panel should be performed. An
acquired B person or someone with hypogammaglobulinemia should not make
antibody that would agglutinate O cells.
- Which condition would most likely be responsible for the following typing results?
Patient cells: Anti-A: neg; Anti-B: neg
Patient serum: A1 cells: neg; B cells: 4+
A. Immunodeficiency
B. Masking of antigens by the presence of massive amounts of antibody
C. Weak or excessive antigen(s)
D. Impossible to determine
Blood bank/Apply principles of basic laboratory procedures/ABO discrepancy/3
C Excessive A substance, as may be found in some types of tumors, may be neutralizing
anti-A. Weak A subgroups may fail to react with anti-A and require additional testing
techniques (e.g., room-temperature incubation) before their expression is apparent.
- Which of the following results is most likely discrepant?
Anti-A, neg Anti-B, 4+
A1 cells, neg B cells, neg
A. Negative B cells
B. Positive reaction with anti-B
C. Negative A1 cells
D. No problem with this typing
C The reverse typing should agree with the forward typing in this result. The 4+
reaction with anti-B indicates group B. A positive reaction is expected with A1 cells in
the reverse group.
- A 61-year-old male with a history of multiple myeloma underwent stem cell
transplantation 3 years ago. The donor was O positive, and the recipient was B positive.
The patient is admitted to a community hospital for fatigue and nausea. Typing results
reveal the following:
Anti-A = 0
Anti-B =0
Anti-A,B = 0
Anti-D = 4+
A1 cells = 4+
B cells = 0
How would you report this type?
A. O positive
B. B positive
C. A positive
D. Undetermined
D In a transplantation scenario, there are no methods to employ to solve the
discrepancy. The medical laboratory scientist must rely on the patient history of donor
type and recipient type and the present serological picture. Giving a B-positive
recipient an O-positive transplant constitutes a minor ABO mismatch. The forward
type resembles the donor. The reverse type still resembles the recipient. The ABO type
reported out does not fit a pattern resulting in an undetermined type.
- A complete Rh typing for antigens C, c, D, E, and e revealed negative results for C, D,
and E. How is the individual designated?
A. Rh positive
B. Rh negative
C. Positive for c and e
D. Impossible to determine
Blood bank/Apply knowledge of fundamental biological characteristics/Rh typing/1
B Rh positive refers to the presence of D antigen; Rh negative refers to the absence of D
antigen. These designations are for D antigen only and do not involve other Rh
antigens.
- How is an individual with genotype Dce/dce classified?
A. Rh positive
B. Rh negative
C. Rhnull
D. Total Rh
Blood bank/Apply knowledge of fundamental biological characteristics/Rh typing/2
A This individual has D antigen and is classified as Rh positive. Any genotype containing
D antigen will be considered Rh positive
- If a patient has a positive DAT, should you perform a weak D test on the cells?
A. No, the cells are already coated with antibody
B. No, the cells are Rhnull
C. Yes, the immunoglobulin will not interfere with the test
D. Yes, Rh reagents are enhanced in protein media
Blood bank/Apply knowledge of fundamental biological characteristics/Rh typing/3
A If a person has a positive DAT, the RBCs are coated with immunoglobulin. If a test for
weak D were performed, the test would yield positive results independent of the
presence or absence of D antigen on the RBCs.
- Which donor unit is selected for a recipient with anti-c?
A. r´r
B. R0R1
C. R2r´
D. r´ry
Blood bank/Apply knowledge of fundamental biological characteristics/Rh typing/3
D The designation r’ is dCe and ry is dCE, neither of which contains c antigen. The other
three Rh types contain c antigen and could not be used in transfusion for a person with
anti-c.
- Which genotype usually shows the strongest reaction with anti-D?
A. DCE/DCE
B. Dce/dCe
C. D–/D–
D. –CE/–ce
Blood bank/Apply knowledge of fundamental biological characteristics/Rh typing/1
C The phenotype that results from D–/D– is classified as enhanced D because it shows a
stronger reaction than expected with anti-D. Such cells have a greater amount of D
antigen than normal. This is thought to result from a larger quantity of precursors being
available to the D genes because there is no competition from other Rh genes.
- Why is testing for Rh antigens and antibodies different from ABO testing?
A. ABO reactions are primarily caused by IgM antibodies and usually occur at room
temperature; Rh antibodies are IgG and agglutination usually requires a 37°C incubation
and enhancement media
B. ABO antigens are attached to receptors on the outside of the RBC and do not require any
special enhancement for testing; Rh antigens are loosely attached to the RBC membrane
and require enhancement for detection
C. Both ABO and Rh antigens and antibodies have similar structures, but Rh antibodies are
configured so that special techniques are needed to facilitate binding to Rh antigens
D. There is no difference in ABO and Rh testing; both may be conducted at room
temperature with no special enhancement needed for reaction
Blood bank/Apply knowledge of fundamental biological characteristics/Rh system/1
A Detection of ABO and Rh antigens and antibodies requires different reaction
conditions. ABO antibodies are naturally occurring IgM molecules and react best at
room temperature. Rh antibodies are generally immune IgG molecules that result from
transfusion or pregnancy. Detection may require 37°C incubation and/or enhancement
techniques
- Testing reveals a weak D that reacts 1+ after indirect antiglobulin testing (IAT). How is
this result classified?
A. Rh-positive
B. Rh-negative, Du positive
C. Rh-negative
D. Rh-positive, Du positive
Blood bank/Apply knowledge of standard operating procedures/Components/Rh label/2
A Blood tested for weak D that shows 1+ reaction after IAT is classified as Rh positive.
The weak D designation is not noted in the reporting of the result.
- What is one possible genotype for a patient who develops anti-C antibody?
A. R1r
B. R1R1
C. r’r
D. rr
Blood bank/Apply knowledge of fundamental biological characteristics/Rh typing/2
D Only rr (dce/dce) does not contain C antigen. A person will form alloantibodies only to
the antigens he or she lacks.
- A patient developed a combination of Rh antibodies: anti-C, anti-E, and anti-D. Can
compatible blood be found for this patient?
A. It is almost impossible to find blood lacking C, E, and D antigens
B. rr blood could be used without causing a problem
C. R0R0 may be used because it lacks all three antigens
D. Although rare, ryr blood may be obtained from close relatives of the patient
B The genotype rr (dce/dce) lacks D, C, and E antigens and would be suitable for an
individual who has developed antibodies to all three antigens. This is the most
common Rh-negative genotype and is found in nearly 14% of blood donors who are
white.
- A patient tests positive for weak D but also appears to have anti-D in his serum. What
may be the problem?
A. Mixup of samples or testing error
B. Most weak D individuals make anti-D
C. The problem could be caused by a disease state
D. A D mosaic may make antibodies to missing antigen parts
Blood bank/Apply knowledge to identify sources of error/Rh antibodies/2
D The D antigen comprises different parts designated as a mosaic. If an individual lacks
parts of the antigen, he or she may make antibodies to the missing parts if exposed to
the whole D antigen
- Which offspring is not possible from a mother who is R1R2 and a father who is R1r?
A. DcE/DcE
B. Dce/DCe
C. DcE/DCe
D. Dce/dce
A DcE/DcE (R2R2) is not possible because R2 can be inherited only from the mother and
is not present in the father.
- Which weak D phenotypes necessitate Rh immune globulin (RhIg) prophylaxis?
A. 1
B. 2
C. 3
D. None of the above
Blood bank/Apply knowledge of biological characteristics/Rh testing/3
D Weak D phenotypes 1, 2, and 3 (as well as 4) are not associated with formation of
anti-D negating RhIg prophylaxis. Weak D phenotypes 5, 11, 15, 19, and 20 would
require RhIg prophylaxis
- What antibodies could an R1R1 make if exposed to R2R2 blood?
A. Anti-e and anti-C
B. Anti-E and anti-c
C. Anti-E and anti-C
D. Anti-e and anti-c
Blood bank/Apply knowledge of fundamental biological characteristics/Rh antibodies/2
B The R1R1 (DCe/DCe) individual does not have the E or c antigen, and could make
anti-E and anti-c antibodies when exposed to R2R2 cells (DcE/DcE).
- What does the genotype —/— represent in the Rh system?
A. Rh negative
B. D mosaic
C. Rhnull
D. Total Rh
Blood bank/Evaluate laboratory data to make identifications/Rh system/Rh antigens/2
C A person who is Rhnull shows no Rh antigens on his or her RBCs. Loss of Rh antigens
is very unlikely to happen because Rh antigens are integral parts of the RBC
membrane. The Rhnull phenotype can result from either genetic suppression of the Rh
genes or inheritance of amorphic genes at the Rh locus.
- What techniques are necessary for weak D testing?
A. Saline + 22°C incubation
B. Albumin or LISS + 37°C incubation
C. Saline + 37°C incubation
D. 37°C incubation + IAT
Blood bank/Apply knowledge of basic laboratory procedures/Rh system/2
D Weak D testing requires both 37°C incubation and the IAT procedure. Anti-D is an
IgG antibody, and attachment of the D antigen is optimized at warmer temperatures.
AHG in the IAT phase facilitates lattice formation by binding to the antigen–antibody
complexes
- A patient types as AB and appears to be Rh positive on slide typing. What additional
tests should be performed for tube typing?
A. Rh negative control
B. Direct antiglobulin test
C. Low-protein Rh antisera
D. No additional testing is needed
Blood bank/Evaluate laboratory data to verify test results/Rh system/2
A An Rh-negative control (patient cells in saline or 6% albumin) should be run if a
sample appears to be AB positive. The ABO test serves as the Rh control for other
ABO types.
- According to the Wiener nomenclature and/or genetic theory of Rh inheritance:
A. There are three closely linked loci, each with a primary set of allelic genes
B. The alleles are named R1, R2, R0, r, r’, r”, Rz, and ry
C. There are multiple alleles at a single complex locus that determine each Rh antigen
D. The antigens are named D, C, E, c, and e
Blood bank/Apply knowledge of fundamental biological principles/Rh system/2
C Wiener proposed a single-locus theory for Rh, with multiple alleles determining
surface molecules that embody numerous antigens.
- The Wiener nomenclature for the E antigen is:
A. hr’
B. hrv’
C. rh”
D. Rh0
Blood bank/Apply knowledge of fundamental biological principles/Rh typing/1
C The Wiener designation for the E antigen is rh”. The Wiener designation hr’ denotes
c, hr” denotes e, and Rh0 is D.
- A physician orders 2 units of leukocyte-reduced RBCs. The patient is a 55-year-old
male with anemia. He types as an AB negative, and his antibody screen is negative.
There is only 1 unit of AB negative in inventory. What is the next blood type that should
be given?
A. AB positive (patient is male)
B. A negative
C. B negative
D. O negative
Blood bank/Evaluate sources of errors/Rh systems/3
B Although giving Rh-positive RBCs to an Rh-negative patient would not harm the
patient in this case, because he is male, giving A negative would be the first choice.
You should not expose a patient to the D antigen, if possible, and the residual anti-B in
a unit of A-negative packed cells is less immunogenic than giving B or O RBCs.
- Which technology may report an Rh-weak D positive as Rh negative?
A. Gel system
B. Solid phase
C. Tube testing
D. None of these options
Blood bank/Apply knowledge of laboratory procedures/Rh system/2
A The Gel system cannot detect a weak D phenotype because there is no washing phase
in the Gel system.
- A patient has the Lewis phenotype Le(a-b-). An antibody panel reveals the presence of
anti-Lea. Another patient with the phenotype Le(a-b+) has a positive antibody screen;
however, a panel reveals no conclusive antibody. Should anti-Lea be considered a
possibility for the patient with the Le(a-b+) phenotype?
A. Anti-Lea should be considered as a possible antibody
B. Anti-Lea may be a possible antibody, but further studies are needed
C. Anti-Lea is not a likely antibody because even Leb individuals secrete some Lea
D. Anti-Lea may be found in saliva but not detectable in serum
Blood bank/Apply knowledge of fundamental biological characteristics/Blood groups/2
C Anti-Lea is produced primarily by persons with the Le(a-b-) phenotype because Le(ab+)
persons still have some Lea antigen present in saliva. Although Lea is not present
on their RBCs, Le(a-b+) persons do not form anti-Lea.
- A medical laboratory scientist (MLS) is having great difficulty resolving an antibody
mixture. One of the antibodies is anti-Lea. This antibody is not clinically significant in
this situation, but it needs to be removed to reveal the possible presence of an underlying
antibody of clinical significance. What can be done?
A. Perform an enzyme panel
B. Neutralize the serum with saliva
C. Neutralize the serum with hydatid cyst fluid
D. Use dithiothreitol (DTT) to treat the panel cells
Blood bank/Apply knowledge of fundamental biological characteristics/Blood groups/3
B Saliva from an individual with the Le gene contains the Lea antigen. This combines
with anti-Lea, neutralizing the antibody. Panel cells treated with DTT (0.2M) lose
reactivity with anti-K and other antibodies, but not anti-Lea. Hydatid cyst fluid
neutralizes anti-P1.
- What type of blood should be given to an individual who has anti-Leb that reacts 1+ at
the IAT phase?
A. Blood that is negative for Leb antigen
B. Blood that is negative for both Lea and Leb antigens
C. Blood that is positive for Leb antigen
D. Lewis antibodies are not clinically significant, so any type of blood may be given
Blood bank/Apply knowledge of fundamental biological characteristics/Blood group
antibodies/3
A Lewis antibodies are generally not considered clinically significant unless they react at
37°C or at the IAT phase. The antibody must be honored in this scenario due to its
reactivity at the IAT phase of testing.
- Which of the following statements is true concerning the MN genotype?
A. Antigens are destroyed using bleach-treated cells
B. Dosage effect may be seen for both M and N antigens
C. Both M and N antigens are impossible to detect because of cross-interference
D. MN is a rare phenotype seldom found in routine antigen typing
Blood bank/Apply knowledge of fundamental biological characteristics/Blood groups/2
B Dosage effect is the term used to describe the phenomenon of an antibody that reacts
more strongly with homozygous cells than with heterozygous cells. Dosage effect is a
characteristic of the genotype MN because the M and N antigens are both present on
the same cell. This causes a weaker reaction than seen with RBCs of either the MM or
NN genotype, which carry a greater amount of the corresponding antigen.
- Anti-M is sometimes found with reactivity detected at the immediate spin (IS) phase that
persists in strength to the IAT phase. What is the main testing problem with a strong
anti-M?
A. Anti-M may not allow detection of a clinically significant antibody
B. Compatible blood may not be found for the patient with a strongly reacting anti-M
C. Anti-M cannot be removed from serum
D. Anti-M may react with the patient’s own cells, causing a positive autocontrol
Blood bank/Apply knowledge of fundamental biological characteristics/Blood groups/2
A Although anti-M may not be clinically significant, a strongly reacting anti-M that
persists through to the IAT phase may interfere with detection of a clinically
significant antibody that reacts only at IAT.
- A patient is suspected of having paroxysmal cold hemoglobinuria (PCH). Which pattern
of reactivity is characteristic of the Donath-Landsteiner antibody, which causes this
condition?
A. The antibody attaches to RBCs at 4°C and causes hemolysis at 37°C
B. The antibody attaches to RBCs at 37°C and causes agglutination at the IAT phase
C. The antibody attaches to RBCs at 22°C and causes hemolysis at 37°C
D. The antibody attaches to RBCs and causes agglutination at the IAT phase
Blood bank/Apply knowledge of fundamental biological characteristics/Blood group
antibodies/1
A The Donath-Landsteiner antibody has anti-P specificity with biphasic activity. The
antibody attaches to RBCs at 4°C and then causes the RBCs to hemolyze when
warmed to 37°C.
- How can interfering anti-P1 antibody be removed from a mixture of antibodies?
A. Neutralization with saliva
B. Agglutination with human milk
C. Combination with urine
D. Neutralization with hydatid cyst fluid
Blood bank/Apply principles of special procedures/Blood group antibodies/1
D Hydatid cyst fluid contains P1 substance, which can neutralize anti-P1 antibody.
- Which antibody is frequently seen in patients with warm autoimmune hemolytic anemia
(WAIHA)?
A. Anti-Jka
B. Anti-e
C. Anti-K
D. Anti-Fyb
Blood bank/Apply knowledge of fundamental biological characteristics/Blood group
antibodies/2
B Anti-e is frequently implicated in cases of WAIHA.
The corresponding antigen is characterized as high frequency in the Rh system and can
mask the presence of other alloantibodies.
- A patient’s antibody shows strong reactions in all test phases. All screen and panel cells
are positive. Serum is then tested with a cord blood cell, and the reaction is negative.
What antibody is suspected?
A. Anti-I
B. Anti-i
C. Anti-H
D. Anti-p
Blood bank/Apply principles of special procedures/Antibody ID/2
A Adult cells contain mostly I antigen, and anti-I would react with all adult cells found
on screen or panel cells. Cord blood cells, however, contain mostly i antigen and
would test negative or only weakly positive with anti-I.
- Which group of antibodies is commonly found as cold agglutinins?
A. Anti-K, anti-k, anti-Jsb
B. Anti-D, anti-e, anti-C
C. Anti-M, anti-N
D. Anti-Fya, anti-Fyb
Blood bank/Apply knowledge of fundamental biological characteristics/Blood group
antibodies/1
C Antibodies to the M and N antigens are IgM antibodies commonly found as cold
agglutinins.
- Which of the following antibodies characteristically gives a refractile mixed-field
appearance?
A. Anti-K
B. Anti-Dia
C. Anti-Sda
D. Anti-s
Blood bank/Apply knowledge of fundamental biological characteristics/Blood group
antibodies/1
C Anti-Sda characteristically gives a refractile mixed-field agglutination reaction in the
IAT phase. The refractile characteristic is more evident under the microscope.
- What does the 3+3 rule ascertain?
A. An antibody is ruled in
B. An antibody is ruled out
C. 95% confidence that the correct antibody has been identified
D. 95% confidence that the correct antibody has not been identified
Blood bank/Apply principles of basic laboratory procedures/Antibody ID/1
C The 3+3 rule ascertains correct identification of antibody at a confidence level of
95%. For this level to be met, reagent RBCs are found containing target antigen to
suspected antibody that react in test phase; likewise, reagent RBCs devoid of antigen will not react in test phase.
- The k (Cellano) antigen is a high-frequency antigen and is found on most RBCs. How
often would one expect to find the corresponding antibody?
A. Often, because it is a high-frequency antibody
B. Rarely, because most individuals have the antigen and therefore would not develop the
antibody
C. Depends on the population, because certain racial and ethnic groups show a higher
frequency of anti-k
D. Impossible to determine without consulting regional blood group antigen charts
Blood bank/Calculate/Hemotherapy/1
B k antigen is found with a frequency of 99.8%; therefore, k-negative individuals are
rare. Because of this, the occurrence of anti-k is also rare.
- Which procedure would help to distinguish between anti-e and anti-Fya in an antibody
mixture?
A. Lowering the pH of test serum
B. Running an enzyme panel
C. Using a thiol reagent
D. Running an LISS panel
Blood bank/Apply principles of special procedures/Antibody ID/2
B Enzyme-treated cells will not react with Duffy antibodies. Rh antibodies react more
strongly with enzyme-treated RBCs. An enzyme panel, therefore, would enhance
reactivity of anti-e and destroy reactivity to anti-Fya.
- Which characteristics are true of all three of the following antibodies: anti-Fya, anti-
Jka, and anti-K?
A. Detected at the IAT phase; may cause hemolytic disease of the fetus and newborn
(HDFN) and hemolytic transfusion reactions
B. Not detected with enzyme-treated cells
C. Requires the IAT technique for detection; usually not associated with HDFN
D. Enhanced reactivity with enzyme-treated cells; may cause severe hemolytic transfusion
reactions
Blood bank/Apply principles of special procedures/Antibody ID/2
A Anti-Fya, anti-Jka, and anti-K are usually detected at IAT and all may cause HDFN
and transfusion reactions that may be hemolytic. Reactivity with anti-Fya is lost with
enzyme-treated RBCs, but reactivity with anti-Jka is enhanced with enzyme-treated
cells. Reactivity with anti-K is unaffected by enzyme-treated cells.
- A patient is admitted to the hospital. Medical records indicate that the patient has a
history of anti-Jka. When you performed the type and screen, the type was O positive,
and the screen was negative. You should:
A. Crossmatch using units negative for Jka antigen
B. Crossmatch random units, since the antibody is not demonstrating
C. Request a new sample
D. Repeat the screen with enzyme-treated screening cells
Blood bank/Apply principles of basic laboratory procedures/Antibody ID/3
A The Kidd antibodies are notorious for disappearing from serum, yielding a negative
result for the antibody screen. If a patient has a history of a Kidd antibody, blood must
be crossmatched using antigen-negative units. If the patient is transfused with the
corresponding antigen, an anamnestic response may occur with a subsequent hemolytic
transfusion reaction.
- An MLS performs an antibody study and finds 1+ and weak positive reactions for
several of the panel cells. The reactions do not fit a pattern. Several selected panels and
a patient phenotype do not reveal any additional information. Serum is diluted and
retested, but the same reactions persist. What type of antibody may be causing these
results?
A. Antibody to a high-frequency antigen
B. Antibody to a low-frequency antigen
C. High titer low avidity (HTLA)
D. Anti-human leukocyte antigen (anti-HLA)
Blood bank/Evaluate laboratory data to make identifications/Antibody ID/3
C HTLA antibodies may persist in reaction strength, even when diluted. These
antibodies are directed against high-frequency antigens (e.g., Cha). They are not
clinically significant but, when present, are responsible for a high incidence of
incompatible crossmatches.
- An antibody is detected in a pregnant woman and is suspected of being the cause of
fetal distress. The antibody reacts at the IAT phase but does not react with DTT-treated
cells. This antibody causes in vitro hemolysis. What is the most likely antibody
specificity?
A. Anti-Lea
B. Anti-Lua
C. Anti-Lub
D. Anti-Xga
Blood bank/Evaluate laboratory data to make identifications/Antibody ID/3
C Of the antibodies listed, only Lub is detected in the IAT phase, causes in vitro
hemolysis, may cause HDFN, and does not react with DTT-treated cells.
- What sample is best for detecting complement-dependent antibodies?
A. Plasma stored at 4°C for no longer than 24 hours
B. Serum stored at 4°C for no longer than 48 hours
C. Either serum or plasma stored at 20°C to 24°C no longer than 6 hours
D. Serum heated at 56°C for 30 minutes
Blood bank/Apply principles of basic laboratory procedures/Antibody ID/2
B Serum stored at 4°C for no longer than 48 hours preserves complement activity.
Plasma is inappropriate because most anticoagulants chelate calcium needed for
activation of complement. Heating the serum to 56°C destroys complement.
- Which antibody would not be detected by group O screening cells?
A. Anti-N
B. Anti-A1
C. Anti-Dia
D. Anti-k
Blood bank/Apply principles of special procedures/Antibody ID/1
B ABO antibodies are not detected by group O screening cells because O cells contain
no A or B antigens.
- Refer to Panel 1. Which antibody is most likely implicated?
A. Anti-Fyb
B. Anti-Jkb
C. Anti-e
D. Anti-c and anti-K
Blood bank/Apply principles of special procedures/Antibody ID/2
B The pattern clearly fits that of anti-Jkb, an antibody that usually reacts best at IAT.
The weaker reactions are caused by the dosage effect found on cells that are
heterozygous for the Jkb antigen.
- SITUATION: An emergency trauma patient requires transfusion. Six units of blood are
ordered stat (immediately). There is no time to draw a patient sample. O-negative blood
is issued. When will compatibility testing be performed?
A. Compatibility testing must be performed before blood is issued
B. Compatibility testing will be performed when a patient sample is available
C. Compatibility testing may be performed immediately by using donor serum
D. Compatibility testing is not necessary when blood is issued in emergency situations
Blood bank/Apply knowledge of laboratory operations/Crossmatch/3
B When patient serum is available, it will be crossmatched with donor cells. Patient
serum might contain antibodies against antigens on donor cells that may destroy donor
cells. If an incompatibility is discovered, the problem will be reported immediately to
the patient’s physician.
- How would autoantibodies affect compatibility testing?
A. No effect
B. The DAT result would be positive
C. ABO, Rh, antibody screen, and crossmatching may show abnormal results
D. Results would depend on the specificity of autoantibody
Blood bank/Evaluate laboratory data to make identifications/Antibody ID/3
C Autoantibodies may cause positive reactions with screening cells, panel cells, donor
cells, and patient cells. The DAT result will be positive; however, DAT is not included
in compatibility testing.
- An antibody screen is reactive at the IAT phase of testing with all three cells of a threecell
screen, and the autocontrol is negative. What is a possible explanation for these
results?
A. A cold alloantibody
B. High-frequency alloantibody or a mixture of alloantibodies
C. A warm autoantibody
D. A cold and warm alloantibody
Blood bank/Evaluate laboratory data to make identifications/Antibody ID/3
B High-frequency alloantibodies or a mixture of alloantibodies may cause all three
screening cells to be positive. A negative autocontrol would rule out autoantibodies
- What does a minor crossmatch consist of?
A. Recipient plasma and recipient RBCs
B. Recipient plasma and donor RBCs
C. Recipient RBCs and donor plasma
D. Donor plasma and donor RBCs
Blood bank/Apply knowledge of laboratory operations/Crossmatch/1
C A minor crossmatch consists of recipient RBCs and donor serum or plasma.
- Can crossmatching be performed on October 14 using a patient sample drawn on
October 12?
A. Yes, a new sample would not be needed
B. Yes, but only if the previous sample has no alloantibodies
C. No, a new sample is needed because the 2-day limit has expired
D. No, a new sample is needed for each testing
Blood bank/Apply knowledge of standard operating procedures/Crossmatch/2
A Compatibility testing may be performed on a patient sample within 3 days of the
scheduled transfusion; however, if the patient is pregnant or was transfused within 3
months, the sample must be less than 3 days old.
- A type and screen was performed on a 32-year-old woman, and the patient was typed as
AB negative. There are no AB-negative units in the blood bank. What should be done?
A. Order AB-negative units from a blood supplier
B. Check inventory of A-, B-, and O-negative units
C. Ask the patient to make a preoperative autologous donation
D. Nothing—the blood will probably not be used
Blood bank/Apply principles of basic laboratory procedures/Crossmatch/2
B An AB person is the universal recipient and may receive any blood type; because only
a type and screen were ordered and blood may not be used, check inventory for A-, B-,
and O-negative units.
- What ABO types may donate to any other ABO type?
A. A negative, B negative, AB negative, O negative
B. O negative
C. AB negative
D. AB negative, A negative, B negative
B An O-negative individual has no A or B antigens and may donate RBCs to any other
ABO type.
- What type(s) of RBC(s) is (are) acceptable to transfuse to an O-negative patient?
A. A negative, B negative, AB negative, or O negative
B. O negative
C. AB negative
D. AB negative, A negative, B negative
Blood bank/Apply knowledge of fundamental biological characteristics/Crossmatch/2
B An O-negative individual has both anti-A and anti-B and may receive only O-negative
RBCs.
- An MLS removed 4 units of blood from the blood bank refrigerator and placed them on
the counter. A clerk was waiting to take the units for transfusion. As she checked the
paperwork, she noticed that one of the units was leaking onto the counter. What should
she do?
A. Issue the unit if the RBCs appear normal
B. Reseal the unit
C. Discard the unit
D. Call the medical director and ask for an opinion
Blood bank/Apply knowledge of standard operating procedures/Crossmatch/3
C Leaking may indicate a broken seal or a puncture, which indicates possible
contamination of the unit, even if the RBCs appear normal. The unit should be
discarded