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Qualitative analysis > Basic radiclas > Flashcards

Basic radiclas Flashcards

1
Q

group 1 ? and group reagent
Do they show any reaction with water

A

aag, prabhu honge
Ag+ , Pb+, {(Hg)2 2+}
Dil Hcl
reacts to form agcl , pbcl2, hg2cl2
all these are white salts.
No reaction with cold water, but PbCl2 dissolves in hot water!

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2
Q

Group 2 radicals?
group reagent ?

A

Cd sun prabhu hoge bimaar , cuch aisa sunao 4 baar.
Cd, Sn 2+ , Pb 2+ , Hg2+ , Bi3+ , Cu2+ , As 3+.
Sn4 + .
and finally Sb 3+

Group reagent is H2S in dil HCl

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3
Q

Which of the group 2 radicals are completely soluble in Yellow ammonium sulphate

A

As 3+,
Sn 2+
Sn4+

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4
Q

what are the colours of the group 2 radicals in learnt order ?
colour of Sb2S3

A

Colour of Sb thing is orange
in learnt order
Cd sun prabhu hoge binmaar, such aisa sunao chaar baar
the colours are Yellow, brown , black , black , black , black , yellow yellow.

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5
Q

what are the black ppts which do not dissolve in any acid but only in aqua regia

A

Hgs

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6
Q

Group 3 radicals ( hint all have +3 state )
what is the group reagent

A

Al, Fe Cr
Nh4oh in presence of Nh4cl

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7
Q

what are the colours of the group three radicals

A

all of them form hydroxides .
Fe(oh)3 - reddish brown
Al(oh)3 - white
Cr(oh)3 - green .

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8
Q

What are the group of 4 radicals
what is the group reagent

A

Zn dagi , Mn ein , Co i , N{h}i
the reagent is H2S in the presence of Nh4Oh

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9
Q

what the colours of group 4

A

Zns Mns Cos Nis
Gry white , Buff, black black

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10
Q

what are the group 5 radicals
what are the reagents of group 5

A

S{i}r Ca Ba{g}
(Nh4)2C03 in presence of Nh4oh

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11
Q

what is 0 grp

A

Nh4+
group reagent is Naoh
forms { Nh3 } gas

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11
Q

what are the colours of group 5 radicals

A

SrCo3 - white
CaCo3 - white
Baco3 - white

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11
Q

which ions give white pppt turning grey on addtion of X
I) write white compounds
ii) what is grey compond
iii) Metal Y when added to the chloride of this ion gives a moisture absorber Z
the metal ( which acts like what on the metal turnings)
iv) when the chloride of this ion is reacted with KI , it forms which coloured ppt .
v) on excess it forms what soluble compounds.

A

the ion is Hg2+
X= sncl2
i ) white - Hg2cl2
II) Hg
iii) Cu + Hgcl2 = Cucl2 (Z) + Hg ( acts as shiny deposit on copper turnings)
iv) Hgcl2 + KI = HgI2 ( orange colour )
v) excess
K2HgI4 which is soluble

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12
Q

what is group 6

A

Mg+2
group reagent - Na2Hpo4
forms - MgNh4po4
white colour

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13
Q

Group2A
here ppt is heated with dil X
all sulphides of 2a except H are converted to nitrates which are soluble in ????
Group 2B
the sulphides of this grp , are first oxidised to higher suphides which then form which compounds . are they soluble?

A

X = hno3
H = HgS
soluble in water

grp 2b
they form thio compounds which are then soluble

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13
Q
A
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13
Q

solution of Pbcl2 and X gives yellow ppt
i) this ppt is insoluble in Y and solble in Z
i a ) write reaction of ppt with Z
ii) Pbcl2 forms another yellow ppt with C
iii) Pbcl2 with dil h2s04 , gives white ppt D , where D is soluble in N

A

X is k2cr04
forms ppt Pbcro4 which is yellow
+ 2 kcl .
Y - acetic acid
Z naoh
Pbcro4 + Naoh = Na2pbo2 + na2cro4
C - Iodide solution
Pbcl2 + Ki = PbI2 + Kcl ( PBI2 is yellow )
D - Pbso4
N - Ammonium acetate.
reaction with ammonium acetate forms
(Ch3coo)2Pb

13
Q

Agcl dissolves in Y to form Z ( chloride )
i) when dilute H is added to above Z , it forms white ppt A plus some nitrate
ii) When KI added to Z , which colour ppt is obtained along with gas F
iii) reaction of K2cr04 with Z gives which coloured ppt
iv)Z + na2c03 = B ( ppt )
v) this ppt ( B ) when heated gives a compound T with release of Co2
Vi) Z + KCN = white ppt U. When excess of KCN is used, a soluble substance J is formed
Name all

A

Y = Nh4oh
Z= [Ag(Nh3)2Cl] = diamminesilver(1) chloride
H = Hno3
A = Agcl + Nh4no3
reaction with KI = AgI ( yellow ppt ) +
gases are KCL + NH3

reaction with K2cr04 **gives brick red ppt **
= Agcro4 + same gases as above.
B = Ag2co3
T = Ag2o ( colour = brown black) + CO2
U = AgCN —– excess ——- [Ag(CN)2] which is soluble

13
Q
A
13
Q

ion X’s ppt dissolves in dil HCL and addition of water gives cloudy white ppt ?
X+ KI = which coloured ppt
ii) X + Y + NAoh = C + Black ppt ( V) + G ( metal ion )

A

X= Bi+3
X + HCL = BICL3
This BiCL3 + water = BIoCl
ii ) BiI3 = which is black ppt
iii) Y = Na2sno2
C= Na2Sno3
V= Bi
Na+ = G

14
Q

antimony ion Sb3+ in the form of their chlorides on additions of water gives what ppt

A

Sbcl3+ H20 = Sb0CL ( white ppt ) + 2HCl

14
Q

which substance H used as some electrode when treated with X turns black ?
i) this black residue dissolves in A to form C
ii) This H forms which colour ppt with stannous chloride with gradually turns which colour
iii) H + KI = V + 2KCL
what is the colour of V

A

H = Hg2Cl2
X = NH4poh
the black compound is Hg+ Hg(NH2)CL
A = aqua regia
C = Hgcl2
reaction with stannous chloride
to form Hg2Cl2 which is H again ( white ppt)
later , it forms 2Hg which is grey ppt
V = Hg2I2 which is green in colour .

14
Q

Which ion gives yellow ppt with H2S
ii) this yellow ppt X +8 HNo3 ( hot and dilute) = Y + gas + S ( sulphur )
iii) Y + NH4oh = COmplex D which is colourless
iv ) ion + CN- = white ppt W
v) ion + K4Fe(cn)6 = bluish white ppt G +

A

Cd2+
X = CdS
Y= Cd(no3)2 + gas ( NO )
D= Cd(NH3)42 colourless
W = Cd(CN)2
G = Cd2[ Fe(CN)6]

15
Q

which ions in the form of Sncl2 give white ppt with Hgcl2 and turn which colour on standing , give equations

A

SN2+ and Sn4+
White ppt = Hg2Cl2
it turns black on standing = Hg
( repeated equations )

15
Q

ions X gives deep blue with excess of Y
i) X gives chocolate brown ppt with Z
ii) IOn X with S gives black ppt
iii) ion + OH - gives which colour ppt
iv ) ion + which other ion gives a brown product
v) Ion + V gives yellow ppt ( unstable ) which further dissociates into D and CN
vi) D + KCN ( excess ) gives B

A

X = Cu2+
Y = Nh4oh
the deep blue comp’d is
[Cu(NH3)4] 2+
Z = K4[Fe(CN)6]
brown ppt is = [Cu2(fe(CN)6)}
S= SCN-
black ppt = Cu(SCN)2

with OH- gives
Cu(OH)2 ( blue ppt )

Cu2+ + I- =
{Cu2I2+ I3-} this is brown

V = CN-
yellow ppt
Cu(CN)2
D = CUCN
B = K3[CU(CN)4)]

15
Q

Which ion gives yellow ppt with ammonium molybdate and Hno3

A

As+3 + HN03 = As+5 ( H3AsO4)

15
Q

What are group 3 catiosn
what is group reagnet?

A

since grp 3 , they show +3 charge
Al Fe Cr
grp reagent
Nh4oh , Nh4cl
Fe(oh)3 reddish brown
CrOh3 green ppt
Aloh)3 white ppt

15
Q

when a brownish ppt of Fe is added to hcl and is divided into three parts :
I ) part 1 is added to X to form a blue colour solution Y
II) part two is added to S to form a red colour solution Z
iii) part three is added to K3feCN6 to forma another brown coloured ppt B

A

the initial brown ppt is Feoh)3 when reacts with Hcl forms Fecl3

I) X = K4( fe(CN)6)]
Y = prussian blue = Fe4(iii)[Fe(ii)(CN)6]3
ii) S = KCNS Z = Fe(CNS)3
iii) B = Fe(iii)[Fe(ii)CN)6]

15
Q

when a white ppt of Al is dissolved in dil hcl followed by naoh , it forms a ppt of the same compound which dissolves in excess of what to form what ?
i) When the last compound is added to C , the white ppt reappears. conforming which ions presence ?

A

white ppt - Al(OH)3
dissolves in excess of = NaOh to form
NaAlo2
NaAlO2 + C ( NH4Cl)
it conforms Al 3+ on

15
Q

Green ppt of X is insoluble in NaOH but addition of What water forms a yellow coloured solution of G write reaction
II) when C is added to G , along with Y , another yellow ppt of P conforms which ion presence .

A

X = Cr(OH)3
Br+H20 ( br2 water )
G = Na2Cr04
C = Acetic acid ( Ch3cooh)
Y = CH3cooh)2Pb ( lead acetate)
P = Pb(Cro4)
it conforms Cr3+ ion

16
Q

in group 3 conformations, as the reagent , which why is HNo3 added
ii) and why is the amont of Hno3 small

A

it will convert Fe2+ to fe3+
ii) amt is small becuase otherwise ,
it will convert Mn2+ to Mn3+

17
Q

when we wash the precipitate of group four , and then dissovle i naqua regia,
ii) extrract the residue with water
THese sulphides, MS ( m= ni or CO )
when reacted with Hcl and nacscent O give MCl2
i) if it is D , then it will react with F in the presence of H to give red coloured ppt ( cherry red ) which conforms

ii) I mole of D reacts with how many moles of F to give the product with how many intramolecular H bonds?

iii) D + bromine water in the presence of J gives black residue of T along with the formation of what gas
Iv ) D + U gives green ppt O and when U is in excess forms R which is soluble.

A

D= Nicl2
F = Dimethlyglyoxime ( DMG)
H= NH4Oh
red ppt = two intramolecular H bonding,
2 ligands of Dmg attached to NI
DMG =
Ch3-C=NOH
|
Ch3-C=NOh
1 mole of Ni reacts with 2 moles of Dmg

iii) J = Nahco3
T = Ni203
along with formation of Co2

iv)
U = KCN gives green ppt of
Ni(Cn)2 ( green )
on exces of KCN
forms a soluble complx.
= K2[Ni(CN)4]

17
Q

if in group four procedure with Hcl and and washing with water,etc
Cocl2 is formed, then it reacts with crystals G in presence of which organic compound to give which colored etheral layer?
ii) Upon addition of bromine water to COcl2 in the presence of Y , it gives which colour solution of conformation.
iii) upon reaction of Cocl2 with KCn , it gives compnd R which is reddish brown in colour, and then due ot excess KCN, it gives a compound which’s is colour is what?

A

G= Nh4CNS
ether
blue coloured etheral layer
=
(NH4)2[Co(CSN)4] ( BLUe )

Y = Nahco3
bromine water to cocl2 in presece of this gives green colour solution of
Na3[Co(iii)(Co3)3] ( green )

upon reaction with KCN ,
Co(CN)2 which is reddish brown in colour
Excess of KCN gives k4[Co(CN)6] which is yellowish brown in colour

18
Q

When MNS of group4 dissolves’ in HCl to form MCl2
i) Naoh converts this compound into Y
and to this Y add bromine water which forms oxidatiion product of this which is U ( which colour is this U )
ii)
to this pptated U , add conc hno3 and R and T and it will oxidise to which coloured solution which conforms Mn2+ ion

A

Y = Mn(Oh) 2
U = MnO2 which is black or brown ppt
R = Pb304 T = Pbo2 , it will oxidise to puruple coloured solutio
due to the presence of HMN04 which is purple is colour.

19
Q

white ppt of ZnS is dissovled in hcl
I ) it forms which compounds D
ii) when we add which Y drop by drop, the white ppt reappears.
iii) this white ppt is solule in excess amount of Y to form compound T
iiv ) on passing which gas , white ppt of Zns reappers from this T solution.
V ) When D compound is reacted with O , in the presence of acetic acid, it forms another white ppt , what are all these?

A

D = ZnCl2
ii) Naoh
this time the white ppt that reappers is
Zn(Oh)2
this white ppt on excess amount of Naoh, to form Na2Zno2 ( sodium zincate)
on passing H2s gas
O = K4[Fe(CN)6] in presence of ACETIC ACID forms
Zn(fe(CN)6)
and when acetic acid is excess, then it forms
Zn3K2[fe(CN)6] 2 ( the 2 is not charge but taken twice]

19
Q

when we take white ppt of Baco3 , and add acetic acid, it gives which compound and which gas ,
i)
when we add R to the solution it forms a yellow ppt , which is ?

A

the compound is
Ch3Coo)2Ba and Co2 gas
i) R - K2cro4 , it forms yellow ppt which is
Bacr04 + Ch3cooK

20
Q

take white ppt of SrCo3 and add which acid, which forms which compound and which gas
i) add F to the solution of the above compound to form another white ppt which conforms the presence of Sr

A

acetic acid.
it forms =
Ch3coo)2 Sr and Co2 gas .
when we add NH4)2So4 to the above compound we get
SrSo4 which is another white ppt

20
Q

take cac03 which is white ppt and add acetic acid, it forms which compound and which gas .
ii) add T to this solution to form another white ppt , which conforms Ca+

A

Ch3Coo)Ca and it forms CO2 gas
T (NH4)2C2o4 which is ammonium oxalate
the last white ppt is CaC2O4
calcium oxalate .

21
Q

for group VI
- take filtrate of Group V , and then add
what compound to move Ba sr ca
this solution is concetrated and furthur which compound is added to make it alkaline?
addition of X forms a white ppt ?
what is the white ppt ?

A

add Nh4)2(C204) ammonium oxalate to remove impurities
NH4oh to make it more alkaline
X = Na2Hp04 to form white ppt
white ppt
Mg(Nh4)Po4
which is white ppt

21
Q

take salt and heat with Naoh , to form ammonia .
i) if hcl dipped rod is brought in contact what is result , which conforms the presence of which ion.
ii) to the aq soln of which salt, which reagent is added to form brown coloured ppt , which is called what .

A

i) if hcl dipped rod …… etc etc ,
if reacts with Nh3 to form Nh4Cl which gives white fumes.
which confims presence of NH4+ ion , group 0
ii) to the aq soln of Nh4cl salt,
NESSLERS REAGENT WHICH =
(K2HgI4)
it forms brown coloured ppt of
iodide of Millions base .
REACTION
Nesslers reagent + ammonium clhroide + KOH =
O
/ \
Hg Hg ]+ I- + 7KI
\ /
Nh2

2 moles of nesslers reagent form 7 moles of KI

Qualitative analysis (3 decks)

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