Basic radiclas Flashcards by Pranav Narayandatta

group 1 ? and group reagent
Do they show any reaction with water

aag, prabhu honge
Ag+ , Pb+, {(Hg)2 2+}
Dil Hcl
reacts to form agcl , pbcl2, hg2cl2
all these are white salts.
No reaction with cold water, but PbCl2 dissolves in hot water!

How well did you know this?

Not at all

Perfectly

Group 2 radicals?
group reagent ?

Cd sun prabhu hoge bimaar , cuch aisa sunao 4 baar.
Cd, Sn 2+ , Pb 2+ , Hg2+ , Bi3+ , Cu2+ , As 3+.
Sn4 + .
and finally Sb 3+

Group reagent is H2S in dil HCl

How well did you know this?

Not at all

Perfectly

Which of the group 2 radicals are completely soluble in Yellow ammonium sulphate

As 3+,
Sn 2+
Sn4+

How well did you know this?

Not at all

Perfectly

what are the colours of the group 2 radicals in learnt order ?
colour of Sb2S3

Colour of Sb thing is orange
in learnt order
Cd sun prabhu hoge binmaar, such aisa sunao chaar baar
the colours are Yellow, brown , black , black , black , black , yellow yellow.

How well did you know this?

Not at all

Perfectly

what are the black ppts which do not dissolve in any acid but only in aqua regia

Hgs

How well did you know this?

Not at all

Perfectly

Group 3 radicals ( hint all have +3 state )
what is the group reagent

Al, Fe Cr
Nh4oh in presence of Nh4cl

How well did you know this?

Not at all

Perfectly

what are the colours of the group three radicals

all of them form hydroxides .
Fe(oh)3 - reddish brown
Al(oh)3 - white
Cr(oh)3 - green .

How well did you know this?

Not at all

Perfectly

What are the group of 4 radicals
what is the group reagent

Zn dagi , Mn ein , Co i , N{h}i
the reagent is H2S in the presence of Nh4Oh

How well did you know this?

Not at all

Perfectly

what the colours of group 4

Zns Mns Cos Nis
Gry white , Buff, black black

How well did you know this?

Not at all

Perfectly

what are the group 5 radicals
what are the reagents of group 5

S{i}r Ca Ba{g}
(Nh4)2C03 in presence of Nh4oh

How well did you know this?

Not at all

Perfectly

what is 0 grp

Nh4+
group reagent is Naoh
forms { Nh3 } gas

How well did you know this?

Not at all

Perfectly

what are the colours of group 5 radicals

SrCo3 - white
CaCo3 - white
Baco3 - white

How well did you know this?

Not at all

Perfectly

which ions give white pppt turning grey on addtion of X
I) write white compounds
ii) what is grey compond
iii) Metal Y when added to the chloride of this ion gives a moisture absorber Z
the metal ( which acts like what on the metal turnings)
iv) when the chloride of this ion is reacted with KI , it forms which coloured ppt .
v) on excess it forms what soluble compounds.

the ion is Hg2+
X= sncl2
i ) white - Hg2cl2
II) Hg
iii) Cu + Hgcl2 = Cucl2 (Z) + Hg ( acts as shiny deposit on copper turnings)
iv) Hgcl2 + KI = HgI2 ( orange colour )
v) excess
K2HgI4 which is soluble

How well did you know this?

Not at all

Perfectly

what is group 6

Mg+2
group reagent - Na2Hpo4
forms - MgNh4po4
white colour

How well did you know this?

Not at all

Perfectly

Group2A
here ppt is heated with dil X
all sulphides of 2a except H are converted to nitrates which are soluble in ????
Group 2B
the sulphides of this grp , are first oxidised to higher suphides which then form which compounds . are they soluble?

X = hno3
H = HgS
soluble in water

grp 2b
they form thio compounds which are then soluble

How well did you know this?

Not at all

Perfectly

How well did you know this?

Not at all

Perfectly

solution of Pbcl2 and X gives yellow ppt
i) this ppt is insoluble in Y and solble in Z
i a ) write reaction of ppt with Z
ii) Pbcl2 forms another yellow ppt with C
iii) Pbcl2 with dil h2s04 , gives white ppt D , where D is soluble in N

X is k2cr04
forms ppt Pbcro4 which is yellow
+ 2 kcl .
Y - acetic acid
Z naoh
Pbcro4 + Naoh = Na2pbo2 + na2cro4
C - Iodide solution
Pbcl2 + Ki = PbI2 + Kcl ( PBI2 is yellow )
D - Pbso4
N - Ammonium acetate.
reaction with ammonium acetate forms
(Ch3coo)2Pb

Agcl dissolves in Y to form Z ( chloride )
i) when dilute H is added to above Z , it forms white ppt A plus some nitrate
ii) When KI added to Z , which colour ppt is obtained along with gas F
iii) reaction of K2cr04 with Z gives which coloured ppt
iv)Z + na2c03 = B ( ppt )
v) this ppt ( B ) when heated gives a compound T with release of Co2
Vi) Z + KCN = white ppt U. When excess of KCN is used, a soluble substance J is formed
Name all

Y = Nh4oh
Z= [Ag(Nh3)2Cl] = diamminesilver(1) chloride
H = Hno3
A = Agcl + Nh4no3
reaction with KI = AgI ( yellow ppt ) +
gases are KCL + NH3

reaction with K2cr04 **gives brick red ppt **
= Agcro4 + same gases as above.
B = Ag2co3
T = Ag2o ( colour = brown black) + CO2
U = AgCN —– excess ——- [Ag(CN)2] which is soluble

ion X’s ppt dissolves in dil HCL and addition of water gives cloudy white ppt ?
X+ KI = which coloured ppt
ii) X + Y + NAoh = C + Black ppt ( V) + G ( metal ion )

X= Bi+3
X + HCL = BICL3
This BiCL3 + water = BIoCl
ii ) BiI3 = which is black ppt
iii) Y = Na2sno2
C= Na2Sno3
V= Bi
Na+ = G

antimony ion Sb3+ in the form of their chlorides on additions of water gives what ppt

Sbcl3+ H20 = Sb0CL ( white ppt ) + 2HCl

which substance H used as some electrode when treated with X turns black ?
i) this black residue dissolves in A to form C
ii) This H forms which colour ppt with stannous chloride with gradually turns which colour
iii) H + KI = V + 2KCL
what is the colour of V

H = Hg2Cl2
X = NH4poh
the black compound is Hg+ Hg(NH2)CL
A = aqua regia
C = Hgcl2
reaction with stannous chloride
to form Hg2Cl2 which is H again ( white ppt)
later , it forms 2Hg which is grey ppt
V = Hg2I2 which is green in colour .

Which ion gives yellow ppt with H2S
ii) this yellow ppt X +8 HNo3 ( hot and dilute) = Y + gas + S ( sulphur )
iii) Y + NH4oh = COmplex D which is colourless
iv ) ion + CN- = white ppt W
v) ion + K4Fe(cn)6 = bluish white ppt G +

Cd2+
X = CdS
Y= Cd(no3)2 + gas ( NO )
D= Cd(NH3)42 colourless
W = Cd(CN)2
G = Cd2[ Fe(CN)6]

which ions in the form of Sncl2 give white ppt with Hgcl2 and turn which colour on standing , give equations

SN2+ and Sn4+
White ppt = Hg2Cl2
it turns black on standing = Hg
( repeated equations )

ions X gives deep blue with excess of Y i) X gives chocolate brown ppt with Z ii) IOn X with S gives black ppt iii) ion + OH - gives which colour ppt iv ) ion + which other ion gives a brown product v) Ion + V gives yellow ppt ( unstable ) which further dissociates into D and CN vi) D + KCN ( excess ) gives B

X = Cu2+ Y = Nh4oh the deep blue comp'd is [Cu(NH3)4] 2+ Z = K4[Fe(CN)6] brown ppt is = [Cu2(fe(CN)6)} S= SCN- black ppt = Cu(SCN)2 with OH- gives Cu(OH)2 ( blue ppt ) Cu2+ + I- = {Cu2I2+ I3-} this is brown V = CN- yellow ppt Cu(CN)2 D = CUCN B = K3[CU(CN)4)]

Which ion gives yellow ppt with ammonium molybdate and Hno3

As+3 + HN03 = As+5 ( H3AsO4)

What are group 3 catiosn what is group reagnet?

since grp 3 , they show +3 charge Al Fe Cr grp reagent Nh4oh , Nh4cl Fe(oh)3 reddish brown CrOh3 green ppt Aloh)3 white ppt

when a brownish ppt of Fe is added to hcl and is divided into three parts : I ) part 1 is added to X to form a blue colour solution Y II) part two is added to S to form a red colour solution Z iii) part three is added to K3feCN6 to forma another brown coloured ppt B

the initial brown ppt is Feoh)3 when reacts with Hcl forms Fecl3 I) X = K4( fe(CN)6)] Y = prussian blue = Fe4(iii)[Fe(ii)(CN)6]3 ii) S = KCNS Z = Fe(CNS)3 iii) B = Fe(iii)[Fe(ii)CN)6]

when a white ppt of Al is dissolved in dil hcl followed by naoh , it forms a ppt of the same compound which dissolves in excess of what to form what ? i) When the last compound is added to C , the white ppt reappears. conforming which ions presence ?

white ppt - Al(OH)3 dissolves in excess of = NaOh to form NaAlo2 NaAlO2 + C ( NH4Cl) it conforms Al 3+ on

Green ppt of X is insoluble in NaOH but addition of What water forms a yellow coloured solution of G write reaction II) when C is added to G , along with Y , another yellow ppt of P conforms which ion presence .

X = Cr(OH)3 Br+H20 ( br2 water ) G = Na2Cr04 C = Acetic acid ( Ch3cooh) Y = CH3cooh)2Pb ( lead acetate) P = Pb(Cro4) it conforms Cr3+ ion

in group 3 conformations, as the reagent , which why is HNo3 added ii) and why is the amont of Hno3 small

it will convert Fe2+ to fe3+ ii) amt is small becuase otherwise , it will convert Mn2+ to Mn3+

when we wash the precipitate of group four , and then dissovle i naqua regia, ii) extrract the residue with water THese sulphides, MS ( m= ni or CO ) when reacted with Hcl and nacscent O give MCl2 i) if it is D , then it will react with F in the presence of H to give red coloured ppt ( cherry red ) which conforms ii) I mole of D reacts with how many moles of F to give the product with how many intramolecular H bonds? iii) D + bromine water in the presence of J gives black residue of T along with the formation of what gas Iv ) D + U gives green ppt O and when U is in excess forms R which is soluble.

D= Nicl2 F = Dimethlyglyoxime ( DMG) H= NH4Oh red ppt = two intramolecular H bonding, 2 ligands of Dmg attached to NI DMG = Ch3-C=NOH | Ch3-C=NOh 1 mole of Ni reacts with 2 moles of Dmg iii) J = Nahco3 T = Ni203 along with formation of Co2 iv) U = KCN gives green ppt of Ni(Cn)2 ( green ) on exces of KCN forms a soluble complx. = K2[Ni(CN)4]

if in group four procedure with Hcl and and washing with water,etc Cocl2 is formed, then it reacts with crystals G in presence of which organic compound to give which colored etheral layer? ii) Upon addition of bromine water to COcl2 in the presence of Y , it gives which colour solution of conformation. iii) upon reaction of Cocl2 with KCn , it gives compnd R which is reddish brown in colour, and then due ot excess KCN, it gives a compound which's is colour is what?

G= Nh4CNS ether blue coloured etheral layer = (NH4)2[Co(CSN)4] ( BLUe ) Y = Nahco3 bromine water to cocl2 in presece of this gives green colour solution of Na3[Co(iii)(Co3)3] ( green ) upon reaction with KCN , Co(CN)2 which is reddish brown in colour Excess of KCN gives k4[Co(CN)6] which is yellowish brown in colour

When MNS of group4 dissolves' in HCl to form MCl2 i) Naoh converts this compound into Y and to this Y add bromine water which forms oxidatiion product of this which is U ( which colour is this U ) ii) to this pptated U , add conc hno3 and R and T and it will oxidise to which coloured solution which conforms Mn2+ ion

Y = Mn(Oh) 2 U = MnO2 which is black or brown ppt R = Pb304 T = Pbo2 , it will oxidise to puruple coloured solutio due to the presence of HMN04 which is purple is colour.

white ppt of ZnS is dissovled in hcl I ) it forms which compounds D ii) when we add which Y drop by drop, the white ppt reappears. iii) this white ppt is solule in excess amount of Y to form compound T iiv ) on passing which gas , white ppt of Zns reappers from this T solution. V ) When D compound is reacted with O , in the presence of acetic acid, it forms another white ppt , what are all these?

D = ZnCl2 ii) Naoh this time the white ppt that reappers is Zn(Oh)2 this white ppt on excess amount of Naoh, to form Na2Zno2 ( sodium zincate) on passing H2s gas O = K4[Fe(CN)6] in presence of ACETIC ACID forms Zn(fe(CN)6) and when acetic acid is excess, then it forms Zn3K2[fe(CN)6] 2 ( the 2 is not charge but taken twice]

when we take white ppt of Baco3 , and add acetic acid, it gives which compound and which gas , i) when we add R to the solution it forms a yellow ppt , which is ?

the compound is Ch3Coo)2Ba and Co2 gas i) R - K2cro4 , it forms yellow ppt which is Bacr04 + Ch3cooK

take white ppt of SrCo3 and add which acid, which forms which compound and which gas i) add F to the solution of the above compound to form another white ppt which conforms the presence of Sr

acetic acid. it forms = Ch3coo)2 Sr and Co2 gas . when we add NH4)2So4 to the above compound we get SrSo4 which is another white ppt

take cac03 which is white ppt and add acetic acid, it forms which compound and which gas . ii) add T to this solution to form another white ppt , which conforms Ca+

Ch3Coo)Ca and it forms CO2 gas T (NH4)2C2o4 which is ammonium oxalate the last white ppt is CaC2O4 calcium oxalate .

for group VI - take filtrate of Group V , and then add what compound to move Ba sr ca this solution is concetrated and furthur which compound is added to make it alkaline? addition of X forms a white ppt ? what is the white ppt ?

add Nh4)2(C204) ammonium oxalate to remove impurities NH4oh to make it more alkaline X = Na2Hp04 to form white ppt white ppt Mg(Nh4)Po4 which is white ppt

take salt and heat with Naoh , to form ammonia . i) if hcl dipped rod is brought in contact what is result , which conforms the presence of which ion. ii) to the aq soln of which salt, which reagent is added to form brown coloured ppt , which is called what .

i) if hcl dipped rod ...... etc etc , if reacts with Nh3 to form Nh4Cl which gives white fumes. which confims presence of NH4+ ion , group 0 ii) to the aq soln of Nh4cl salt, NESSLERS REAGENT WHICH = (K2HgI4) it forms brown coloured ppt of iodide of Millions base . REACTION Nesslers reagent + ammonium clhroide + KOH = O / \ Hg Hg ]+ I- + 7KI \ / Nh2 2 moles of nesslers reagent form 7 moles of KI