Basic concepts Flashcards

1
Q

Empirical formula

A

Simplest whole number ratio of each element present in a compound

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2
Q

Molecular formula

A

Actual number of atoms of each element in a molecule

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3
Q

General formula

A

Simplest algebraic formula of a member of a homologous series i.e. for an alkane: C(n)H(2n)

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4
Q

Structural formula

A

The minimal detail that shows the arrangement of atoms in a molecule e.g. for butane CH(3)(CH(2)2)CH(3)

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5
Q

Displayed formula

A

The relative positioning of atoms and the bonds between them (with all the bond sticks)

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6
Q

Skeletal formula

A

The simplified organic formula, shown by removing hydrogen atoms from alkyl chains, leaving just a carbon skeleton and associated functional groups

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7
Q

Homologous series

A

A series of organic compounds having the same functional group but with each successive member differing by a CH2 group

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8
Q

Functional group

A

A group of atoms responsible for the characteristic reactions of a compound

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9
Q

First 10 alkanes

A

Methane, Ethane, Propane, Butane, Pentane, Hexane, Heptane, Octane, Nonane, Decane

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10
Q

Structural isomers

A

Compounds with the same molecular formula but different structural formula

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11
Q

Stereoisomers

A

Compounds with the same structural formula but with a different arrangement of atoms in space

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12
Q

E/Z isomerism

A

An example of stereoisomerism. Conditions: C=C double bond (restricted rotation) and each carbon atom in the C=C double bond to have 2 different groups attached. E is when the groups are apart; Z is when the groups are together

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13
Q

Cis-trans isomerism

A

A special case of E/Z isomerism in which 2 of the substituent groups are the same

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14
Q

Homolytic fission

A

The breaking of a covalent bond with one of the bonded electrons going to each atom, forming two radicals

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15
Q

Heterolytic fission

A

The breaking of a covalent bond with both of the bonded electrons going to one of the atoms forming a cation (+) and an anion (-)

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16
Q

Curly arrow

A

The movement of an electron pair, showing either breaking or formation of a covalent bond

17
Q

Atom economy=

A

(molecular mass of desired products/sum of molecular mass of all products)*100%

18
Q

Percentage yield=

A

(actual amount in moles of product/theoretical amount in moles of product)*100%

19
Q

Addition reactions and substitution reactions atom economy

A

Addition reactions have 100% atom economy (2 reactants -> 1 product); substitution reactions are less efficient (2 reactants -> 2 products)

20
Q

Benefits of a high atom economy

A

Fewer waste materials are produced