B Part 1

Question 1

If palmitic acid(C16:0) has a melting point of 63 degrees Celsius, what would you expect the melting point of palmitoleic acid(C16:1 omega -7-cis) to be?

Answer 1

Considerably lower than 63 degrees Celsius

Question 2

Linoleum acid( C16:2 omega-6-cis omega-9-cis) has a pKa of 9.25. You make a 7 mM solution in a pH 11.50 buffer: what will be present?

Answer 2

5 mM linoleate ions

Question 3

Which types of bond is the branching attachment in floridean starch?

Answer 3

(6- ->1) glycosidic bond

Question 4

Spheroprotein found in the cytoplasm of a cell…

Answer 4

The amino acyl residues clustering on the inside are hydrophobic and those on the outside are hydrophilic

Question 5

You have 1.1 mL of a 28 mM solution of summers reagent. What amount do you have?

Answer 5

Amount

31 μmol (amount in moles= concentration in moles per litre x volume in litres)

Concentration = 28 mM = 28 × 10⁻³ mol/L
Volume = 1.1 mL = 1.1 × 10⁻³ L
Now, calculate the amount:

28
×
1
0
−
3
 
mol/L
×
1.1
×
1
0
−
3
 
L
Amount=28×10
−3
mol/L×1.1×10
−3
L
Amount
=
30.8
×
1
0
−
6
 
mol
=
31
 
μ
mol
Amount=30.8×10
−6
mol=31μmol

Question 6

True statements about a phospholipid…

Answer 6

1. Th phosphate group in the ‘heat’ makes it charged and hydrophilic versus the ‘tail’
2. They are found primarily in membranes in the eukarya , bacteria and about half of the known archaea
3. The ‘head’ is com[osed of glycerol with a phosphate group attached and usually another group of some kind
4. The ‘tails’ are attached to the ‘head’ by ester linkages

Question 7

What is the complementary strand for this piece of genomic DNA from a member of the metazoa?
5’-GCCCAGATGGAACCGGA-3’

Answer 7

3’-CGGGTCTACCTTGGCCT-5’